Hello, if nobody complains, I will attempt 13th roots from 109-digit numbers instead of 100. Alexis ... Faites un voeu et puis Voila ! www.voila.fr...
lemaire.alexis
lemaire.alexis@...
Apr 1, 2003 11:38 am
822
And that changes a lot to the problem ? ... From: lemaire.alexis [mailto:lemaire.alexis@...] Sent: mardi 1 avril 2003 13:38 To: MentalCalculation Subject:...
Emmanuel.DUBRULLE@...
Apr 1, 2003 11:46 am
823
la> Hello, la> if nobody complains, I will attempt 13th roots from 109-digit numbers instead of 100. I complains. You promised 13th roots from 200-digit...
Oleg Stepanov
olegstepanov@...
Apr 2, 2003 12:13 am
824
I said earlier that I had criteria to quickly detect prime number n MOD 6 ,if = 1 or 5 the n is supposed to be prime. But there is unfortunately exceptions :...
Emmanuel.DUBRULLE@...
Apr 2, 2003 6:01 am
825
... Hi Oleg, do you accept it if I try 13th root from 200-digit number the same day? I don't want we change 100 to 109, only to allow more than 100 as it is...
al.lemaire
al.lemaire@...
Apr 2, 2003 3:17 pm
826
al> Hi Oleg, al> do you accept it if I try 13th root from 200-digit number the same day? Accept??? I afraid my opinion not interest to Guinness Show. Or you ...
Oleg Stepanov
olegstepanov@...
Apr 2, 2003 4:20 pm
827
Yes, it is true that all prime numbers are one more or one less than a multiple of 6 (N mod 6 = 1 or 5). However, as you say, not all such numbers are prime ...
Hello one and all. Just a quick note to introduce myself as a new member. I'm from the UK and am fairly new to the world of MC although I believe I have an...
Nice to meet you Paul Reed ... From: Paul Reed [mailto:paul.reed@...] Sent: jeudi 3 avril 2003 12:50 To: MentalCalculation@yahoogroups.com Subject:...
Emmanuel.DUBRULLE@...
Apr 3, 2003 11:18 am
830
Hello Paul Reed, I am glad you join our group! I am curious to hear more about your attempts and your results. After returning from my travel to South Africa...
Fleissdr@...
Apr 3, 2003 12:23 pm
831
So Oleg, to be clear, do you complain or not? Alexis ... Faites un voeu et puis Voila ! www.voila.fr...
al.lemaire
al.lemaire@...
Apr 3, 2003 7:35 pm
832
al> So Oleg, to be clear, do you complain or not? Alexis Please, I am not Englishmen. Would be you so kind use another word, not "complain". It give me...
Oleg Stepanov
olegstepanov@...
Apr 3, 2003 10:11 pm
834
... al> If you feel nothing bad about my suggestion, this means that you don't complain. Looks like. al> Today I get a great answer from Guinness after 4...
Oleg Stepanov
olegstepanov@...
Apr 4, 2003 3:59 pm
835
. ... I begin to not respect you :))) you don't understand "NEW" ? If this means something, this means 13th root from 100-digit number is erased because of...
al.lemaire
al.lemaire@...
Apr 4, 2003 4:33 pm
836
... In a similar vein, rootists might find some use for the following: N mod 6 = N^3 mod 6 It is easy to see why this should be so: N^3 - N = (N-1) x N x (N+1)...
Hi Paul:I am new too and from Canada.You did better than I did.I have only read the first 100 emails. Have a nice day!: Robert Chan [Non-text portions of...
Hello Paul: My name´s Javier and i write you from north of Spain. I´ve no special ability for M.C. , so i decided start with it. The only operation i do...
... Hello Paul: My name´s Javier and i write you from north of Spain. I´ve no special ability for M.C. , so i decided start with it. The only operation i do...
Javier, Good to hear from you...... it sounds like we're both relative beginners here. I'd love to hear how you square numbers quickly - I'm pretty quick but...
Interresting, I like your method to square numbers. I guess that it's not impossible to extend those principle for more irregular multiplication, you follow a...
Emmanuel.DUBRULLE@...
Apr 14, 2003 9:08 am
842
Emanuel I find it interesting that you find my method interesting - I assumed everyone did it like this!! How would you do it?? I haven't really considered how...
Your algorithm looks like a clever application of a^2+2*a*b+b^2;clever but not revolutionary yet. However , I congratulate you if you found it entirely by...
Emmanuel.DUBRULLE@...
Apr 14, 2003 1:53 pm
844
(This reply to a posting to indianvedicmathematics@yahoogroups.com is sent as a cross-posting to http://groups.yahoo.com/group/indianvedicmathematics and ...
Hello: For squaring i use the well known expresion N^2=(N+d)*(N-d)+d^2 where N is the number to square d a convenient number to make easy the product. ...
Javier, This is great - and just the kind of thing I am keen to learn at the moment. It's good to hear from people with different perspectives and techniques. ...
Don't be afraid to ask question Paul, If you read, all article on Oleg's site so you perheaps know that many of the past calculator couldn't read or write and...
Emmanuel.DUBRULLE@...
Apr 16, 2003 8:36 am
848
Excuseme . I wrote 74^2 with an error ... ^ ... IT MUST BE (70)------------------------------ Best wishes. Javier...
I have found that a restatement of the formulas obtained by applying Newton's method to the problem of finding roots helps a lot. If you calculate the...
Here are some methods for doing some miscellaneous tasks. To calculate the sum of two consecutive squares, triangulate the smaller of the numbers, multiply...
Josh I've some problems understand your explanation because I'm not a verbal thinker (later I'll explain why) could you please show us an exemple with figures....