Ok. It will really help. Thanks so much, Arristeo. ... lighter side, bec. if i do, I wouldn't bother myself posting the question in the first place, right? i'm...
... Right, my turn! If x+1 is a factor of 2x^3-7x^2+bx+c, then x+1 = 0, and therefore x = -1, is a solution for 2x^3-7x^2+bx+c = 0. 2(-1)³-7(-1)²+(-1)b+c = 0...
wat is the value of 1+ 1/2+1/3+1/4+1/5+......upto infinity There are 15 messages in this issue. Topics in this digest: 1. Re: Digest Number 758 From:...
... 1+1/2+1/3+....diverges. In other words, given any n, howsoever large, you can always find some k such that 1+ 1/2 + 1/3 + ... + 1/k is larger than n. An...
Members are urged, when replying to digests, not to include the entire digest as the end of the message. Rather, include just that part of the digest that is...
In a message dated 2004-09-30 2:50:09 PM Eastern Daylight Time, ... Emily, At least 40 years ago the rule was: if a number ends in 1, 2, 3, or 4, then round...
... Don't know of any quick proofs, but here are four sketches, in roughly ascending order of technical prerequisites: 1. Expand arcsin x as a power series...
In a message dated 2004-10-01 3:31:03 AM Eastern Daylight Time, ... I think this whole idea of 'rounding bias', while true if 0 is ignored, should itself be...
It's worth noting that this is the Zeta function, famous in song and story, evaluated at 2. Enter Zeta[2] into Mathematica and it will respond with pi²/6....
Hi, For (x,y,p) = 1, p prime Without using Fermat's Little Theorem (flt) or Euler Phi. Prove: Theorem 1. x^(p-1) - y^(p-1) is divisible by p if p is prime. It...
In a message dated 2004-10-02 4:28:06 AM Eastern Daylight Time, ... Anand, Could you please use proper spelling? Capitalization would be nice too. stevo ...
the symmetric difference of two sets A and B, denoted by A(delta)B is defined as the set of those elements in either A or B, but not both A and B. a) is the...
... On the subject, what does Mathematica say if you enter Zeta[3]? Does it return a numerical value, or leave things as "Zeta[3]", or...? ... I thought...
... Hi, Sorry if you got the first message garbled. I think it is a YAHOO send back to hotmail problem. It came out ok in the yahoo messages posted so I am...
I'm studying a bit of algebra and I have a problem. If we define a module as a set s.t there exists an operation + s.t. (M,+) is a commutative group and there...
Nisoli Isaia
orkolorko@...
Oct 2, 2004 7:26 pm
8838
in order to prove it, u first must setup the MAclaurin series for e^x. u continously take the derivative of e^x and evaluate it at x=0. then u divide by n!. So...
Annika Saunders <waterlillysas@...> wrote: ok thanks alot Alyssa when is chat normally? ... From: Alyssa To: mathforfun@yahoogroups.com Sent: Thursday,...
... Quick summary: The issue seems to boil down to two different definitions of "module". :) ... This is the usual definition of a "left R-module over M",...
... <hillcino368@h...> ... Perhaps I'm missing something, but since the result you want to prove *becomes* Fermat's little theorem when y=1, it's not wholly...
... actually, Julien's proof doesn't make a lick of sense to me. The question was to prove that the sum(1/n!)=e. I did the correct proof by using the Maclaurin...
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