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Hyacinthos · We discuss themes on Triangle Geometry

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  • Members: 3
  • Category: Geometry
  • Founded: Dec 22, 1999
  • Language: English
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Messages 5999 - 6029 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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5999 Paul Yiu
yiuatfauedu Send Email
Oct 25, 2002
2:18 pm
Dear Jean-Pierre, ... Euler has written 2 long papers on this problem: [729] Dilucidationes super problemate geometrico de quadrisectione, M\'emoires de...
6000 Paul Yiu
yiuatfauedu Send Email
Oct 25, 2002
2:33 pm
Dear Yagci, ... On the other hand, if we consider a right isosceles triangle ABC with A=45, B=45, and C=90. There is an interior point P such that PAB = 15,...
6001 jpehrmfr Send Email Oct 25, 2002
3:01 pm
Dear Paul ... D' ... duas ... 333. ... Many thanks, Paul, for these references. In fact, there is a natural way to proceed (I don't know how Euler has solved...
6002 yagcimustafa Send Email Oct 25, 2002
6:51 pm
dear Paul, i think you missed a word while reading... i have written that 'these six angle measurements are not equal and all of them are integer... ... with...
6003 Nikolaos Dergiades
ndergiades Send Email
Oct 25, 2002
7:54 pm
Dear Paul, Yagci and all, If x, y, z are the angles PAB, PCB, PBC to divide an equilateral triangle with different angles there are the following 6 cases y...
6004 RICARDO BARROSO CAMPOS
rbarroso@... Send Email
Oct 25, 2002
8:22 pm
Friends of Hyacinthos: In http://www.pdipas.us.es/r/rbarroso/Pruebas/dou1140.pdf Is the solve to Circle of Dou, CRUX MATHEMATICORUM NOVEMBER 2002 . The teacher...
6005 Paul Yiu
yiuatfauedu Send Email
Oct 25, 2002
9:22 pm
Dear Nik, ... Thank you for this counter-example. Is this one of the triangles recently discussed on Hyacinthos? Best regards Sincerely Paul...
6006 yagcimustafa Send Email Oct 25, 2002
9:37 pm
... dear Nikos, i wanted to mean that there have no other six angles that satisfy the relation, then i know there are 6 cases for it... sorry for my ...
6007 Nikolaos Dergiades
ndergiades Send Email
Oct 25, 2002
10:32 pm
Dear Paul, [ND] ... [PY] ... triangles recently ... ******** If you mean the 53 Langley's type triangles NO it is an example made now by the computer and there...
6008 Nikolaos Dergiades
ndergiades Send Email
Oct 25, 2002
10:32 pm
Dear Jean-Pierre, this problem is Leibniz's problem and leads to an equation of eighth degree. F.G-M 1624a If a point D is on the side AB then we can...
6009 yagcimustafa Send Email Oct 25, 2002
10:54 pm
... the ... the ... a ... FCD ... here is my synthetic solution for CASE 2: for a point D outside the triangle ABC, draw an equilateral triangle PDC that makes...
6010 yagcimustafa Send Email Oct 25, 2002
11:16 pm
it's easy but i have a question about this theme... if a line seperates the triangle ABC into two parts that have equal areas and equal perimeters, then show...
6011 jpehrmfr Send Email Oct 25, 2002
11:45 pm
Dear Nikolaos ... Many thanks for the reference. What is very STRANGE is the fact that in Rouche et Comberousse : Traite de Geometrie - Gabay reprint -, I see ...
6012 yagcimustafa Send Email Oct 26, 2002
10:44 am
ABC is a triangle A-bisector intersects BC at D B-bisector intersects AC at E C-bisector intersects AB at F if m(FDE)=90 then what is m(BAC)? MUSTAFA YAGCI...
6013 RICARDO BARROSO CAMPOS
rbarroso@... Send Email
Oct 26, 2002
10:59 am
Dear friends of Hyacinthos Is m(BAC)= 120 In http://www.pdipas.us.es/r/rbarroso/trianguloscabri/problema9.htm in its alternative vision, The problem is...
6014 none none
zhora_k Send Email
Oct 26, 2002
7:08 pm
Hi all, -- On Fri, 25 Oct 2002 23:16:31 yagcimustafa wrote: it's easy but i have a question about this theme... if a line seperates the triangle ABC into two...
6015 Nikolaos Dergiades
ndergiades Send Email
Oct 27, 2002
2:26 pm
Dear Yadci, ... m(BAP)=18,m(PAC)=42,m(PCA)=54,m(PCB)=6,m(PBC)=12,m(PBA)=48 ... triangle ... we have the ... Also for a ... triangle BAE ... we can ... see that...
6016 Barry Wolk
wolkbarry Send Email
Oct 27, 2002
10:05 pm
... ABC... ... I found a simple equation connecting these six angles, which holds for a general triangle (not necessarily equilateral). I used x=IAP, y=IBP,...
6017 yagcimustafa Send Email Oct 27, 2002
11:25 pm
... OK, LET ME EXPLAÝN: since EADFK is a proper pentagon, |AD|=|DF|... since PDF is an equilateral triangle, |DF|=|PD|... so |AD|=|DF|=|PD|, namely |AD|=|PD|,...
6018 yagcimustafa Send Email Oct 28, 2002
12:01 am
Could you please give a synthetic proof for the ... DEAR NIKOS, for a point K on [AE],draw a [DK] as parallel to [BC]... for a point F outside the triangle...
6019 jpehrmfr Send Email Oct 28, 2002
9:09 am
Dear Hyacinthists, here is a problem : construct a convex quadrilateral Ab,Bc,Ac,Ca such as - Ab lies on [AB], Bc lies on [BC], Ac and Ca lie on [AC] - the...
6020 Nikolaos Dergiades
ndergiades Send Email
Oct 28, 2002
12:11 pm
Dear Ricardo , [Mustafa] ABC is a triangle A-bisector intersects BC at D B-bisector intersects AC at E C-bisector intersects AB at F if m(FDE)=90 then what is...
6021 ForumGeom
ForumGeom@... Send Email
Oct 28, 2002
4:54 pm
The following paper has been published in Forum Geometricorum. It can be viewed at http://forumgeom.fau.edu/FG2002volume2/FG200215index.html The Editors Forum...
6022 RICARDO BARROSO CAMPOS
rbarroso@... Send Email
Oct 29, 2002
2:18 pm
Dear Hyacinthos, Nik and Mustafa: In my message, 6013, said: it is an alternative vision. so and as it indicates Nik in effect, in ...
6023 yagcimustafa Send Email Oct 29, 2002
8:12 pm
... dear nikos, could you please explain where the point P is... i sent you a private mail to your email address but i think you couldn't get it... isn't your...
6024 Nikolaos Dergiades
ndergiades Send Email
Oct 29, 2002
8:47 pm
Dear Moustafa, you wrote: dear nikos, could you please explain where the point P is... Sorry, it is false instead of P I mean D: Hence the correct solution to...
6026 eky
eyupkamilyes... Send Email
Oct 30, 2002
7:28 pm
Please, have a look at the gestion on the following link. http://groups.yahoo.com/group/Hyacinthos/files/hesap.gif...
6027 zbaruh Send Email Oct 31, 2002
9:49 am
Dear Hyacinthians, Is it true that there exists *at most* one triangle with given elements a, t_b, t_c (the last two are angle bisectors)? If yes, how can we...
6028 Bernard Gibert
bernardgibert Send Email
Oct 31, 2002
1:57 pm
Dear friends, GaGbGc is the antimedial triangle, A',B',C' are the reflections of A / BC, etc. for any point M, Ca is the conic through B, C, A', Ga, M, Cb, Cc...
6029 Bernard Gibert
bernardgibert Send Email
Nov 1, 2002
4:33 am
Dear friends, ... after rereading that, I feel it is not very clear : I just wanted to say that the 3 conics have 3 points in common (one of them being M) iff...
Messages 5999 - 6029 of 21989   Oldest  |  < Older  |  Newer >  |  Newest
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