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Messages 11052 - 11081 of 13927   Oldest  |  < Older  |  Newer >  |  Newest
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11052
In a message dated 10/31/2005 8:52:59 PM Central Standard Time, ... This assumes that Ouija boards are so stupid they don't recognize this kind of logical...
MorphemeAddict@...
lojbaner
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Nov 1, 2005
12:35 pm
11053
referrelative="t" o:spt="75" coordsize="21600,21600"> I have 5 trig problems that I cannot solve, Can anyone show me tips or clues on how to solve them? ...
vcamt1510
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Nov 5, 2005
10:24 pm
11054
I have a couple of trig problems that I don't know how to solve. Can you provide some clues or tips on how to solve them . Thankyou 1a) Evaluate using the...
vcamt1510
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Nov 6, 2005
5:22 pm
11055
I was wondering if the oblique asymptote of this graph is y=x 1) (x+4)^2(x+3)^2(x^2-3x+2) divided by / (x-3)^2(x^2+5x+6)(x-2) In addition is there a hole at...
vcamt1510
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Nov 6, 2005
8:05 pm
11056
Here's a nice website that describes: Vertical asymptotes Oblique asymptotes (slanted) Horizontal asymptotes C:\Documents and Settings\Emachine\Local...
brianejensen
brianedwardj...
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Nov 7, 2005
12:32 am
11057
All you have to do is some simple algebra 1a) sin(75) = sin(45+30) = sin45.cos30 + sin30.cos45 2a) ... Yahoo! FareChase - Search multiple travel sites in one...
V i j a y
v0121223
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Nov 7, 2005
4:13 am
11058
Guys, what do you think about this St.Petersburg Paradox....I would like to have some discussion on this. ... Yahoo! FareChase - Search multiple travel sites...
V i j a y
v0121223
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Nov 7, 2005
4:19 am
11059
In a message dated 11/6/2005 10:19:50 PM Central Standard Time, ... Uh, what paradox would that be? stevo [Non-text portions of this message have been removed]...
MorphemeAddict@...
lojbaner
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Nov 7, 2005
7:38 am
11060
... like to have some discussion on this. ... I bet $50....
cooperpuzzles
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Nov 7, 2005
8:26 am
11061
Here's one I found while surfing the web. Which fits best - a square peg in a round hole, or a round peg in a square hole? Regards, John...
cooperpuzzles
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Nov 7, 2005
9:05 am
11062
In a message dated 11/6/2005 2:05:47 PM Central Standard Time, ... A9 = x = -8..+8 B9 =(A9+4)^2*(A9+3)^2*(A9^2-3*A9+2) C9 =(A9-3)^2*(A9^2+5*A9+6)*(A9-2) D9...
MorphemeAddict@...
lojbaner
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Nov 7, 2005
12:01 pm
11063
I cna't say taht I'm eternily cencivnod taht tihs wkors. Ppahers in cextont, but not on a word-for-word biass. ... rdanieg. The ... Cmabrigde ... are, the ... ...
clooneman
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Nov 7, 2005
2:03 pm
11064
y= (x+4)^2(x+3)^2(x^2-3x+2) divided by / (x-3)^2(x^2+5x+6)(x-2) Let's say x is a billion. Then the single digit numbers become negligible. so we have: y=...
brianejensen
brianedwardj...
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Nov 7, 2005
5:30 pm
11065
... 2Pi - 6 ''Brownie, you're doing a heckuva job.'' Cino...
cino hilliard
hillcino368
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Nov 7, 2005
7:39 pm
11066
It should be should be easier to hammer a slightly oversize square peg in to a round hole, rather than vice-versa, as you would only be 'shavin...
Peter Otzen
bogaduck
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Nov 8, 2005
2:41 am
11067
In a message dated 11/7/2005 3:06:07 AM Central Standard Time, ... To me it's just a matter of which shape fills the other shape more completely. So it's a...
MorphemeAddict@...
lojbaner
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Nov 8, 2005
1:18 pm
11068
... This had been my first thought as well, but Peter's answer gives a mechanical rather than geometric interpretation, which highlights the omission in the...
adh_math
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Nov 8, 2005
1:44 pm
11069
... Ah ah! I think we should start on a computer program that translates properly spelled text into this jibberish. Artificial intelligence? We will of course...
cino hilliard
hillcino368
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Nov 8, 2005
3:42 pm
11070
... Let the measure of "fit" be the ratio leftover area of inscribed peg cross-section R= ----------------------------------------------------------- area of...
cino hilliard
hillcino368
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Nov 8, 2005
4:52 pm
11071
Using numbers 0 to 9 only once, make this a true subtraction problem: "-,---" minus "---" equals "---". Also, you cannot use "0" in the thousands column. How...
garcdan
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Nov 8, 2005
11:25 pm
11072
... Is there an implied trick that you can use 0 in the hundreds column of the 'three figure numbers'? Peter...
Peter Otzen
bogaduck
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Nov 9, 2005
12:17 am
11073
With square pergs and round holes etc, perhaps it is time re revisit the semingly meaningless, but actually serious problem of: Why are man-hole covers round? ...
Peter Otzen
bogaduck
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Nov 9, 2005
12:18 am
11074
A round manhole cover can NEVER fall into the manhole. The longest dimension (diameter) of the cover is slightly larger than the longest dimension (diameter)...
dwittman@...
derekwittman
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Nov 9, 2005
2:08 am
11075
How about a 3 pointed star? I think that would work too. In general though, I think a circle is the only convex shape that will work....
slim_the_dude
Offline
Nov 9, 2005
4:34 am
11076
There you go. AMA ... From: warazaki@... <warazaki@...> Date: Nov 9, 2005 12:36 PM Subject: [iic664_july2005] Fwd: [MATH for FUN] why are...
amali1999
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Nov 9, 2005
4:47 am
11077
... An equilateral triangle of side s would work but would be dangerous since a vertex would extend ~ sqrt(s^2-s^2/4) = sqrt(3)s/2 units. Eg., a side of 2 feet...
cino hilliard
hillcino368
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Nov 9, 2005
7:45 am
11078
What do you mean by a 3-pointed star? Some sort of triangle with 'indentations' at the center points of the side? I'm not seeing how that would prevent it...
dwittman@...
derekwittman
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Nov 9, 2005
12:57 pm
11079
I believe a hexagonal cover, when edges are lined up with 2 distant points (across the 'diameter') will still fall in. ... From: amali1999...
dwittman@...
derekwittman
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Nov 9, 2005
12:59 pm
11080
A polygon with an infinite number of sides... as the number of sides increases, the figure looks more and more like a circle to me... Anyone else? (just saw...
dwittman@...
derekwittman
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Nov 9, 2005
1:01 pm
11081
... Yes ... Actually the hexagon "tube" is what holds the honey and the tessellation of hexagons in the hive provides the greatest volume per unit expenditure...
cino hilliard
hillcino368
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Nov 9, 2005
4:42 pm
Messages 11052 - 11081 of 13927   Oldest  |  < Older  |  Newer >  |  Newest
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