Square Roots by Hand Square Roots by Hand Instructions: Example: 1 Count the number of digits your number has that are on the left side of the decimal point....
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adrish.mukherjee@...
adrishm
May 3, 2004 5:25 am
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udai_khatri
May 4, 2004 4:41 am
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alokmba
May 4, 2004 5:36 am
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anjli_bhargav
May 5, 2004 4:29 am
Hey Alok, You have already subscribed...... Anjli....
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adrish.mukherjee@...
adrishm
May 5, 2004 5:02 am
hello, the remainder rotates in intervals of 4 2 1 is correct but the fact that 11^11^11 = 11^ 121 is wrong as 11^ 11 is not 121 that is 11^ 2 = 121 one way...
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adrish.mukherjee@...
adrishm
May 5, 2004 5:20 am
hello, there was a general method of getting the powers of 11 i have forgotten that - can you please tell me about that like 11^2 = 121 11^3 = 1331 11^4 =...
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adrish.mukherjee@...
adrishm
May 5, 2004 6:00 am
hello all, about getting the remainder i am getting the answer as 1 when 11^11^11 is divided by 7 do you get a different answer. Debarya_Sarkar wrote: What is...
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roxvary
May 5, 2004 6:29 am
Hello Adrish, The pattern about which you are thinking is actually goes like below 1^2 = 1 111^2 = 12321 1111^2 = 1234321 11111^2 = 123454321 111111^2 =...
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roxvary
May 5, 2004 6:35 am
Hi, To find out if a number is divisible by seven, take the last digit, double it, and subtract it from the rest of the number. Example: If you had 203, you...
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Dandwekar, Mihir (Cog...
mihir_vjti
May 5, 2004 6:44 am
1 shud be the answer Thanks & regards, MD. Mobile - 9822329922. "Risk comes from not knowing what you're doing." -Warren Buffett ... From:...
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Navalgund, Raghavendra
raghavendra.navalgund...
May 5, 2004 6:51 am
Hi, This is a good way to find out about the divisibility. Thanks for sharing. However it becomes cumbersome if problems with 11^11 involves divisibility by 7....
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priyankaat2003
May 5, 2004 7:11 am
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Abhinav_Singh
abhinav_si
May 5, 2004 8:10 am
11^11^11=(7+4) ^11^11 Now here we have to consider only 4 ^11^11 as after binomial expansion all the other terms will be perfectly divisible by 7. => 4^11^11=...
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Bhagwati Singh
bhagwati.singh@...
May 5, 2004 11:17 am
great Mr. Abhinav really good ... From: Abhinav_Singh [mailto:abhinav_singh@...] Sent: Wednesday, May 05, 2004 12:58 PM To:...
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sabyasachi.sen@...
iamsabyasachi
May 5, 2004 11:17 am
Abhinav has really given a wonderful solution to this quant teaser.... but i think 4^11^11=(4^3)^11^11 would have been a better way of solving this..........
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aravind kpv
aravindkpv
May 6, 2004 4:53 am
What is the remainder when 11^11^11 is divided by 7? 11/7 GIVES 4 REMANIDER =>4^4^4/7 =>(256)^4/7 =>1^4/7 =>REMANIDER =1 P.S: I BELIEVE THAT THIS ANS IS...
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anjli bhargav
anjli_bhargav
May 6, 2004 7:02 am
Hi I haven't understand one thing. According to you 4^11^11= (64)^(11^11-3) but it should be 4^11^11 = (64)^(11-3)^11 ... __________________________________ Do...
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Abhinav_Singh
abhinav_si
May 6, 2004 7:37 am
Lets assume 11^11= Some very large number X => 4^(11^11) =4^X =64^(X-3) Is it clear now... ... From: anjli bhargav [mailto:anjli_bhargav@...] Sent:...
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anjli_bhargav
May 6, 2004 8:11 am
No!! it is not clear this time also.... Let us take an example 2^4^3 = ? (2x2x2x2)^3 = ? (16)^3 = 4096 according to you 2^4^3 = (4)^(4^3-2) = 4^4 = 256 again...
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sabyasachi.sen@...
iamsabyasachi
May 6, 2004 8:21 am
I don't agree with Abhinav this time.... U can do that only when x tends to infinity.. otherwise u can't... I mean 11^11 is still a finite value and u just...
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Atal
atal_bihari_b
May 6, 2004 8:29 am
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anjli_bhargav
May 6, 2004 8:42 am
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priyankaat2003
May 6, 2004 8:51 am
Hey Anjli, You are telling right. Good consideration by you. Now the problem occures again (11^11^11)/7 then remainder =? ... system...
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sabyasachi.sen@...
iamsabyasachi
May 6, 2004 10:44 am
Anjli, I think u are confusing the powers notation.... let me clarify it.... As per u 2^4^3=(2 x 2 x 2 x 2)^3.. which i am afraid is wrong..... Perhaps it is...
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Abhinav_Singh
abhinav_si
May 6, 2004 10:44 am
11^11 will always be a number which we need not calculate. I have denoted it by X. It dosent tends to infinity and Why can't you deduct 3 from it. Second thing...
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Abhinav_Singh
abhinav_si
May 6, 2004 10:44 am
11^11-3 dosent mean 11^8 it means (11^11)-3 it means 11 raised to pwer 11 minus 3.for example if it was 11^2-3 it would have meant 121-3 =118 and not 11 raise...
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jaspreet.singh@...
jaspreet008
May 6, 2004 11:08 am
hey abhinav, i believe there was a problem with your earliar premise, u said something like 4^(11^11) Now to make this 4 as 64, what u need to do is take the...
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sabyasachi.sen@...
iamsabyasachi
May 6, 2004 11:20 am
Sorry Abhinav.. but i am not satisfied with ur clarification...... ... From: Abhinav_Singh [mailto:abhinav_singh@...] Sent: Thu 5/6/2004 2:11 PM To:...
