---

From: lpc9xxbeginner <schluchti@...>
To: lpc900_users@yahoogroups.com
Sent: Tuesday, April 7, 2009 11:23:52 PM
Subject: [lpc900_users] Re: LPC938 Baudrate generator

Hi,

if you are using the internal RC oscillator, try this:

void init()
{
    BRGCON = 0x00;
    BRGR0 = 0xF0;
    BRGR1 = 0x02;
    BRGCON = 0x03;
    PCON &=0xC0;


SCON = 0x50;
SSTAT = 0x40;
P1M1 = 0x00;
P1M2 = 0x01;
P1M2 = 0x001;
TI = 1;
RI = 0;

}

Best Regards
Bernhard

--- In lpc900_users@yahoogroups.com, "SR" <emddjava@...> wrote:
>
> Hi
>
> I am using LPC938, I am trying to get the UART's baudrate to 9600 but nothing seems to work..I the following code and all I see on hyperterm is just various ASCII characters.
>
>    EA = 0;
>     TR1 = 0;        /* stop timer 1 */
>     ET1 = 0;        /* disable timer 1 interrupt */
>
>     TH1 = 0xFC;  //(unsigned char) (256 - (clock / (16L * 12L * baudrate)));
>
>     PCON |= 0x80;        /* 0x80=SMOD: set serial baudrate doubler */
>
>     TMOD &= ~0xF0;        /* clear timer 1 mode bits */
>     TMOD |= 0x20;        /* put timer 1 into MODE 2 */
>     SCON = 0x50;
>
>     TR1 = 1;        /* start timer 1 */
>
>
>     INT_ENABLE;
>
>
>     EA = 1;
>
> Samuel
>




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