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Message #5934 of 18442 |

ABC is a right triangle with mB=90 . D is a point on [AB] and E is a
point on [BC] .If m(BAE)=m(EAC) , m(BCD)=m(DCA) , |AE|=3 cm , |CD|=4
cm then find |AC|

Mon Oct 14, 2002 10:26 pm

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Message #5934 of 18442 |

Expand Messages	Author	Sort by Date
ABC is a right triangle with mB=90 . D is a point on [AB] and E is a point on [BC] .If m(BAE)=m(EAC) , m(BCD)=m(DCA) , \|AE\|=3 cm , \|CD\|=4 cm then find \|AC\|...	yagcimustafa	Oct 14, 2002 10:26 pm
... a ... Putting x=AC^2, I get x^3-25.x^2+108.x-450 (+/-)6(x^2-25.x+36)root(2) = 0 I presume that this can be solved using trigonometry but I didn't find. ...	jpehrmfr	Oct 14, 2002 11:45 pm
... is ... What was your method, out of interest? Nick...	Nick_Hobson	Oct 24, 2002 6:23 am
Dear Nick and other Hyacinthists ... u = angle(BAE); b = AC Clearly AE = b cos(u)/cos(u/2) = 3; CD = b sin(u)/cos(45-u/2) = 4 Hence, if p = cos(u/2); q =...	jpehrmfr	Oct 24, 2002 9:25 am
Dear Hyacinthists, as automn 2002 seems to be the moment for synthetic proofs, may I suggest you the following - related with an upcoming paper in FG - : ...	jpehrmfr	Oct 24, 2002 9:18 pm

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