Or here's one that works, and you can change the delimiter in an optional 3rd argument.

function listItemPrepend(list,str) {
    var delim = ",";
    if(arrayLen(arguments) EQ 3) { delim=arguments[3]; }
    return reReplace(arguments.list, "(\w+)(#delim#)?", "#arguments.str#\1\2", "all");

}

nathan strutz
[Blog and Family @ http://www.dopefly.com/]
[AZCFUG Manager @ http://www.azcfug.org/]
[Twitter @nathanstrutz]

On Wed, Nov 11, 2009 at 3:03 PM, Nathan Strutz <strutz@...> wrote:

Why not something simpler, like this

function listItemPrepend(list,str) {
    return reReplace(arguments.list, "(\w)+", "#arguments.str#\1", "all");

}


nathan strutz
[Blog and Family @ http://www.dopefly.com/]
[AZCFUG Manager @ http://www.azcfug.org/]
[Twitter @nathanstrutz]

On Wed, Nov 11, 2009 at 1:31 PM, Charlie Griefer <charlie.griefer@...> wrote:

 

All I can think of is a regular expression to prepend a '1' to any digit not preceded by another digit.  But, it doesn't work.

<cfset mylist = "(1,2,3,4,5)" />
<cfoutput>#rereplaceNoCase(myList, '([^\d])(\d)', '\1x\2', 'all')#</cfoutput>

In that rereplace(), the \1 is a reference to the non-digit character found in front of a digit character.  If you run the code above, you'll get:

(x1,x2,x3,x4,x5)

Which seems peachy, right?  Just replace the 'x' with a '1' in the expression above and you're golden.

But... then you end up with this:
<cfoutput>#rereplaceNoCase(myList, '([^\d])(\d)', '\11\2', 'all')#</cfoutput>

Which doesn't work because the regex engine is now looking for the 11th grouped reference instead of the first.

What I'm trying to say is... just use a loop :) 

But I posted this out of curiosity.  Any regex gurus know of a way to tell the regex engine to effectively break out of looking for a grouped reference?  A way to say "\1 -and- 1 -and- \2" ?

On Wed, Nov 11, 2009 at 12:11 PM, Cheryl Novalis-Marine <cheryl@...> wrote:

 

Anyone know if there is a cf function to update all the values in a list the same? I know I can easily do this my looping over the list, but just wondering if there is a function too that can do this.  

 

For example here is my list (1,2,3,4,5) and I want to insert a 1 in front of each value so that this list is now (11,12,13,14,15).

 

Thanks,
Cheryl

--
Charlie Griefer
http://charlie.griefer.com/

I have failed as much as I have succeeded. But I love my life. I love my wife. And I wish you my kind of success.