... Jim, I admit to being confused still. I must not understand the Pods creation well enough. I certainly don't flow the "lensing" information. How a Pods...
rybo, (see below) ... Sorry for adding to your confusion. The lens shape is the shape formed when the two circles overlap. ... It's important to forget the...
Maybe you are talking about an ARC length of 4 inches, so the CHORD would be less. So, for a hexagon, the chord would be the same as the radius of that arc....
Alan, Thanks for your input! I'm not sure if the arc formed by the pod edge is considered an ARC length. It may be I dunno. There are two types of arcs on...
... That I understand as the 2D diagram of the two hexagons make two arcs, of the pod, quite obvious. ... The hexagon is still a hexagon. The edge of hexagon...
rybo, (below) ... The edge of the hexagon is not carried intact to the pod. It would be better to call the axial length of the pod C and D since that length...
http://www.maths.gla.ac.uk/~wws/cabripages/inversive/infinity.html Jim, check this one out. It is interactive now I can get and idea of how the Pods axial...
Jim, the edge arcs <http://mathworld.wolfram.com/Arc.html> bulge out twice as far from the chord <http://mathworld.wolfram.com/Chord.html> as the face arcs...
Alan, If I keep in mind the physical pod, which is what I am trying to duplicate, then both arcs are present. If the method used to find the chord of the pod...
David, Thanks for your reply! I have some questions and comments: 1- Is your pod edge length the length of the pod edge as a straight segment, and not the...
... Yes, I shouldn't mix edge bulge with face bulge! ... Yes, I did think that you meant along the edge. But I arrived at the figure based on the circle arcs,...
Adrian, Thanks for your efforts here. Yes, I agree with you that your results appear to be on the long side. I made a CAD drawing that forms the pod with...
Alan, ... It's interesting that the pod has two different arc behaviors. Adrian is suggesting that calculus may be the way to go. This seems to be an open...
David, Thanks for your reply and added references. If your answer to the chord length of the pod is 4.1887902, then this is too long. When the pod is formed,...
... Hmmm, well Jim, after reviewing this one I still don't understand how the long axial length of the Pod can be anything other than the length of the edge of...
rybo, This pod question is certainly a tricky one to wrap a brain around. As I mentioned earlier, its important to not jump ahead and go for the overlay on...
David, Thanks again for your input. 3.8197186 is too short. Please take another look at how the leaf shape formed by the overlapping circles form the three...
Are you sure that you are using a sixth of a circle? I'm basing everything on the ratio of PI/3. That's a sixth of a circle to a hexagon's side. Make sure that...
Adrian, My check-in on synergeo has been pretty good these last few days, but I did miss this one. Your chord length of : 3.9331744 looks quite good! I am...
David, See below... REF: Pod chord: http://www.blackcatphotoproducts.com/L11124.jpg ... I should have called the line in the pod C and D since it is not the ...
Alan, RE: Pod chord: http://www.blackcatphotoproducts.com/L11124.jpg ... Yes. ... The circles are broken into segments by the hexagons. ... The calipers are...
Hi Spencer, See comments below.... ... Yes ... Right ... Yes ... Dunno. I'm not sure what kind of arc we have here. ... Dunno ... Join the crowd! This...
Alan, The pathways that look like great circles on the Pandora are not circles or elipses, they meander. Please note that the only influence the pod has on...
... circles ... may ... that ... Yes, I see, the Pandora is that mid-polyhedron inside the Curved Vector Equilibrium. The pods cross the Pandora at the...
Alan, I very much appreciate you taking an interest in the CVM. You are bringing observations that are very helpful to me. See below...... ... Yes. ... Yes ...
Jim, You have the number 1.071797 and the number 3.9331744 Notice that 3.9331744 minus 3 is .9331744 notice too that 1 / 1.071797 is .9330125 This ia too...
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