The web site to accompany this group is about to come online. For the moment, it can be reached at http://www.unsolvedproblems.org and following the link. It...
January 2007: Several typos on the site have been corrected. The existence of the site has been announced on a few relevant newsgroups. The Square of Squares...
This is the first thing that popped to mind, and I know it can't be right, but I can't figure out why it's wrong. It's been proven that (2m+1)+(2n+1) = any and...
I don't think your logic is very clear. You seem to be saying that (1) every even number can be expressed as the sum of two odd numbers, and (2) odd numbers...
Hi Tim, You understood the bulk of what I was trying to say, but I guess what I'm really trying to get at is better served with a few examples. For 2k=6,...
Hi Andrew, That's not correct. Perhaps I can best illustrate by giving you an example, say the GoldSeven Conjecture, which states that every even number is...
OK, I see my error now, and I thought of a modification that at least keeps the GoldSeven Conjecture from being used against it. Instead of splitting up the...
Hi Andrew, Yes, for every even number n = 2k there will be k/2, or (k+1)/2 if k is odd, distinct pairs of odd numbers that sum to it, eg 10 = 2*5 has the three...
Here are my guesses (and nothing more than guesses) re each of the problems listed at the site: Chromatic Number: will be shown to be 7 Collatz: provably true ...
I have just seen a funny thing on the Web, reported in some newspaper (which best remain nameless) by a reporter (who best remain nameless) about the...
Supposedly, many world-famous mathematicians regularly receive crank solutions to unsolved mathematical problems. Now, I can't comment as to the real extent...
A proposed proof of the Riemann Hypothesis has been posted on the web site. It is available from http://www.unsolvedproblems.org/UP/Solutions.htm Tim...
All, I just thought I'd start a post to offer any explanations on my proof which is currently being presented on the Unsolved Problems website. There are a...
Greg, You provide the equivalence to the Mobius function's zeros, which have nothing to do with the Riemann Zeta Function non-trivial zeros. The RH suggests...
Hi Jeff, If you read these it may help. http://www.gregorme.com/RH/ This path is quite different to the one you are following but it does not require using...
Greg, I think your goal was the same as mine. But the equivalence between the Mobius Function, then sum of which is called Mertens' Function is shown...
I should rewrite the paper as you say. I sent it to a Journal a few years ago, but I don't think they understood it. After that I shelved it until I saw the...
Greg, I have two RH proofs in my paper. One that shows that M(k) is big oh of x^(1/2 + e) not for simply the power of 1/2, which my paper two would say grows...
Greg, I should also mention that the polite and proper thing to do when someone finds a flaw in your proof, you should humbly retract it until you fix the...
What flaws are you referring to? From: UnsolvedProblems@yahoogroups.com [mailto:UnsolvedProblems@yahoogroups.com] On Behalf Of Jeffrey N Cook Sent: Sunday, 3...
Hello all, I'm going to use my prerogative as group owner and step in here. The only authoritative way for anyone to have their ideas accepted is via peer...
Maybe you need to write to some experts on the RH and see if they have any students or associates who might examine your paper, perhaps for a fee. Gottingen...
Your first flaw is one page one, line one. You "aim" to prove something, but cannot by the method you use; you can show me example after example of something...
Hello all, I have an unusually extreme abhorrence to censorship in any of its forms, but, for the next three days, we'll have a cooling-off period re posts...
Hi all, Two new additions in recent days: another proposed solution to the Dorabella cipher, and the Zodiac Killer's unsolved 340 cipher has been added to the...
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