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Messages 20437 - 20467 of 21025   Oldest  |  < Older  |  Newer >  |  Newest
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20437 Francisco Javier
garciacapitan Offline Send Email
Dec 1, 2011
9:13 pm
Dear Randy, The point at infinity of line O1O2 is X(526). The coordinates of O1 are shown below (T stands for twice the area of the triangle multiplied by...
20438 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 2, 2011
7:26 pm
A construction of X(84) and a general locus: http://anthrakitis.blogspot.com/2011/12/reflections-of-cevians-in-cevians.html Being the center X84 on Darboux...
20440 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 2, 2011
11:40 pm
Locus of P is circumcircle + McCay cubic. ... Francisco Javier García Capitán http://garciacapitan.99on.com El 2 de diciembre de 2011 23:14, Antreas...
20441 Nikolaos Dergiades
ndergiades Offline Send Email
Dec 3, 2011
8:03 am
Dear friends, 1) If two triangles ABC and A'B'C' have the same circumcircle and are perspective at P (A'B'C' is the circumcevian triangle of P relative to ABC)...
20442 Sung Hyun Lim
bbblow Offline Send Email
Dec 3, 2011
9:53 am
Dear Nikolaos, In the first case, Q is midpoint of P and O. This can be easily derived from the fact that [circumcenter of PBC'] is image of [intersection of...
20443 Nikolaos Dergiades
ndergiades Offline Send Email
Dec 3, 2011
12:13 pm
Dear Sung Hyun thank you. Francisco Garcia answered me privately that Q in first case is mid point of OP after finding the barycentrics of Q. Yes, you are...
20444 Francisco Javier Garc...
garciacapitan Offline Send Email
Dec 3, 2011
1:54 pm
Hello, Sung and Nikolaos, In case 1), there exist two points P for which the six circumcenters are on a circle. These two points lie on the Euler line, its...
20445 Barry Wolk
wolkbarry Offline Send Email
Dec 3, 2011
10:20 pm
I was able to replace your polynomial of degree 14 with one of degree 6.   The coordinates of O1 are cyclically symmetric, and the first coordinate is     ...
20446 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 3, 2011
10:38 pm
Let ABC be a triangle, IaIbIc the excentral triangle and A'B'C' the extagents triangle [see it HERE<http://mathworld.wolfram.com/ExtangentsTriangle.html> ] Let...
20447 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 3, 2011
10:49 pm
On Sun, Dec 4, 2011 at 12:37 AM, Antreas Hatzipolakis ... One of the centers is O. The other one?? APH -- http://anthrakitis.blogspot.com/ [Non-text portions...
20448 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 3, 2011
11:10 pm
-a^2 b^2 c^4 x^3 y - b^4 c^4 x^3 y + b^2 c^6 x^3 y + a^4 c^4 x y^3 + a^2 b^2 c^4 x y^3 - a^2 c^6 x y^3 + a^2 b^4 c^2 x^3 z - b^6 c^2 x^3 z + b^4 c^4 x^3 z +...
20449 Bernard Gibert
bernardgibert Offline Send Email
Dec 4, 2011
4:16 am
Dear Antreas, this is the Euler-Morley quartic Q002. http://bernard.gibert.pagesperso-orange.fr/curves/q002.html Best regards Bernard ... [Non-text portions of...
20450 Sung Hyun Lim
bbblow Offline Send Email
Dec 4, 2011
5:33 am
Dear all, Take a conic from pencil generated by Steiner inellipse and Orthic Axis squared. Circumconics with perspectors on this conic have equal eccentricity...
20451 Bernard Gibert
bernardgibert Offline Send Email
Dec 4, 2011
6:03 am
Dear Sung Hyun, ... that with perspectors the intersections of the circumcircle and the orthic axis. it is real when ABC is obtusangle. Best regards Bernard ...
20452 Francisco Javier
garciacapitan Offline Send Email
Dec 4, 2011
7:59 am
This is the point S = {a (a^3 - a^2 b - a b^2 + b^3 - a^2 c - 2 a b c + b^2 c - a c^2 + b c^2 + c^3), b (a^3 - a^2 b - a b^2 + b^3 + a^2 c - 2 a b c - b^2 c +...
20453 jpehrmfr Offline Send Email Dec 4, 2011
8:40 am
Dear Sung Hyun and Bernard ... Yes, very good. If you consider the feet U & V of the tangents from a point P to an inconic, the pencil of conics touching PU &...
20454 Sung Hyun Lim
bbblow Offline Send Email
Dec 4, 2011
8:45 am
Dear Jean-Pierre and Bernard, Big thanks to both of you for the interesting results. I'd like to throw another question: what is the value of (1-2e^{-2})^2 for...
20455 jpehrmfr Offline Send Email Dec 4, 2011
9:51 am
... If I didn't mistake, it should be -cos(A)cos(B)cos(C) (If ABC is acutangle, your conic has no real point) Kind regards. Jean-Pierre...
20456 jpehrmfr Offline Send Email Dec 4, 2011
10:54 am
Dear Sung Hyun Lim a remark : as the tangential triangle KaKbKc is the precevian triangle of K, the tangential triangle is selfpolar wrt your conic. Its...
20457 Sung Hyun Lim
bbblow Offline Send Email
Dec 4, 2011
11:20 am
Barycentrics of [point with coordinates (u:v:w) from perspective of tangential triangle] are K [Non-text portions of this message have been removed]...
20458 Sung Hyun Lim
bbblow Offline Send Email
Dec 4, 2011
11:21 am
Sorry, I accidentally sent an incomplete message. Sung Hyun [Non-text portions of this message have been removed]...
20459 Sung Hyun Lim
bbblow Offline Send Email
Dec 4, 2011
11:29 am
Barycentrics of [point with coordinates (u:v:w) from perspective of tangential triangle] are K * anticomplement of [X div [anticomplement of K] ] where * is...
20460 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 4, 2011
11:40 am
Dear Bernard Thank you. The email correspondace between Francisco and me took place after midnight, and it seems we were semi-sleeping :-) Antreas ... ...
20461 Quang Tuan Bui
bqtuan1962 Offline Send Email
Dec 4, 2011
3:33 pm
Dear All My Friends,   Point E is orthogonal projection of focus F on directrix of a parabola. The circle with diameter EF intersects the parabola at two...
20462 Bernard Gibert
bernardgibert Offline Send Email
Dec 4, 2011
5:48 pm
Dear Sung Hyun and Jean-Pierre, ... Actually, the bicevian conic is bitangent to the Steiner inellipse at its intersections with the orthic axis but these...
20463 Sung Hyun Lim
bbblow Offline Send Email
Dec 5, 2011
1:05 am
Dear Bernard, Just a remark: Jean-Pierre also commented that this is a bitangent pencil in #19531. Regards, Sung Hyun [Non-text portions of this message have...
20464 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 5, 2011
9:47 am
A construction of X(54) http://anthrakitis.blogspot.com/2011/12/reflections-of-circumcircle-in.html APH [Non-text portions of this message have been removed]...
20465 Antreas Hatzipolakis
xpolakis Offline Send Email
Dec 5, 2011
12:59 pm
Let ABC be a triangle, P a point, A'B'C' the pedal triangle of P, A12, A13 the orthogonal projections of the excenters I2, I3 on PA', resp.. Let A* = BA13 /\...
20466 forumgeom forumgeom
ForumGeom@... Send Email
Dec 5, 2011
6:24 pm
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2011volume11/FG201128index.html The editors Forum...
20467 Angel
amontes1949 Offline Send Email
Dec 5, 2011
7:27 pm
In: Eric Danneels and Nikolaos Dergiades.- A Theorem on Orthology Centers. Forum Geometricorum Volume 4 (2004) 135–141. ...
Messages 20437 - 20467 of 21025   Oldest  |  < Older  |  Newer >  |  Newest
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