Dear friends: Let X be touch point at BC with the extangent circle to excircles (I_b) and (I_c) of ABC triangle. Y and Z are similarly the touch points on AC...
Dear Juan P is the orthocenter of ABC. ABC and UVW are perspective and orthologic and so one... Friendly François ... [Non-text portions of this message have...
Dear Juan ABC and XYZ have N the Nagel point as perspector . ABC and UVW have H the othocenter of ABC as perspector. So XYZ and UVW are perspective with...
Dear Francois: I am sorry by my statement, clarifying the circle that touches BC at X is a circle that is on the same side that excircles(I_b) and (I_c)....
Dear Francois: I am sorry by my statement, clarifying the circle that touches BC at X is a circle that is on the same side that the excircles (I_b) and (I_c)....
Dear Francois: I posted in the files one figure for the first circle with the touch point X. Thanks Juan Carlos ... UVW are ... excircles ... touch ... ...
Dear all, this is the first time I gather courage to write. Even if I've been working for a long time with synthetic geometry the reason is that I don't work...
you can look at some of the pictures in http://madelapaz.blogspot.com/ ... Do You Yahoo!? La mejor conexión a Internet y 2GB extra a tu correo por $100 al...
The circles I mentioned as locus of symmedian intersecion with Euler line are tangent to the tangential triangle NOT to the original triangle! ... Do You...
Dear Juan, ... There are two extangents circles. A small and a large. If we consider the case of the small circle then after tedious calculations I found that,...
Dear Nik: You wrote: ... Yes, you are right.In this case, I take the small circle. ... If we denote by P and Q the touch points between the excircles (I_c,r_c)...
Dear Juan Carlos, your point X is the intersection of BC with the midcircle of the B- excircle and the C-excircle, lying between B and C For the large circle,...
Dear Juan and Eric, the same construction I had in mind as you and Eric. If M is the intersection of PQ and IbIc and rc<rb then the line PIc meets the circle...
Dear Juan Carlos If Ab and Ac the points where the B and C-excircles touch BC, the circle with diameter AbAc (this circle is centered at the midpoint of BC...
The triangle of centers (LaLbLc) is in perspective with (ABC) in The circumcenter U of (ABC), the axe of the perspective being the Lemoine line of (ABC) which...
Greetings people, and wonderful newsgroup! I've been a bit stumped on a problem of defining the eccentricity and (length value of a, not the equation of the...
My dear Kai Yes, I know your formula on the latus rectum of a parabola. Here in France we call the semi-latus rectum parameter p. For a general non degenerate...
Of course, I must correct a little typo, so the formula for eccentricity is: (1-e^2)/e^4 = {delta}/[(a-b)^2 + 4 h^2] Friendly François [Non-text portions of...
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2006volume6/FG200604index.html The editors Forum...
ForumGeom
ForumGeom@...
Feb 6, 2006 8:31 pm
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Dear Hyacinthians. I have found an interesting result in the configuration of a cyclic quadrilateral. The four Euler lines of the triangles in which divided a...
Dear all, for some reason I have not been receiving your messages after I posted my constructions.... I got into the gruop's messagges to read them. Since I...
Dear Maria Yes, I think you can post your figures within the group but I don't know how to do it! Maybe somebody in the group can explain that to you? I am...
Dear Maria, you wrote ... In Cartesian coordinates the points B(-a, 0), C(a, 0) and the circumcenter Q(0, b) of triangle ABC are fixed points and the point...
The following paper has been published in Forum Geometricorum. It can be viewed at file:///X:/FG2006volume6/FG200605index.html The editors Forum Geometricorum ...
ForumGeom
ForumGeom@...
Feb 13, 2006 3:33 pm
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Apology for an incorrect link in a previous announcement. The following paper has been published in Forum Geometricorum. It can be viewed at ...
ForumGeom
ForumGeom@...
Feb 13, 2006 3:39 pm
12119
Dear Nikos, dear all, First, thank you for your calculation for the hyperbola!!....I'm still trying to work it out this case as the following: As I told you in...
... are ... on ... This ... organized ... one ... that ... Hi Seve I am afraid that there are no strong points on your line. Think of a line L as the tripolar...