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math_club

Group Information

  • Members: 723
  • Category: Mathematics
  • Founded: Mar 19, 2005
  • Language: English
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Description

Welcome to the virtual math club and mathematical discussion center. It is the place where everybody who loves math, curious about math or has mathematical problem can join easily and consult each other. This group is specially formed for the Bangladesh Mathematical Olympiad participants, BdMO members, MOVers, Teachers and all other math lovers of Bangladesh. We hope it will take a good attempt to solve our mathematical problem.
Though it is a club, another target is to build a math group, a math family where the members can exchange their feelings also. We hope this group will not only build a math club but also make a family, math family.
Any one can join this group. But a request, before joining please be introduced to the existing members by giving a little description about you through your first mail to the group.

Most Recent Messages

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Re: Intersection of Cone with Plane [Nice Website of Jon]
You have created a wonderful website, Jon. Traveling across your land of reation. :)   Regards,   S. M. Mamun Ar Rashid ... From: Jon <jon8338@...>
Posted - Sat Nov 7, 2009 2:53 pm
S. M. Mamun Ar Rashid
mamun305
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Intersection of Cone with Plane
I have worked out the general case for the intersection of any plane with any cone. This has already been discovered, but it is not proprietary information.
Posted - Sat Nov 7, 2009 1:22 am
Jon
jongiff2000
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Re: Another Coprime Arithmetic
Thanks Avik. Now I understood the proof. ________________________________ From: avik roy <avik_3.1416@...> To: math_club@yahoogroups.com Sent: Mon,
Posted - Mon Nov 2, 2009 10:57 am
Mirza Sabbir Hossain ...
mirzasabbirh...
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Re: Coprime Arithmetic
I think the proof is ok. The problem is "for odd a and b, if a-b=2^n, a and b are coprime" The proof shows that assuming any common divisor d for a and b, we
Posted - Mon Nov 2, 2009 10:33 am
avik roy
avik_3.1416
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Re: Another Coprime Arithmetic
The same proof is valid in this case.... for any number d to divide a and b, it has to divide p, hence d=1 or p, but a,b<p thus d can't be p and thus d has to
Posted - Mon Nov 2, 2009 10:07 am
avik roy
avik_3.1416
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Message History

Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec
2009 78 32 11 12 29 14 34 25 112 79 12
2008 43 45 133 85 67 38 43 77 43 33 16 39
2007 148 307 143 153 65 63 103 201 60 48 33 89
2006 205 113 192 83 104 100 82 161 118 330 141 139
2005 55 116 34 22 57 69 26 15 47 440
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