What I meant was:

Pfgw -f -q((2^^4200+13)^^30-1)/(2^^4200+12)

((2^4200+13)^30-1)/(2^4200+12) has factors: 2

Lélio

-----Mensagem original-----
De: openpfgw@yahoogroups.com [mailto:openpfgw@yahoogroups.com] Em nome de
Phil Carmody
Enviada em: domingo, 26 de março de 2006 08:53
Para: openpfgw@yahoogroups.com
Assunto: Re: [openpfgw] pfgw and phi(x,y)

--- Lélio Ribeiro de Paula <leliorp@...> wrote:
> How does pfgw evaluates phi(x,y)?

By multiplication and division of Phi(d,y) terms for d|x.

> I found this number to be a PrP, but can't write it in a more
> palatable way:
>
> phi(30,2^4200+13) is Fermat and Lucas PRP! (72.3111s+0.0435s)

There is no more palatable way. It's both succinct and clear,
and you can't ask for more than that.

Phil

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