Skip to search.

Breaking News Visit Yahoo! News for the latest.

×Close this window

Hyacinthos · We discuss themes on Triangle Geometry

The Yahoo! Groups Product Blog

Check it out!

Group Information

  • Members: 3
  • Category: Geometry
  • Founded: Dec 22, 1999
  • Language: English
? Already a member? Sign in to Yahoo!

Yahoo! Groups Tips

Did you know...
Real people. Real stories. See how Yahoo! Groups impacts members worldwide.

Messages

Advanced
Messages Help
Messages 11348 - 11382 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
Messages: Simplify | Expand Author Sort by Date ^
11348 Francois Rideau
francoisrideau Send Email
Jul 1, 2005
7:00 am
I correct a little typo in my last answer. With your notation: OP:PH = k:1-k you mean: OP = k OH so P = G for k=1:3 (and not for k=-2!) Friendly François...
11349 Etienne Rousee
etiennerousee Send Email
Jul 1, 2005
8:16 am
... Yes, it's an error of mine. I have forgotten to change the subject. Etienne [Non-text portions of this message have been removed]...
11350 jpehrmfr Send Email Jul 1, 2005
5:49 pm
Dear Jeff ... one ... in ... whose ... If T(P) is the circlecevian triangle of P, there exists one and only one point Q such as T(Q) is inscribed in T(P) :...
11351 Bernard Gibert
bernardgibert Send Email
Jul 1, 2005
6:18 pm
Dear Jeff and Jean-Pierre, ... I had found the same results and a strong connection with circular isogonal pK. All these points P, P*, Q, Q*, the vertices of...
11352 Antreas P. Hatzipolakis
xpolakis Send Email
Jul 1, 2005
7:31 pm
... --...
11353 Jeff Brooks
jbrooks_tulsa Send Email
Jul 2, 2005
3:04 pm
Dear Jean-Pierre and Bernard, Thank you very much for your responses. I did not expect the inverse problem to be quite so involved. Bernard, your analysis...
11354 jpehrmfr Send Email Jul 3, 2005
7:21 am
Dear Jeff and Bernard, may be this is more clear. For a given point, let M* = isogonal conjugate of M T(M) = circlecevian triangle of M with vertices...
11355 Bernard Gibert
bernardgibert Send Email
Jul 3, 2005
7:29 am
Dear Jean-Pierre and Jeff, ... How to be sure they are ruler and compass constructible ? In this case, it would be possible to construct the common points of a...
11356 Bernard Gibert
bernardgibert Send Email
Jul 3, 2005
7:32 am
Dear Jean-Pierre, ... these are the points such that M lies on the infinite branch of the isogonal circular pK with pivot the infinite point of the line MM*. ...
11360 jpehrmfr Send Email Jul 3, 2005
8:25 am
Dear Bernard [JPE] ... [BG] ... Yes but, except the limit cases, we can split the plane in two parts : if M lies in the first part, there are 4 points P; if M...
11361 jpehrmfr Send Email Jul 3, 2005
10:09 am
Dear Bernard and Jeff ... generally ... ruler ... [BG] ... of ... If I well follow you, the points P such as T(P) circumscribes T(M) are the isogonal...
11362 Bernard Gibert
bernardgibert Send Email
Jul 3, 2005
4:58 pm
Dear Jean-Pierre and Jeff, ... here's a construction of the four points : let Q be a point and A1B1C1 its circle cevian triangle. we seek P whose circle cevian...
11363 jpehrmfr Send Email Jul 3, 2005
5:28 pm
Dear Bernard ... (M) ... the ... simple ... conic ... A1, ... pivot ... B', ... Very good. In fact, it gives (after projectivity) a construction of the common ...
11364 fredlangch Send Email Jul 4, 2005
8:16 am
... Hello! Hence, we can construct the four tangents from a point of a pK. Bye. Fred...
11365 Bernard Gibert
bernardgibert Send Email
Jul 4, 2005
6:24 pm
Dear Jean-Pierre, ... in fact, it is not necessary to have another pair of points on the pK if it is defined by its pivot P and its isoconjugate P*. to...
11366 Nikolaos Dergiades
ndergiades Send Email
Jul 4, 2005
9:23 pm
Dear friends, it is known http://mathworld.wolfram.com/AdamsCircle.html that the parallel lines from the Gergonne point Ge = ( 1/(s-a) , 1/(s-b), 1/(s-c) ) in...
11369 Antreas P. Hatzipolakis
xpolakis Send Email
Jul 4, 2005
9:36 pm
Dear Nikos [ND] ... This should be known by Conway's extraversion BTW, and Conway's Circle is also centered at I and has three brother-circles by extraversion....
11370 Jeff Brooks
jbrooks_tulsa Send Email
Jul 5, 2005
5:46 am
Dear friends, Recent messages (many thanks to Jean-Pierre and Bernard!) on nested circle cevian triangles led me to take a look at the class of circular...
11371 ForumGeom
ForumGeom@... Send Email
Jul 5, 2005
5:14 pm
The following paper has been published in Forum Geometricorum. It can be viewd at http://forumgeom.fau.edu/FG2005volume5/FG200513index.html The editors Forum...
11372 Nikolaos Dergiades
ndergiades Send Email
Jul 5, 2005
7:54 pm
Thanks Antreas. [ND] ... [APH] ... If the point P has barycentrics (x : y : z) and A'B'C' is its cevian triangle then the parallel line from P to B'C' meets...
11373 Francois Rideau
francoisrideau Send Email
Jul 6, 2005
7:38 am
Dear friends Beeing given 3 lines L_{1}, L_{2}, L_{3} in R^3 with equations: x = a_{k} z + b_{k} y = c_{k} z + d_{k} for k= 1, 2, 3 1° Is there a simple way...
11374 Antreas P. Hatzipolakis
xpolakis Send Email
Jul 6, 2005
4:51 pm
If three concurrent chords of a conic are equal, then is the conic a circle (and the chords diameters) ? aph --...
11375 Antreas P. Hatzipolakis
xpolakis Send Email
Jul 6, 2005
5:14 pm
... Well... not. Now, if three concurrent chords of a circle are equal, then the three chords are necessarily diameters. Simple proof? aph...
11376 Li Zhou
lizhoupolk Send Email
Jul 6, 2005
8:44 pm
Dear Friends, The question is about Math. Magazine Problem 1171 (Feb/2005). Suppose the cevians AA', BB', CC' of triangle ABC meet at M. If M is inside ABC and...
11377 Boutte Gilles
g_bouttefr Send Email
Jul 6, 2005
9:18 pm
The chords AA', BB', CC' of the circle (O) are concurrent at M. Let l = AA' = BB' = CC', and p the power of M wrt (O). We have : MA + xMA' = MB + xMB' = MC +...
11378 Francois Rideau
francoisrideau Send Email
Jul 7, 2005
5:02 am
... Gilles's proof is very nice. Here another one, not using directly the ... If l<>R, then r<>0, and we have a nonsense with 3 distinct tangents from M to a...
11379 Nikolaos Dergiades
ndergiades Send Email
Jul 7, 2005
6:16 am
Dear Antreas, we had very nice proofs for the case of circle but before this you wrote ... and maybe somebody is trying to solve this problem. The answer is no...
11380 Francois Rideau
francoisrideau Send Email
Jul 7, 2005
7:39 am
Here what the meaning of a curve? If we begin with a "curve" C and we construct the conchoid C' of C wrt O for a length l, the reunion of C and C' is a new...
11381 Nikolaos Dergiades
ndergiades Send Email
Jul 7, 2005
8:52 am
Dear François, I had in mind the cardioide. For example in polar coordinates (p, w) the cardioide with equation p = 1 + cosw has every chord AA' that passes...
11382 Alexey.A.Zaslavsky
zasl@... Send Email
Jul 7, 2005
12:14 pm
Dear colleagues! There are some interesting properties of two triangle centers. Let P1, P2 are the Brocard points of triangle ABC, C0 is the common point of ...
Messages 11348 - 11382 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
Add to My Yahoo!      XML What's This?

Copyright © 2010 Yahoo! Inc. All rights reserved.
Privacy Policy - Terms of Service - Guidelines NEW - Help