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Messages 12645 - 12675 of 13927   Oldest  |  < Older  |  Newer >  |  Newest
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12645
In coordinate geometry, is there a formula for the circumcentre of a triangle like there is for the centroid...... Suppose, If (x1,y1) , (x2,y2) and (x3,y3)...
Shail Shah
unique_loneleo
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Apr 7, 2007
6:09 am
12646
Consider 2N points arranged in a rectangular grid of two rows with N points per row. Adjacent points can be connected by drawing lines between them...
video_ranger
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Apr 8, 2007
6:52 pm
12647
... Some things to consider: 1. What's the degree of P? 2. How can you determine the sum of the roots of a polynomial without *knowing* the roots?...
adh_math
Offline
Apr 8, 2007
11:42 pm
12648
... Do you know a geometric construction of the circumcenter? If so, you can probably turn the construction into a formula....
adh_math
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Apr 8, 2007
11:44 pm
12649
... Bother...solution fell apart as I was typing....
adh_math
Offline
Apr 9, 2007
12:13 am
12650
How? Please justify wat u mean by "turning a construction into a formula."..I' m a 10th grade student in India . Thank you. ... [Non-text portions of this...
shail shah
unique_loneleo
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Apr 9, 2007
6:35 am
12651
Check this out http://en.wikipedia.org/wiki/Circumcenter...
kkjb1999
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Apr 9, 2007
7:54 am
12653
... I found a recursion generating the correct number of trees for N <= 5 (modulo correctness of my count for these cases), and have a putative proof of...
adh_math
Offline
Apr 9, 2007
2:22 pm
12654
... <mathforfun%40yahoogroups.com>, "Shail ... If you decide to derive the formula yourself rather than looking at wikipedia, start with a geometric...
adh_math
Offline
Apr 9, 2007
2:38 pm
12655
... with N ... of ... by a ... of ... (2) = ... 5 ... putative ... verbally ... to ... (15))/2. ... You found the correct recursion formula: T(n) =...
video_ranger
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Apr 10, 2007
2:30 pm
12656
... Yep. It would be interesting to write a "minimally complex" algorithm to solve this problem. Upon getting the recursive formula, that's what I thought...
Julien Santini
julien_santini
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Apr 10, 2007
3:12 pm
12657
... Even the recursion was a bit of a mess to work out. :) It's easy (with diagrams:) to see that T(n) = 3T(n-1) plus the number of (a certain set of) graphs...
adh_math
Offline
Apr 10, 2007
3:14 pm
12658
... The following procedure seems to generate all connected spanning trees: Start with the "complete" graph on 2(n+1) vertices (consisting of n squares) and...
adh_math
Offline
Apr 10, 2007
5:54 pm
12659
... lines ... ways ... <= ... how ... term ... was ... Using methods explained here: http://mathworld.wolfram.com/LinearRecurrenceEquation.html T(n) = ...
cooperpuzzles
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Apr 11, 2007
10:58 am
12660
... <video_ranger@> ... connected ... number ... and T ... N ... 209. ... This expression is in the form: T(n) = A*r^(n-1) + B*s^(n-1) The method briefly:...
cooperpuzzles
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Apr 11, 2007
6:07 pm
12661
From: Shail Shah <shail91@...> Date: 2007/04/07 Sat AM 01:09:12 CDT To: mathforfun@yahoogroups.com Subject: [MATH for FUN] Circumcentre In coordinate...
ramsey2879@...
ramsey2879
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Apr 11, 2007
10:12 pm
12662
Hi, Today I was watching the Science Channel about Saturn. It was mentioned that the speed of light was 300,000 kilometers/sec. Now in miles it is 186,000 ...
cino hilliard
hillcino368
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Apr 15, 2007
4:44 am
12663
... mentioned that ... Actually 93 million [miles] is a little more than 186, 000 [miles per second] which would explain why light takes about 4 minutes,...
Peter Otzen
bogaduck
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Apr 15, 2007
10:45 am
12664
... mentioned that ... 186,000 ... we have a ... (5280*12*2.54) ... Given that the distances are, I believe, stated as 300 thousand km and 186 thousand miles...
Peter Otzen
bogaduck
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Apr 15, 2007
10:50 am
12665
In a message dated 4/14/2007 11:44:38 PM Central Daylight Time, ... Not bad, but both 186,000 mi/s and 300,000 km/s are approximate already. I just remember...
MorphemeAddict@...
lojbaner
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Apr 15, 2007
11:28 am
12666
... Shouldn't that be about 8 minutes, rather than 4?...
jwwarrenva
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Apr 15, 2007
12:53 pm
12667
In a message dated 4/15/2007 5:45:39 AM Central Daylight Time, ... I don't understand how you got 4 minutes. 93,000,000 mi/(186,000 mi/s) = 500 s. 500 s/(60...
MorphemeAddict@...
lojbaner
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Apr 15, 2007
11:29 pm
12668
No, it takes about 8 minutes, not 4. Re-do your math. Tarcisio ____________ Actually 93 million [miles] is a little more than 186, 000 [miles per second] which...
TCG
tarcisiogoes
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Apr 16, 2007
2:37 am
12669
Hi, Consider the following ratios. 60499999499/4900500000000 13308887/98010000 1209493/49005000 Try them on windows calculator view scientific or better on a...
cino hilliard
hillcino368
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Apr 16, 2007
7:32 am
12670
... It's simple - use late night memory rather than arithmetic! Peter...
Peter Otzen
bogaduck
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Apr 16, 2007
12:32 pm
12671
... multiprecision ... then do it ... Very good! With a simple Excel sheet I see they go on forever mod 100. After 96 the second and third switch, odds to...
cooperpuzzles
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Apr 17, 2007
7:36 am
12672
... 60499999499/4900500000000. = 0.012345678910111213141516171819202122232425262728293031323334353637383940 ...
cino hilliard
hillcino368
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Apr 18, 2007
6:57 am
12673
... 96 ... 0.01234567891011121314151617181920212223242526272829303132333435363738 3940 ... ...
cooperpuzzles
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Apr 18, 2007
1:11 pm
12674
adh_math, jason1990 and I were writing a paper when they both decided to bail on me and I'd like to continue (my) research. It's in the field of combinatorics...
bqllpd
Offline
Apr 19, 2007
12:03 am
12675
... Here are some convergents for primes. There does not seem to be any spectacular, compact ratios giving many primes in the outout. 0/1, 1/4, 4/17, 33/140, ...
cino hilliard
hillcino368
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Apr 19, 2007
1:09 pm
Messages 12645 - 12675 of 13927   Oldest  |  < Older  |  Newer >  |  Newest
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