... do i explain that to my friend new to induction? ... I think the error came with the simple statement Let us assume the proposition P(k) that k horses are...
... assume the proposition P(k) that k horses are the same colour and use this to imply that k+1 horses are the same colour. Given the set of k+1 horses, we...
it's a simple example the error is the proof of p(2) by p(1) for k=2 the induction says one of them is for example white but its not necessary for the ither to...
... with respect to dx from b to ... using the the lesbesgue ... an element of I such ... than 0), but i'm stuck. ... let f(c) = d >o from continuity for every...
... similar ... An operator is linear if each output term a_n is given by a linear combination of any of the a's in the original sequence. E^j a_i = a_ (i+j)...
Given n is a positive integer. Verify by substitution the following: C(2n,n+1)=C(2n,n)=1/2 *C(2n+2,n+1) Also need a combinatorial proof. Please help me ....
... Did you really mean to have two "=" signs in the above, and is the last term (1/2) multiplied by .... or do you mean 1 divided by (2 times ....)...
I am sorry for the incorrect symbols This is the correct one C(2n,n+1)+C(2n,n)=0.5 *C(2n+2,n+1) I also need a combinatorial proof( explanation in words to...
... assume the proposition P(k) that k horses are the same colour and use this to imply that k+1 horses are the same colour. Given the set of k+1 horses, we...
C(n,r) = n!/(n-r)!/r! for n=k, (2k)!/((k-1)!/(k+1)! + (2k)!/k!^2 since (k-1) = k!/k and (k+1)! = (k+1)*k! we have (2k+1)(2k)!/(k+1)(k!)^2. since (k+1)! =...
A formal proof has already been given (by cino). Here's a combinatoric derivation (there are probably others) --> How many ways are there of dividing a gym...
Please explain this for me: In the first case there are C(2n,n+1) ways of selecting their opponent team. In the second case there are C(2n,n) ways of selecting...
Please help me formulate the maze problem using the Graph theory . I have uploaded the description of the problem in the Files section with name "maze problem...
... Don't forget that C[2n,n+1] and C[2n,n-1] have the same value (since (n+1) + (n-1) = 2n ) So we could have said C[2n,n-1] ways to choose the rest of A's...
Demonstrate your intellect and compete for an interview. Extraordinary people achieve extraordinary things. Mapleridge capital is looking for extraordinary...
... I ... with ... Am ... Hard to say exactly what's expected but I would be inclined to partition the space into rectangular shaped rooms by adding vertical ...
... disjoint ... the ... I've been having a bad case of insomnia lately, so early this morning I decided to construct the centroid of 100 points using this...
Hello, This email message is a notification to let you know that a file has been uploaded to the Files area of the mathforfun group. File : /scans.pdf ...
mathforfun@yahoogroup...
Oct 12, 2008 2:52 am
13557
How many ways can a size k + 1 subset with maximum element m + 1 can be created from the given set S={1,2,3,.....,n+1} Is it m choose k ways? Please explain...
... this. ... That sounds right to me. if the highest element is m+1, then the other k elements must be from {1,2,3,....m} So you're choosing k elements...
Listen to this video from CNN. 2,100 for 2,100 In Lake County, IN the Registrar of Voters started examining voter registrations turned in by ACORN. Of the...
... I assume this is a paid political announcement. If you live in a country where it is not necessary for everyone to vote, you will never find out what ALL...
http://ap.google.com/article/ALeqM5hwFew2vQ69x6-RFPFXQPyPFCceGgD93RQIM81 http://www.komonews.com/news/health/31166339.html Popular Bee Gees song could...
Suppose there were an election between two candidates, with say approximately a million people expected to vote. A poll of 100 voters selected at random is...
... The equivalent problem is flipping 100 coins with a vote for one being heads and a vote for the other being tails. If a sample of 100 voters gave a 50 50...
Suppose there were an election between two candidates, with say ... The equivalent problem is flipping 100 coins with a vote for one being heads and a vote for...
Having problems with message search?
Fill out this form to ensure your group is one of the first to be migrated to the new message search system.
