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Hyacinthos · We discuss themes on Triangle Geometry

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  • Members: 3
  • Category: Geometry
  • Founded: Dec 22, 1999
  • Language: English
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Messages 14418 - 14447 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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14418 Quang Tuan Bui
bqtuan1962 Send Email
Nov 8, 2006
4:37 am
Dear All My Friends, From incenter I we construct one line perpendicular to sidelines BC. This line cuts AB at Ab, cuts AC at Ac and cuts incircle (other than...
14419 Francois Rideau
francoisrideau Send Email
Nov 8, 2006
5:01 am
Dear friends ... Sorry, the map f is not involutive, ( I was mistaken with another configuration!), but the fixed points of the map f are well the foci of ...
14420 Quang Tuan Bui
bqtuan1962 Send Email
Nov 8, 2006
6:26 pm
Dear All My Friends, By calculations I have found: - Triangle AiBiCi has barycentrics: Ai = (a^2 : sa*sb : sa*sc) Bi = (sb*sa : b^2 : sb*sc) Ci = (sc*sa :...
14421 ?????????
tl_em@... Send Email
Nov 8, 2006
11:42 pm
Dear Tuan, ... This line cuts AB at Ab, cuts AC at Ac and cuts incircle (other than touch point with BC) at Ai. Similarly we construct Bc, Ba, Bi, and Ca, Cb,...
14422 Quang Tuan Bui
bqtuan1962 Send Email
Nov 9, 2006
6:03 pm
Dear All My Friends We can generalize the circumconic (Co) as follow: Suppose I is any point P with barycentrics (p : q : r). Construct A1B1C1 as before. Six...
14423 Emelyanov
tl_em@... Send Email
Nov 9, 2006
10:47 pm
Dear Tuan, I found many interesting facts about the Nagel point. For example: let A'B'C' be the cevian triangle of Nagel point, then 1) we always can constract...
14424 Quang Tuan Bui
bqtuan1962 Send Email
Nov 10, 2006
2:31 am
Dear Lev, Thank you very much for your proof in previous message and interesting results in this message. Also thank you for the information I need which you...
14425 Quang Tuan Bui
bqtuan1962 Send Email
Nov 10, 2006
4:17 am
Dear All My Friends, If we choose P as circumcenter then we have one very simple circumconic: - The barycentrics equation: a^4*y*z + b^4*z*x + c^4*x*y = 0 -...
14426 Quang Tuan Bui
bqtuan1962 Send Email
Nov 10, 2006
6:15 am
Dear All My Friends, The general circumconic (Co) (with any point P) has one interesting feature: Let Q is perspector of (Co), gQ is isogonal conjugate of Q,...
14427 Quang Tuan Bui
bqtuan1962 Send Email
Nov 10, 2006
8:41 am
Dear All My Friends, I am very sorry. The features related with perspector Q, gQ, tgQ, X, X' of one conic and operation barycentric product are true for any...
14428 Francois Rideau
francoisrideau Send Email
Nov 10, 2006
8:51 am
... [Non-text portions of this message have been removed]...
14429 Jeff Brooks
jbrooks_tulsa Send Email
Nov 10, 2006
9:33 am
Hey François, I'll definitely look closer at your description below. How might we relate (if at all possible) these relationships to orthogonal polynomials...
14430 Francois Rideau
francoisrideau Send Email
Nov 10, 2006
10:17 am
Dear Jeff Good to remember me the name of this great russian man. Maybe there is a connection with linkages? Friendly François [Non-text portions of this...
14431 Jeff Brooks
jbrooks_tulsa Send Email
Nov 10, 2006
10:47 am
Well, besides mine, there are only three other references to him in the Group. But, it's possible I did not apply the correct filter. :-) Sincerely, Jeff...
14432 Francois Rideau
francoisrideau Send Email
Nov 10, 2006
10:38 pm
Dear friends Given a triangle ABC, I give you other properties of the configuration of the family of the pedal triangles abc of points M on a line L in...
14433 Francois Rideau
francoisrideau Send Email
Nov 10, 2006
11:04 pm
Dear friends I forgot to tell you something in the last theorem 6 of my previous post: We know that the four lines L1, L2, L3, L4 bound 4 triangles which give...
14434 Francois Rideau
francoisrideau Send Email
Nov 11, 2006
8:03 am
Dear friends ... Sorry, my theorem 3 is wrong. My sight is not so good now and maybe I made a mistake using a Cabri macro. That's why I have had some...
14435 jpehrmfr Send Email Nov 11, 2006
8:47 am
Dear Francois you wrote ... configuration of ... inversive ... the line ... Simson ... a'b'c', ... Here is another one : If the line L intersects BC, CA, AB at...
14436 Francois Rideau
francoisrideau Send Email
Nov 11, 2006
10:10 am
Dear Jean-Pierre Thanks for your drawing. Suddenly, it seems to me that triangles both perspective and directly similar have been already studied in the past...
14437 jpehrmfr Send Email Nov 11, 2006
10:41 am
Dear Francois ... and ... remember it? You are probably right. The only thing that I know is that, when the similitude is not an homothecy, the perspector and...
14438 Quang Tuan Bui
bqtuan1962 Send Email
Nov 11, 2006
3:49 pm
Dear All My Friends, Some properties of this circumconic: 1. P and reflection of P in circumcenter share one common (Co) conic 2. If P on circumcirle then...
14439 Quang Tuan Bui
bqtuan1962 Send Email
Nov 11, 2006
5:23 pm
Dear All My Friends, Center of this locus circumconic passing through X(2966), X(112), X(1576), X(1415) with perspector X(184) has barycentrics: a^4*(a^8 + b^8...
14440 Milorad Stevanovic
yumarince Send Email
Nov 11, 2006
8:53 pm
Dear friends, Let P be a point and A1=PA /\ BC and P1 is harmonic conjugate to P wrt A and A1, and analogously for P2 and P3.Then P1,P2 and P3 are...
14441 Nikolaos Dergiades
ndergiades Send Email
Nov 11, 2006
10:21 pm
Dear Milorad, The triangle P1P2P3 is the anticevian triangle of P = (x : y : z) in barycentrics and the Miquel point of ABC wrt P1P2P3 is the point in...
14442 Francois Rideau
francoisrideau Send Email
Nov 12, 2006
9:53 am
Dear friends I come back again to the Atul-Darij paper http://forumgeom.fau.edu/FG2004volume4/FG200406.pdf ... use the Pappus theorem to prove alignment of...
14443 Quang Tuan Bui
bqtuan1962 Send Email
Nov 12, 2006
11:21 am
Dear All My Friends, In the case P = incenter, three lines AA2, BB2, CC2 are concurrent at X(651). In general these three lines are not concurrent. By some...
14444 Francois Rideau
francoisrideau Send Email
Nov 12, 2006
5:13 pm
Dear friends And it fact it easy to prove equalities of crossratios. I keep notations of my previous post. For example, if A', B', C' , D' are the orthogonal...
14445 Quang Tuan Bui
bqtuan1962 Send Email
Nov 13, 2006
2:47 pm
Dear All My Friends, Given triangle ABC; point P with barycentrics (p:q:r); point U with barycentrics (u:v:w). A perpendicular line from P to BC cuts AB at Ab,...
14446 ForumGeom
ForumGeom@... Send Email
Nov 13, 2006
4:09 pm
The following paper has been published. It can be viewed at http://forumgeom.fau.edu/FG2006volume6/FG200633index.html The editors Forum Geometricorum ...
14447 Quang Tuan Bui
bqtuan1962 Send Email
Nov 14, 2006
8:46 am
Dear All My Friends, Today I search one point in ETC Search Table. Suddenly I see strange search value of X(519). Here it is: 14.03030303030 I try to calculate...
Messages 14418 - 14447 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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