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Hyacinthos · We discuss themes on Triangle Geometry

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  • Members: 3
  • Category: Geometry
  • Founded: Dec 22, 1999
  • Language: English
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Let ABC be a triangle. Draw a cevian AD so that: the intouch (antitangential) triangles of the triangles ADB, ADC be in perspective. That is: A /\ / \ / \ ...
18 May 2, 2008
10:38 am

maedu@...
maedu_acosta
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Dear Hyacinthos In triangle (ABC), point M= [m:n:p] has for cevian triangle (PQR), with P =[0:n:p], Q = [m:0:p], R=[m:n:0] Parallel line through P to (AC) cuts...
5 May 1, 2008
8:45 am

michgarl
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Dear friends, the circumconics S_B yz + S_C zx + S_A xy = 0, S_C yz + S_A zx + S_B xy = 0 meet again at the Tarry point. These circumconics appear a locus. You...
1 May 1, 2008
6:26 am

garciacapitan
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Dear friends, Let P be a point in plane with circumcevian triangle A'B'C' with respect to a triangle ABC. Let s(A'), s(B'), s(C') be the Simson lines of points...
5 Apr 29, 2008
12:15 pm

Bernard Gibert
bernardgibert
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Dear Hyacinthists, let ABC be a triangle, I the incenter, 1 the circumcircle, O the circumcenter, A' the second intersection point of AI and 1, A" the...
1 Apr 28, 2008
3:26 pm

Jean-Louis Ayme
jeanlouisayme
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Dear friends I think one can generalize the results of Paris Pamphilos in his beautifil paper D(3) actions on a triangle in this way: Let <Gamma> be a circle...
4 Apr 28, 2008
3:26 pm

Francois Rideau
francoisrideau
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Dear Hyacinthians, the perpendiculars to the angular bisectors through the corresponding excenters form a triangle A*B*C* perspective with ABC The perspector...
6 Apr 26, 2008
3:03 am

Nikolaos Dergiades
ndergiades
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Dear Paris and dear friends I read again your beautiful paper on the D(3) action on a triangle. Of course, I knew already most of this topic but I see now you...
1 Apr 24, 2008
5:00 pm

Francois Rideau
francoisrideau
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Dear Hyacinthos In a file in French (nouveau point de vue), I propose a new point of view about some topics of elementary geometry In particular, I explain my...
1 Apr 23, 2008
3:42 pm

michgarl
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Dear Hyacinthists, a proof of this result has been published on my website http://perso.orange.fr/jl.ayme clik on "contenu" then "volume 3" Sincerely ...
1 Apr 22, 2008
4:22 pm

Jean-Louis Ayme
jeanlouisayme
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Dear friends As I see some of you like affine geometry, I give you some affine riddles to find when day dreaming during spring time. So we start with your...
3 Apr 18, 2008
2:05 pm

Francois Rideau
francoisrideau
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Dear Nikolaos and Hyacinthists, a synthetical proof can be obtain by using the circles of Huseyin Demir in the particular case when the lines are parallels. I...
2 Apr 14, 2008
12:50 pm

Milton Donaire Peña
jaimegeomat
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I have a (may be silly) question! Please anwser me! Thanks everybody! Let A'B'C' be the cevian triangle of incenter of triangle ABC. Let A" be the symmetry...
6 Apr 12, 2008
10:28 am

Nikolaos Dergiades
ndergiades
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Thanks to Javier Garcia Capitán for his observations to the problems that I have raised, and also to Pavan Naidu, for his observations. Forgive the correct...
2 Apr 11, 2008
4:45 pm

Nikolaos Dergiades
ndergiades
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Dear Friends: in A Triángle ABC, P is on AC,C1: circle inscript in ABC y C2: circle inscript in BPC. The straight line parallel to AC and tangent to the...
1 Apr 8, 2008
4:24 pm

Milton Donaire Peña
jaimegeomat
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Forgive in the message 16255 the terms of reference are incorrect. It looks like to me an attractive problem presented in a paper(role) of the...
1 Apr 8, 2008
2:40 pm

Milton Donaire Peña
jaimegeomat
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Dear Nikos: I send my solution euclidea of 456 Greetings Ricardo ... De: Nikolaos Dergiades <ndergiades@...> Para: Hyacinthos@yahoogroups.com Enviado:...
4 Apr 10, 2008
2:13 pm

Ricardo Barroso
ricardobca
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Can somebody please translate this into English? Cuando sobre los lados de un triángulo se construyen cuadrados de lados de igual longitud que los lados del...
1 Apr 7, 2008
6:01 pm

Milton Donaire Peña
jaimegeomat
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Dear friends: The great geometer Spanish John Bosco Romero has devoted a tribute to Juan Carlos Salazar in ...
1 Apr 4, 2008
4:54 pm

Ricardo Barroso
ricardobca
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Dear friends: Given the knowledge that I have the esteem they had Juan Carlos, shareregret that my husband died the day 31-03-08 in South Africa, hisremains...
1 Apr 4, 2008
4:51 pm

Ricardo Barroso
ricardobca
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Dear friends, I would like to dedicate the following (new?) result to the memory of Juan Carlos Salazar. Though I didn't personally know him, I express my ...
3 Apr 10, 2008
2:13 pm

Cosmin Pohoata
pohoata_cosm...
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Dear Ricardo, a very sad new to day... I was in contact with Juan Carlos for one of my article and he told me that he was working in Mozambique... I give You...
1 Apr 4, 2008
4:29 pm

Jean-Louis Ayme
jeanlouisayme
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Dear friends: I regret to report that the great geometer Venezuelan Juan Carlos Salazar has died. In his tribute I have edited this problem. ...
3 Apr 7, 2008
2:55 pm

Nikolaos Dergiades
ndergiades
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Hello Hyacinthists, Here is a problem: In a triangle ABC,E and F are points on BC such that AE and AF are the trisectors of BAC.BB' is a median. O is the...
3 Apr 4, 2008
4:30 pm

pavan naidu
pavan_mahathey
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Dear Floor and Hyacinthists, a new purely proof has being put on my website: volume (2008) Le cercle de van Lamoen http://perso.orange.fr/jl.ayme Sincerely ...
8 Apr 9, 2008
2:19 pm

Francois Rideau
francoisrideau
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Dear all, Please try your hand on the following problem: In a triangle ABC,E and F are points on BC such that AE and AF are the trisectors of BAC.BB' is a...
1 Apr 2, 2008
11:42 am

pavan naidu
pavan_mahathey
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... From: Francois Rideau <francois.rideau@...> Date: Sat, Mar 29, 2008 at 2:02 PM Subject: Re: [EMHL] Neuberg line? To: Nikolaos Dergiades...
1 Apr 1, 2008
12:56 am

Francois Rideau
francoisrideau
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Dear Hyacintos I join to this message a file with the calculus and a drawing Giving a ideal point[-n-p:n:p], you draw a line from A cutting (BC) in M = [0:n:p]...
2 Mar 28, 2008
4:55 pm

Francois Rideau
francoisrideau
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Dear friends I ask you here a question of terminology. In the euclidian plane, we have 2 pairs of points (A, B) and (A', B'). For the sake of simplicity, I...
3 Mar 28, 2008
4:55 pm

Francois Rideau
francoisrideau
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Dear friends, While reviewing some old notes of mine on mixtilinear incircles, I ran through the following result: Let M be an arbitrary point on the...
4 Apr 4, 2008
4:30 pm

Cosmin Pohoata
pohoata_cosm...
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