Group Information- Members: 618
- Category: Mathematics
- Founded: Aug 27, 2001
- Language: English
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Discussion of harmonic analysis and all related fields (wavelets, representation theory, PDE, Fourier series, etc.), including announcements of conferences, job openings, etc.
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This group is not for posting personal preprints, research announcements, or opinions, unless it is relevant to an ongoing discussion. This group is also not intended for promotion of any commercial product. Repeated abuse of posting privileges will result in removal of such privileges.
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Re: continuity of operator norms
Hi, maybe I am completely wrong, but one should be able to interpolate since it is bounded on L^{2-\delta}. So for a \varepsilon depending on \delta and the
Posted - Tue Oct 20, 2009 10:15 pm
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Josef Kirsch
joki49...
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Re: continuity of operator norms
David, By Riesz-Thorin, the logarithm of the operator norm is convex as a function of 1/p, which means it's continuous. Best, Philip
Posted - Tue Oct 20, 2009 7:43 pm
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ptgressman
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continuity of operator norms
I have a linear operator T that is bounded on L^p(w), 2-\epsilon < p < 2+ \epsilon, for a fixed weight w. I know that on L^2(w) the operator norm of T is less
Posted - Tue Oct 20, 2009 6:50 pm
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mablung123
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Posted - Tue Oct 20, 2009 6:50 pm
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Int. J. App. Mathemat...
eic.ijms
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Posted - Thu Oct 15, 2009 11:09 pm
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Mathematics Conferenc...
gzlu2001
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