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a multiplier operator on the n-torus   Message List  
Reply | Forward Message #435 of 450 |
Re: [harmonic] a multiplier operator on the n-torus

lakhmau wrote:
>
>
>
> Dear all,
>
> I would like to know why the (Bessel-like ?) operator which maps
>
> exp(2i.pi.m.x) |-> exp(2i.pi.m.x) / (1 + |m|^2)^{n/2 - 1}
>
> for any multi-index m \in \Z^n maps the space
>
> L^{n/(n-1)}((0,1)^n)
>
> into L^2((0,1)^n) ?
>
> Sorry, the post is not really readable...
>
> Thanks,
> L.

I have an elementary proof of a similar result at the end of the paper:
http://www.math.missouri.edu/~stephen/preprints/thin.html
You may be able to adopt this to your situation. But really, you want
to learn the Littlewood-Paley decomposition and use that.




Fri May 15, 2009 1:44 am

stephenmontg...
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Message #435 of 450 |
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Dear all, I would like to know why the (Bessel-like ?) operator which maps exp(2i.pi.m.x) |-> exp(2i.pi.m.x) / (1 + |m|^2)^{n/2 - 1} for any multi-index m \in...
lakhmau
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May 14, 2009
3:18 pm

This reply assumes that you left out a square root: (1+|m|^2)^{(n/2-1)/2}. This operator may be expressed as convolution with a kernel k(x) which has a...
Philip Gressman
ptgressman
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May 14, 2009
11:11 pm

Thanks a lot....
lakhmau
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May 15, 2009
3:41 pm

... I have an elementary proof of a similar result at the end of the paper: http://www.math.missouri.edu/~stephen/preprints/thin.html You may be able to adopt...
Stephen Montgomery-Sm...
stephenmontg...
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May 15, 2009
1:45 am
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