Group Information- Members: 723
- Category: Mathematics
- Founded: Mar 19, 2005
- Language: English
|
Visit the
Groups blog for the latest Yahoo! Groups information
Description
Welcome to the virtual math club and mathematical discussion center. It is the place where everybody who loves math, curious about math or has mathematical problem can join easily and consult each other. This group is specially formed for the Bangladesh Mathematical Olympiad participants, BdMO members, MOVers, Teachers and all other math lovers of Bangladesh. We hope it will take a good attempt to solve our mathematical problem.
Though it is a club, another target is to build a math group, a math family where the members can exchange their feelings also. We hope this group will not only build a math club but also make a family, math family.
Any one can join this group. But a request, before joining please be introduced to the existing members by giving a little description about you through your first mail to the group.
|
|
Posted - Sat Nov 7, 2009 2:53 pm
|
S. M. Mamun Ar Rashid
mamun305
 Offline
 Send Email
|
Intersection of Cone with Plane
I have worked out the general case for the intersection of any plane with any cone. This has already been discovered, but it is not proprietary information.
Posted - Sat Nov 7, 2009 1:22 am
|
Jon
jongiff2000
Offline
Send Email
|
Re: Another Coprime Arithmetic
Thanks Avik. Now I understood the proof. ________________________________ From: avik roy <avik_3.1416@...> To: math_club@yahoogroups.com Sent: Mon,
Posted - Mon Nov 2, 2009 10:57 am
|
Mirza Sabbir Hossain ...
mirzasabbirh...
Offline
Send Email
|
Re: Coprime Arithmetic
I think the proof is ok. The problem is "for odd a and b, if a-b=2^n, a and b are coprime" The proof shows that assuming any common divisor d for a and b, we
Posted - Mon Nov 2, 2009 10:33 am
|
avik roy
avik_3.1416
Offline
Send Email
|
Re: Another Coprime Arithmetic
The same proof is valid in this case.... for any number d to divide a and b, it has to divide p, hence d=1 or p, but a,b<p thus d can't be p and thus d has to
Posted - Mon Nov 2, 2009 10:07 am
|
avik roy
avik_3.1416
Offline
Send Email
|
Add math_club to your personalized My Yahoo! page   What's This?
|
Message History
Group Email Addresses
| Post message: |
math_club@yahoogroups.com |
| Subscribe: |
math_club-subscribe@yahoogroups.com |
| Unsubscribe: |
math_club-unsubscribe@yahoogroups.com |
| List owner: |
math_club-owner@yahoogroups.com |
|
