Hi Jeff, If you read these it may help. http://www.gregorme.com/RH/ This path is quite different to the one you are following but it does not require using...
Greg, I think your goal was the same as mine. But the equivalence between the Mobius Function, then sum of which is called Mertens' Function is shown...
I should rewrite the paper as you say. I sent it to a Journal a few years ago, but I don't think they understood it. After that I shelved it until I saw the...
Greg, I have two RH proofs in my paper. One that shows that M(k) is big oh of x^(1/2 + e) not for simply the power of 1/2, which my paper two would say grows...
Greg, I should also mention that the polite and proper thing to do when someone finds a flaw in your proof, you should humbly retract it until you fix the...
What flaws are you referring to? From: UnsolvedProblems@yahoogroups.com [mailto:UnsolvedProblems@yahoogroups.com] On Behalf Of Jeffrey N Cook Sent: Sunday, 3...
Hello all, I'm going to use my prerogative as group owner and step in here. The only authoritative way for anyone to have their ideas accepted is via peer...
Maybe you need to write to some experts on the RH and see if they have any students or associates who might examine your paper, perhaps for a fee. Gottingen...
Your first flaw is one page one, line one. You "aim" to prove something, but cannot by the method you use; you can show me example after example of something...
Hello all, I have an unusually extreme abhorrence to censorship in any of its forms, but, for the next three days, we'll have a cooling-off period re posts...
Hi all, Two new additions in recent days: another proposed solution to the Dorabella cipher, and the Zodiac Killer's unsolved 340 cipher has been added to the...
Let N = (p^k)*(m^2) be an odd perfect number (abbreviated hereinafter as OPN) with gcd(p, m) = 1, p a prime congruent to k and congruent to 1 modulo 4. (In...
It has been known since the time of Euler that an odd perfect number N (if it exists) must have the form N = p^a * Q^2 where p is prime and p = a = 1 mod 4...
I've added a slightly expanded version of the result below to the web site at http://www.unsolvedproblems.org/UP/index.htm Comments welcome! Tim ... number ......
Hi Renaat, No, the Goldbach Conjecture has not been proved to date! Discussion via this group is welcome. As at the beginning of June 2008, all of the...
Hello, Perhaps you may be interested to check out the conjecture, which I have made lately ? NO "n" exist, such that ( n! + prime(n) ) yields integral m^k ...
Hi, I came up with OEIS A004664 related conjecture: n! + n^2 != m^2 for n>=1, m>= 0 I checked using PARI that indeed n! +n^2 doesn't yield perfect square up to...
Hi there, I am trying to find a problem that has been proven to have no solution and I need some help. I know that is the class of problems called to be...
Hi Haskell, Well, there are several mathematical problems proved to be impossible, such as squaring the circle, doubling the cube and trisecting an angle. ...
Hi Tim, Let me explain myself, all those problems have answer, for example the Turing Halting is proved to not exist a Turing machine capable of saying if...
Greetings ... not sure what kind of problems you seek but what about the proof that there is no general solution to a quintic (or higher) polynomial with real...
No this problem still has an answer that "there is no general solution" the kind of problem I am looking would be more like "about the proof that cannot be...
Hello all, The web site at http://unsolvedproblems.org has undergone a revamp. Also added since the beginning of 2009 are a proposed solution to the Goldbach...
Here is some great progress made on RH. http://www.singularics.com/science/mathematics/ Best, Alex -- alex petty ceo singularics corporation advancing energy...
... and possibly deliberately fatuous. This sentence on page 2 is a barefaced lie: It follows from them quite clearly that a pair of unique, integral legs must...
I began working on the Goldbach Conjecture 2 months ago. I 'solved' it within 3 days in layman's terms but I have spent the rest of the time trying to express...
Hi whotoldyouthat, That's precisely what the unsolved problems web site is for - for ideas and semi-proofs that may be right or may be wrong, but in either...