... drawing "by ... Lineal.) ... THX for the tip. DLed. Can someone check the following? It doesn't work with actual test values, and I must have made a stupid...
... UNCLE OF EDIT: Flunked a factor of 2. Now it works with the circumcenter (pi-@,pi-ß,pi-y). (@,ß,y) does NOT work. Double drat. (2@,2ß,2y) as well as...
17000
Hyacinthos@yahoogroup...
Dec 1, 2008 3:07 pm
Hello, This email message is a notification to let you know that a file has been uploaded to the Files area of the Hyacinthos group. File : /cercle...
17001
ForumGeom
ForumGeom@...
Dec 1, 2008 3:22 pm
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2008volume8/FG200828index.html The editors Forum...
Hi Hyacinthians, ... [ That is draw on ABC the isosceles triangles BUC, CVA, AWB, with angles U,VW equal to x (similar isosceles triangles) Then AU, BV, CW...
17003
ForumGeom
ForumGeom@...
Dec 3, 2008 8:24 pm
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2008volume8/FG200829index.html The editors Forum...
... THX, I would have asked that eventually anyway (my memory - x,x,x works - *didn't* fail me this time :-) This leaves (for ending this thread :-) the...
http://pagesperso-orange.fr/bernard.gibert/Tables/table14.html An obvious question would be to ask for the point for which the cevians concur (like the...
Dear all, Here is a simple poser: In a triangle ABC, D is the midpoint of BC, B' is the foot of the altitude from B upon AC,and Z is the midpoint of CH. ...
Dear Vijayaprasad, I think that as H you mean the orthocenter of ABC. Construct the symmetric point B" of B relative to Z. The parallel from B" to DZ meets the...
Dear Hauke, I think the answer is yes. If we consider an arbitrary convex quadrilateral ABCD, we can construct a point P inwardly to it, such that the...
Dear All My Friends, Following geometrical facts are very easy to prove but they are interesting enough. There is also one problem: to find the best (optimal,...
17011
ForumGeom
ForumGeom@...
Dec 5, 2008 4:51 pm
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2008volume8/FG200830index.html The editors Forum...
Dear Nikos Dergiades, You mean the symmetric point B'' of B' relative to Z? Alternatively, Let the circles D(DB') and Z(ZB') cut at C Let B be the symmetric...
Dear Vijayaprasad, ... Yes. You are right. Sorry for the typo. Best regards Nikos Dergiades ___________________________________________________________ ...
Dear Hauke, If I understood your problem we have the following: Let 2p, 2q, 2r be the peak angles of the isosceles triangles A'BC, B'CA, C'AB outside ABC and x...
Let ABC be a triangle, P a point, and A'B'C' the cevian triangle of P. In the complete quadrilateral bounded by the lines (AB, BB',AC, CC'), denote Emelyanov...
Dear Alexey, thank you very much. You sent your message only to me and not to hyacinthos. So I tried to answer privately without success. My message returned. ...
Dear friends As I have nothing else to do to forget subprimes , I was daydreaming this afternoon about Newton line. I remember you the saga. You start with...
Dear Francois, I have a brief comment on something you wrote in your message on Newton's line. ... not ... proof ... Why are CPU proofs not enough? I am not...
Dear François and Harold, I think both your are right, Being a mathematician, I am closer to François, since a good proof requires the checking of all cases....
Dear Harold Of course I was joking just to titillate your curiosity! And by the way, I am very very happy to have GSP too! As I said it in my previous post,...
... A bit of computing also affirms that - a triangle similar to ABC can be rotated (1), scaled (1) and shifted (2 free variables), and the perspector just...
... Yup, I also dimly remembered there was a classic solution with half-angles. Your arccot formula explains many things, although the cases 2A,2B,2C and...
... OK. Let ABC be a triangle, and A'B'C' an equilateral triangle circumscribed around ABC, like in your table 14. Now demand that AA',BB' and CC' concur in O....
17025
Hyacinthos@yahoogroup...
Dec 8, 2008 8:35 am
Hello, This email message is a notification to let you know that a file has been uploaded to the Files area of the Hyacinthos group. File : /Le...
Dear Hauke, Dear Nikolaos, In addition to the solutions (and notation) of Nikolaos here are some extra solutions though not based on isosceles triangles but on...
... Addendum: A numeric solution for the Kimberling triangle suggest the Fermat point #13 (can't be) and alternatively y=1.9094098548 (not in list, but it...
