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Reply | Forward Message #151 of 165 |
Hi list,
there's something odd about substitution:

Suppose you have

r=c+a+b
and
x=a+b

then substituting x in the 1st equation is impossible; whereas it
works if a+b appears first.

I guess it has something to do with '+' being a binary operation-- or
is there another reason?

Regards,
Thomas






Mon Sep 18, 2006 6:56 am

thomas_heye
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Message #151 of 165 |
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Hi list, there's something odd about substitution: Suppose you have r=c+a+b and x=a+b then substituting x in the 1st equation is impossible; whereas it works...
Thomas Heye
thomas_heye
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Sep 18, 2006
12:40 pm

Hi Thomas, The usual order precedence for algebraic operators is built into DC Proof. In this case r=c+a+b is interpreted as r=(c+a)+b, the left- most +...
Dan Christensen
dchris1953
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Sep 18, 2006
1:24 pm
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