Try doin it like this:

#define SIZE 30
int c [SIZE], s[SIZE]; // statement b

#include <stdio.h>
void change (int a[], int, int);
int main ()
{
int d[3];
d[0] = 1, d[1] = 10, d[2] = 25;
int n = SIZE, k = 3;
change (d, k, n);
return 1;
}

void change (int d[], int k, int n)
{
int c [SIZE], s[SIZE]; // statement b
c[0] = 0;
int p;
int min, i, coin = 0;

for (p=1; p<n; p++)
{
c[p] = 0;
s[p] = 0;
printf ("\n test : %d \n", p);
}
}





On Sun, Nov 9, 2008 at 6:11 AM, Mallik <hi_malli2k3@...> wrote:

> Hi All,
>
> Could you please help me out in analysing this issue:
>
> I really find strange behavior with the following code. If the statement b
> is present as below, the for loop is executing infinitely. But when
> statement b is replaced with statement a as
> int c[31], s[31];. Then the for loop is exited after n iterations. Below is
> my gcc version where i executed the code. Please help me out in this regard.
>
> int c [30], s[30]; // statement b
>
> #include <stdio.h>
> void change (int a[], int, int);
> int main ()
> {
> int d[3];
> d[0] = 1, d[1] = 10, d[2] = 25;
> int n = 30, k = 3;
> change (d, k, n);
> return 1;
> }
>
> void change (int d[], int k, int n)
> {
> int c [30], s[30]; // statement b
> c[0] = 0;
> int p;
> int min, i, coin = 0;
>
> for (p=1; p<=n; p++)
> {
> c[p] = 0;
> s[p] = 0;
> printf ("\n test : %d \n", p);
> }
> }
>
> gcc (GCC) 4.1.2 (Gentoo 4.1.2 p1.0.2)
> Copyright (C) 2006 Free Software Foundation, Inc.
> This is free software; see the source for copying conditions. There is NO
> warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
>
> --
> Thanks & Regards,
> Mallik
>
> [Non-text portions of this message have been removed]
>
>
>


[Non-text portions of this message have been removed]