I think you need to carefully analyze your “remove one horse, add another” logic. In detail, what you are saying is “Start with k-1 horses – they’re...
Please anyone feel free to respond to this message. This is a forward of an email that I sent to Andy Wuensche. Thank you for your time. I'm sorry to...
yes. the site name http://www.discoveryschool.com ________________________________ From: ani_choudhury <ani_choudhury@...> To: mathforfun@yahoogroups.com...
Khushbu , Zelkomi thanks for the info. Rgds AC ... topic ... Calendar ... Foods ... format to Traditional ... to http://in..promos.yahoo.com/groups/citygroups/...
... do i explain that to my friend new to induction?"< Well, step by step: 1) iduction bazis: It is obvious that one horse is the same colour. 2) induction...
... do i explain that to my friend new to induction? The problem with this argument as mehrdad noted is that the same argument that will get you from P(k) to...
Thank you for your reply, but I am perfectly aware of everything Wolfram has already written. None of the links you provided even begin to answer the three...
GIVEN THE FOLLOWING SCENARIO; A series of six numbers exist ( a sequence) Each number in the series may be from 1 to 2 digits Each number will be one of...
This is something I found by accident last night when messing with my HP calc. We all know a^2+b^2=c^2 has positive integer solutions for a, b and c. If you...
In a message dated 2009-02-19 23:17:07 Eastern Standard Time, ... I don't see where you get 3^1+2^2=5^2, since 3^1+2^2=5^1. ... The latter two examples are...
You might want to try some triangles and triples that aren't similar to the 3:4:5 triangle before you get to excited - it doesn't seem to work for 5-12-13. Ed ...
Somebody told me that the equation: a^b = b^a with a>b has multiple solutions, but I cant figure it out!! Could you help me? Thanks a lot!! Heriberto...
... Almost completely answer in http://www.komal.hu (see english version) Article: On commutative and associative powers Author Lajos Loczi Shortely:...
... TO prove there are multiple solutions, let me just arbitrarily pick two candidates for a: 5 and 6 Case 1. a=5 for b=1, we have a^b = 5 > 1 = b^a for...
... my ... a, ... sum of ... of ... If I'm understanding you correctly, would this be a couterexample? 12 + 5 = 13 prime factors of 12 are 2 and 3 prime...
... the ... Me too. Nevertheless, the idea is interesting. I took the liberty of writing a program in Pari to examine these numbers. Some output is below. You...
Quick summary of the posts to which I am responding: The first post posited that in integral Pythagorean triples, the sum of the prime factors of the legs...
PhilM4@...
Feb 21, 2009 1:30 am
13647
If u use mathematica to simplify the equation you get an very wierd answer. Use GraphEq and plot x^y=y^x and you'll see the multiple solns ... Connect with...
Indeed, let the triple a,b,c have prime divisors without multiplicity, a1,a2..al,b1,b2..bm,c1,c2..cn. Now in Jason's query, a^2+b^2=c^2 breaks down to ...
*A two digit number is 7 times the sum of its digits. If the digits are interchanged, the resultant becomes 27 less than the original number. Find the original...
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