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Reply | Forward Message #431 of 458 |
Re: [harmonic] question

Dear Fatima
 
1. Unless the haar measure is bounded it will not belong to M(G).
2. Ofcourse, one can conclude that the haar measure is not discrete. This follows because of the fact that Haar measure is translation invariant.
 
Bye
Shravan
--- On Fri, 1/5/09, fatima22_m <fatima22_m@...> wrote:

From: fatima22_m <fatima22_m@...>
Subject: [harmonic] question
To: harmonicanalysis@yahoogroups.com
Date: Friday, 1 May, 2009, 11:27 AM

Dear All
Thanks a lot Maria Roginskala. please help me with the following
questions :
1-As I know when $G$ is a compact group then the Haar measure $\mu$
does belong to $M(G)$. Is it true when $G$ is a locally comapct abelian
group?
2-Let $G$ is a locally compact abelian group.. if we prove that Haar
measure $\mu$ that is restircted to a relatively compact open subset
of $G$ , say $U$ , is not discrete , can we conclude that $\mu$ is not
discrete for the group $G$?
I wish to hear from whom can give his or her comments very soon.
Best Regards
Fatima



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Mon May 4, 2009 4:37 am

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Dear All please help me with the proof of this point. the group $G$ is discrete if the Haar measure $\mu$ is discrete. In the proof of this point the writer...
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Dear All Thanks a lot Maria Roginskala. please help me with the following questions : 1-As I know when $G$ is a compact group then the Haar measure $\mu$ ...
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