--- Kent Andersen <sci@...> wrote:

> Sounds like you have done quite a bit of homework. This seems to be a
> typical result from MEG builders
> In a video that I watched where bearden goes into detail on the MEG's
> operation it is more of a L/C
> type of circuit. from what he said in that video the input waveform
> is
> like /`\ ramp up and ramp down.

That makes sense since the primary and secondary should be closely
coupled ( as distinct from the sine output of a high Q self resonant
secondary that is loosely coupled)

> since its a L/C circuit you must design a load match transformer that
> will allow you to pull power out of it.
> simply putting a resistive load across the output will detune the
> circuit and throw it out of its "balance"

That does not make sense, a resistive load would lower the Q but by
definition not detune anything. It would change the flux in the core,
so that would change the inductance a bit, and some frequency & dwell
adjustments could possibly be helpful. Does the "load match"
transformer you mention have something to do with drawing power from
both secondarys equally to maintain the balance between the sides?

> I have not done this myself yet as I have been short on time but that
> is
> my next step to design a, more or
> less a balun or unun to decouple the meg from the effects of the
> load.
>
> (Kent)


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