well I think you could use a smaller secondary coil on it. Most of these
guys go for big voltage
because they get the idea that big voltage = big power.
you might try youtube.com they sometimes have these videos pirated there.
Bearden is selling the video on his website here.
http://www.cheniere.org/sales/buy-e1.htm

he has completely moved away from his theories of phase conjugation
(junk science stuff)
to more practical theories that everyone else in the scientific
community is using.
I would surely check out that video if you can before you go out
spending big wads of cash
do your research as it is known that the patents do not contain all of
the information required
to reproduce what it is claimed to do.
some other data you might want to look at is here if you have not already
http://jnaudin.free.fr/meg/meg.htm

I recently purchased 2 of the metglass C cores AMCC500 which I am going
to use in some experiments
with ferro magnetic resonance. they were 179.00 per pair.. so if you
decide to build a meg prepare
to go for a ride.

Hope that helps

Kent

lichtrov wrote:
>
> Thank you for the response. I'm thinking about load matching also.
>
> Where the video, you're talking about, can be downloaded from?
>
> And one more question: does anybody have an idea why such a huge
> secondary voltage is required (TB in the patent claims that it can be
> lowered with smaller secondary windings, but I didn't see anything
> done with low secondary voltage)?
>
> --- In MEG_builders@yahoogroups.com
> <mailto:MEG_builders%40yahoogroups.com>, Kent Andersen <sci@...> wrote:
> >
> > Sounds like you have done quite a bit of homework. This seems to be
> a
> > typical result from MEG builders
> > In a video that I watched where bearden goes into detail on the
> MEG's
> > operation it is more of a L/C
> > type of circuit. from what he said in that video the input waveform
> is
> > like /`\ ramp up and ramp down.
> > as you can tell there are some sweet spots between pulse width and
> > frequency of the drive signal.
> > since its a L/C circuit you must design a load match transformer
> that
> > will allow you to pull power out of it.
> > simply putting a resistive load across the output will detune the
> > circuit and throw it out of its "balance"
> > I have not done this myself yet as I have been short on time but
> that is
> > my next step to design a, more or
> > less a balun or unun to decouple the meg from the effects of the
> load.
> >
> > (Kent)
> >
> > lichtrov wrote:
> > >
> > > Hi all!
> > >
> > > I'm an EE and was intriqued by MEG because of simple circuitry
> > > required to operate. I've built my own replication of the MEG -
> also
> > > unsuccessfully (I mean I didn't obtain COP > 1). In my controller
> I
> > > can independently change both frequency and duty cycle of the gate
> > > driving voltage. My MEG has taps on both primary and secondary
> > > windings and I can play with turns ratio. While working without
> load,
> > > I obtained output voltage with close to sine waveform and
> amplitudes
> > > around reported by Bearden and Naudin. However, after loading the
> > > output (even lightly with 100kOhm resistor), output voltage
> decreases
> > > significantly to a few volts.
> > >
> > > It's pretty hard to debug the device since I don't understand how
> it
> > > should work. I started to dig into Berden's patent and I have a
> > > question: does anybody have an idea how Bearden measured the
> current
> > > in both primary (Fig 6D) and secondary (Figs 6G,H)?
> > >
> > > The question arised because the primary current he described has
> > > extremely small duty cycle - around 1 microsecond for both rise
> and
> > > fall. It supposes duty cycle with around 500 nanoseconds of active
> > > driving voltage - nothing comparable can be seen in Figs 6A,B.
> Also I
> > > tried to build high side current measurement circuit and (even
> with
> > > most recent chips!) it has around 500kHz bandwidth and cannot
> provide
> > > such a sharp waveform. Thus I presume that Tom measured a voltage
> on
> > > a small low side resistor. The voltage produced by such
> measurement
> > > can have short spikes as presented in Fig 6D because of capacitive
> > > coupling from adjacent circuitry and even from the ground ripple
> > > itself.
> > >
> > >
> >
>
>