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Hyacinthos · We discuss themes on Triangle Geometry

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  • Members: 3
  • Category: Geometry
  • Founded: Dec 22, 1999
  • Language: English
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Messages 14935 - 14965 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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14935 Quang Tuan Bui
bqtuan1962 Send Email
Mar 2, 2007
4:53 pm
Dear All My Friends, Given triangle ABC with circumcircle (O). There is and exactly one equilateral triangle inscribed in (O) taken A as one vertex. We denote...
14936 michgarl Send Email Mar 2, 2007
5:22 pm
Je reviens sur le sujet traité dans les messages 10135,10136,10146 et 10358. Après avoir pris conaissance des résultats de Darij Grinberg, je me suis...
14937 garciacapitan Send Email Mar 2, 2007
5:38 pm
Dear friends, I would like to have a construction of the point (0:a^2-2(b+c)a+b^2+c^2:-2bc) Thank you....
14938 Paul Yiu
yiuatfauedu Send Email
Mar 2, 2007
8:44 pm
Dear Tuan, How wonderful. I make a quick sketch and see that your P is the isogonal conjugate of the infinite point of the Euler line. Best regards Sincerely ...
14939 Francois Rideau
francoisrideau Send Email
Mar 2, 2007
9:18 pm
Anh Tuan oi I think the point P is known for a long time. It is X(74). It was found by Dobbs more than 100 years ago with just your way! Friendly François ......
14940 Andreas P. Hatzipolakis
xpolakis Send Email
Mar 2, 2007
9:38 pm
Dear Tuan and Paul Since there are no "islands" in the Geometry "sea", I am wondering how can we generalize it. Probably a way is this: Let ABC be a triangle...
14941 pneagoe Send Email Mar 2, 2007
9:52 pm
... one equilateral triangle inscribed in (O) taken A as one vertex. We denote its bottom line wrt A as La, intesection of La with sideline BC as A'. Similarly...
14942 Francois Rideau
francoisrideau Send Email
Mar 3, 2007
12:07 am
Anh Tuan oi As Paul notices, your P is X(74) wrt ABC. To prove the last property of the line A'B'C', I think the best is to use polarity wrt the imaginary...
14943 Steve Sigur
steve_sigur Send Email
Mar 3, 2007
12:20 am
Sorry I got circum and inconics mixed up. Here is the correct message. Bernard wrote this in Hyacinthos a few years ago. ... I was wondering how one shows...
14944 pneagoe Send Email Mar 3, 2007
12:54 am
Dear Andreas, Let ABC be a triangle with circumcircle C(O) and the incircle c(I). Ca is the circle with center A and radius AI. La is the radical axis of the...
14945 Steve Sigur
steve_sigur Send Email
Mar 3, 2007
12:57 am
Bernard wrote this in Hyacinthos a few years ago. ... I was wondering how one shows this. This result combines with one of my own to give this Every...
14946 pneagoe Send Email Mar 3, 2007
1:25 am
Dear Andreas, If the points A', B', C' lies on the line L and the lines AA", BB", CC" are concurrent at P then : 4. the point P lies on the line OI. 5. OI and...
14947 Paul Yiu
yiuatfauedu Send Email
Mar 3, 2007
2:01 am
Dear friends, BQT (14935) Given triangle ABC with circumcircle (O). There is and exactly one equilateral triangle inscribed in (O) taken A as one vertex. We...
14948 Quang Tuan Bui
bqtuan1962 Send Email
Mar 3, 2007
2:28 am
Dear All My Friends, Thank you very much for your references and remarks. I have some results: - L bound with ABC one complete quadrilateral with Miquel point...
14949 jpehrmfr Send Email Mar 3, 2007
7:41 am
Dear Steve ... The axes of the inconic with center M are parallel to the asymptots of the conjugate rectangular hyperbola going through M (ie the rectangular ...
14950 Quim Castellsaguer
fqces Send Email
Mar 3, 2007
11:32 am
Dear friends, I have read in "American Mathematical Monthly", may 2006, this result: "Any inscribed triangle UVW is similar to the cevian triangle of a point...
14951 jpehrmfr Send Email Mar 3, 2007
11:35 am
Dear friends [QTB] ... one equilateral triangle inscribed in (O) taken A as one vertex. We denote its bottom line wrt A as La, intesection of La with sideline ...
14952 jpehrmfr Send Email Mar 3, 2007
11:57 am
Dear Quim ... This is not possible with ruler and compass : look at the case UVW equilateral; there exists usually 4 or 6 equilateral cevian triangles, none of...
14953 jpehrmfr Send Email Mar 3, 2007
12:54 pm
Dear friends ... [JPE] ... one ... going ... perpendicular ... mapping ... UbVb; ... Here is a more symetric way to draw this figure : Ca is the circle going...
14954 jpehrmfr Send Email Mar 3, 2007
1:42 pm
Dear friends I wrote ... the ... this ... a ... then ... In fact, this is a bit tedious because the centers of the three circles Ca, Cb, Cc are homothetic in...
14955 Francois Rideau
francoisrideau Send Email
Mar 3, 2007
3:09 pm
... And what about the conic locus of the point BU' inter CW' through B and C? ... . ... [Non-text portions of this message have been removed]...
14956 Francois Rideau
francoisrideau Send Email
Mar 3, 2007
3:20 pm
Sorry, I send my post by mistake! I only want to say that this problem is a special case of the following: That is to say, given 3 homographic motions t-->...
14957 Nikolaos Dergiades
ndergiades Send Email
Mar 3, 2007
3:30 pm
Dear Quim, ... As Jean-Pierre said, P is conic constructible, and the construction of the conics is the following: Let A'B'C'= UVW be the triangle inscribed in...
14958 Aleksandra.Wojtas@...
aleksandraali Send Email
Mar 3, 2007
3:49 pm
I'm looking for some information which I need to my thesis. I'm going to put there something about Simson Line. And while the theorem and the proof was not so...
14959 Ricardo Barroso
ricardobca Send Email
Mar 3, 2007
4:00 pm
Dear Aleksandra please .. author, title, review, of article? Ricardo Barroso ... De: "Aleksandra.Wojtas@..." <wojtas.ola@...> Para:...
14960 Aleksandra.Wojtas@...
aleksandraali Send Email
Mar 3, 2007
4:29 pm
sorry, I forgot *Discussions: Relating to the "Simson Line" or "Wallace Line"* Roger A. Johnson *The American Mathematical Monthly*, Vol. 23, No. 2 (Feb.,...
14961 jpehrmfr Send Email Mar 3, 2007
4:33 pm
Dear friends ... it ... Robert ... I quote Roger A. Johnson in Modern Geometry : << In the nineteenth century, it was generally supposed that this theorem was...
14962 Ricardo Barroso
ricardobca Send Email
Mar 3, 2007
5:30 pm
Dear Hyacinthos The article of Johnson Ricardo ... De: "Aleksandra.Wojtas@..." <wojtas.ola@...> Para: Hyacinthos@yahoogroups.com Enviado: sábado,...
14963 Steve Sigur
steve_sigur Send Email
Mar 3, 2007
6:51 pm
... Jean-Pierre, Thanks. I used to call these "polar conics" but Conway has me calling them "diagonal conics." Terminology...ug! Since the incircles are...
14965 jpehrmfr Send Email Mar 4, 2007
4:09 pm
Dear Steve [Steve] ... parallel ... [JP] ... asymptots of ... precevian ... the ... [Steve] ... Because they have a diagonal matrix?? Let L1,L2 be the infinite...
Messages 14935 - 14965 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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