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Messages 7703 - 7732 of 13927   Oldest  |  < Older  |  Newer >  |  Newest
Messages: Simplify | Expand   (Group by Topic) Author Sort by Date ^
7703
... doing ... c(n,k) is n choose k. p is a positive integer. I did generate a family of equations for each value of n > 0. I guess you can say I cheated...
bqllpd
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May 1, 2004
8:53 pm
7704
... in i ... the ... 97976320, ... 438220881920,... ... the ... above, ... guess c ... consecutively? ... I ... I ... calculator ... for ... honestly, ... ...
jason1990
Offline
May 1, 2004
9:31 pm
7705
... p. ... p is an arbitrary positive integer, because when n>m, then J_h(a_i) = 0 for all (n+p)>m. "J_h(a_i)" is the J-transform for brevity. I solved for h...
bqllpd
Offline
May 2, 2004
1:30 am
7706
... Let me rephrase the second part The summation does depend on p. When the J-transform = 0 for values of n>m and (n+p)>m, then there exists a root for the...
bqllpd
Offline
May 2, 2004
1:36 am
7707
The correction should be Sum{(h^(n+p-i)*c(n,i)*(a_i, i=0 to n+p}...
bqllpd
Offline
May 2, 2004
1:39 am
7708
Sum{(h^(n+p-i)*c(n+p,i)*(a_i), i=0 to n+p} Sorry. I swear this is it. I'm not a good proof reader at all......
bqllpd
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May 2, 2004
1:41 am
7709
I'm sorry, bq. I'm totally lost at this point. I could sit down and try to work it out for myself, but I think that defeats the purpose, given that this is...
jason1990
Offline
May 2, 2004
3:17 am
7710
Looking again at this message I wrote, it seems a bit curt. Sorry. Just so you know, I *am* interested in figuring out what you're doing here, but I think it's...
jason1990
Offline
May 2, 2004
5:10 am
7711
A cube has edges of length 10 inches. The square bases of six identical right pyramids also have side lengths 10 inches and each base is glued to a face of the...
ray chan
yowieray
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May 2, 2004
7:30 am
7712
... hi y=4x^2-8x=x(4x-8) 1.x=0 2.4x-8=0,4x=8,x=2 BYE AMIR faezeh sanaei <faezehsanaei@...> wrote: hi i wonder if enyone could do this for me ? ...
faezeh sanaei
faezehsanaei
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May 2, 2004
4:53 pm
7713
Sorry about not being clear with this theory, but here's one last thing I'll mention about the J-transform. I found this by accident last night. Suppose h is...
bqllpd
Offline
May 3, 2004
12:28 am
7714
This is what I managed to come up with: Let the cube be centered at the origin. Its vertecies are at A (5,5,5), B(5,5,-5), C(5,-5,5), D(5,-5,-5), E(-5,5,5),...
brianscsmith
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May 3, 2004
2:06 pm
7715
Is the derivative w.r.t. x of y=2x^4 + 28x^3 +150x^2 + 356x + 315 equal to y=2x^3 + 21x^2 +75x + 89? One part of my calculator says yes and another part no....
bqllpd
Offline
May 4, 2004
1:58 am
7716
No! y'= 8x³ + 84x² + 300x + 356 Carlos ... From: "bqllpd" <no_reply@yahoogroups.com>...
Carlos Assale
c_assalebr
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May 4, 2004
2:07 am
7717
So supposing the last post is correct, I should rewrite that (d(Sum{x^(n+1-i)*C(n+1,i)*a_i, i=0 to n+1})/dx)/n = Sum{(x^(n-i)*C(n,i)*a_i, i=0 to n}, n > 0 So...
bqllpd
Offline
May 4, 2004
2:46 am
7718
But you know that very well....what's the catch???? Carlos...
Carlos Assale
c_assalebr
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May 4, 2004
2:50 am
7719
hi, i just wonder if this question is answered b4. let p,q be 2 primes. find the smallest a in terms of p and q so that pq+a is prime. thx...
stclaus_imi
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May 4, 2004
4:23 am
7720
No, I think you're right. I got 50.5% the first time I thought about it, but then got 49.5. I'll give it one more bash... P(success) = P(he's first picked) +...
clooneman
Offline
May 4, 2004
12:50 pm
7721
... %....
clooneman
Offline
May 4, 2004
12:51 pm
7722
hi every one if the 2 opposite apexes of a square are (3,0) and (-4,1)find the other 2 apexes. ____________________________________________________________ ...
faezeh sanaei
faezehsanaei
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May 4, 2004
4:17 pm
7723
Surely your calculator retailer has sold you a alculator gone horribly wrong. Unless I'm VERY much mistaken, dy/dx in this case = 8x³ + 84x² + 300x + 356....
clooneman
Offline
May 4, 2004
5:03 pm
7724
Might I suggest a = 2-pq as an answer? ... that...
clooneman
Offline
May 4, 2004
5:08 pm
7725
In a message dated 2004-05-04 9:37:37 AM Eastern Daylight Time, ... what a relief! when i first looked at this, i thought "that can't be right." it's...
MorphemeAddict@...
lojbaner
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May 4, 2004
5:19 pm
7726
Doesn't make a lot of sense to me, but that's just me. ... information ... RHS ... one?...
clooneman
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May 4, 2004
5:21 pm
7727
... I would assume that a>0 is intended. Problems involving primality usually require positive integers....
brianscsmith
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May 4, 2004
5:50 pm
7728
For one thing, I don't use drugs. Two, the HP49G is one of the best calculators there is. What my calculator did was plot y=2x^4 + 28x^3 + 150x^2 + 315 Then...
bqllpd
Offline
May 4, 2004
8:56 pm
7729
The smallest values for p,q,a is p=2, q=3, a=1, pq+a = 7 prime ... that...
bqllpd
Offline
May 4, 2004
9:00 pm
7730
I've just done the derivation in my HP48G and the answer was right. Carlos ... For one thing, I don't use drugs. Two, the HP49G is one of the best calculators...
Carlos Assale
c_assalebr
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May 4, 2004
9:17 pm
7731
Now try graphing the first equation as a function and after it plots, press FNC, then NXT then F' and see that if it plots the derivative correctly. ... it...
bqllpd
Offline
May 4, 2004
9:20 pm
7732
The derivative plotted was: 2*(4*x^3)+28*(3*x^2)+150*(2*x)+356 wich is equal to 8x³ + 84x² + 300x + 356 as expected.... Had you tried it again???? Tried to...
Carlos Assale
c_assalebr
Offline Send Email
May 4, 2004
10:04 pm
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