Hope someone can help me with this one.  completely stuck.  any solutions out

there?  it's

on page 490 about proving the conditionalized version of the general product

rule.



P(X,Y|e) = P(X|Y,e) P(Y|e)



part b:  prove the conditionalized version of Bayes' Rule in Equation (13.10)



P(Y|X,e) = P(X|Y,e) P(Y|e)

                 ------------

                         P(X)



ANY HELP WOULD BE GREAT.



thanks,

brandon

Both follow the normal proof methods ....



Note that P(X,Y|e) = P(X,Y,e)/P(e)

and P(X|Y,e) = P(X,Y,e)/P(Y,e)

and P(Y|e) = P(Y,e)/P(e)



The first part is immediate from this.



The second part is almost trivial after this ...

Note that,

P(X,Y|e) = P(X|Y,e) P(Y|e)

also,

P(X,Y|e) = P(Y|X,e) P(X|e)



Can u finish it off from here?

-- AI



--- In aima-talk@yahoogroups.com, "brandon_pitt_47"

<brandon_pitt_47@y...> wrote:

>

>

> Hope someone can help me with this one.  completely stuck.  any

solutions out there?  it's

> on page 490 about proving the conditionalized version of the general

product rule.

>

> P(X,Y|e) = P(X|Y,e) P(Y|e)

>

> part b:  prove the conditionalized version of Bayes' Rule in

Equation (13.10)

>

> P(Y|X,e) = P(X|Y,e) P(Y|e)

>                 ------------

>                         P(X)

>

> ANY HELP WOULD BE GREAT.

>

> thanks,

> brandon

yes, i can.  thanks again for your help.



brandon







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