... That rule is incomplete (wrong). I can rewrite it like this: Given SatisList and restrictions on S and T; P4 Rule =...
Craig Carey
research@...
Sep 1, 2001 8:50 pm
144
... Example 1: 10 AB : Total = 48; 48/4 = 12; 48/3 = 16 15 B : Candidates under the "1/4" quota are: {A,D} 23 C 0 D Stage 1: eliminate...
Craig Carey
research@...
Sep 18, 2001 4:38 am
145
Dear Craig, ... Situation 1: 7:A>B>C>D 3:D>A>B>C 15:B>A>C>D 23:C>A>B>D The quota is 12. D is eliminated since (2*d=6 < 22=a+b), (2*d=6 < 30=a+c) and (2*d=6 <...
Markus Schulze
markus.schulze@...
Sep 18, 2001 4:42 pm
146
A 4 candidate solution was derived by me and this is a solution to the 1 winner 4 candidate problem subject to P1,P2, and P3 being held, and the papers being...
Craig Carey
research@...
Sep 21, 2001 8:30 pm
147
To: politicians-and-polytopes@yahoogroups.com Subject: 1/4 quota lost(?); P4 tests S92 method (1328 lines) GMT 24 Sept 2001 By G. A. Craig Carey The problem...
Craig Carey
research@...
Sep 25, 2001 11:58 am
148
... Continued Below is APPENDIX B : DERIVATION OF THE 'S92' METHOD FOR PAPERS {(AB),(B),(C),(D)} ...
Craig Carey
research@...
Sep 25, 2001 12:15 pm
149
... aW = (b<a)(c<a)(d<a) bW = (a<b)(c<b+ab)(d<b+ab)(a+c<b+d or a+c<2b)(a+d<b+c or a+d<2b) cW = (a<c)(d<c)(b+ab<c or (b+d<a+c)(2b<a+c)) dW = (a<d)(c<d)(b+ab<d...
Craig Carey
research@...
Sep 29, 2001 6:37 am
152
Free Demo Games A list of some sites to browse to if the aim is to get PC games for Windows NT or Windows 2000. This information might be interesting to...
Craig Carey
research@...
Oct 13, 2001 10:43 pm
153
Porting MAS (of the Heinz Kredel and partly by M Pesch, and of the Computer Algebra Group, University of Passau, Germany), from Modula-2 to Ada 95. This is on...
At 2001\07\31 23:25 +0100 Tuesday, Joe Otten wrote: ... That seems most unpromising and I can't see why it ought not be ignored, It seems to not say _which_ of...
The title is not quite right and it is assuming that truncation resistance holds (or else that monotonicity is read to mean, P1). I today visualised some of...
... Extraordinary. I hope that when you use terms like "one man one vote" in this redefined sense, you make it clear that it is not "one man one vote" in the...
There was an error in my reply and I now correct the sentence by altering the wording from this ... into this: @ So for 1 winner elections, "one man one vote"...
The equal suffrage axiom will be simplified and that geometric description I gave in the last message is derived using symbolic polytope formulae. The...
The Condorcet method considers 2 candidates at a time. The results just posted say that when there is 1 winner, no more than '1 candidate at a time' should be...
P2 was a rule that seemed a bit weak. It said things like: When the candidates are {A,B,C,D,E}, then the set of winners is unaltered by rewriting this paper...
P4, an equation imposing a type of equal suffrage on a preferential method receiving STV-style papers, is strengthened. The "#" "cardinal number of" function...
Date = 8 Mar 2002 I check out the P2 and see if it can be altered. REDLOG was used against IFPP (and AV, see below) and I conclude that the old P2 is as good...
An example showing that the Alternative Vote will act against 24.998125% of an electorate if they were the last to arrive and then cast AV ballot papers that...
Rather than show IFPP differs from STV, here a check is done to see if it disagrees with the "shouldn't count papers twice when transferring" idea that was STV...
Once P4 is checked then it could be used in software that checks STV. Software to add dots. The last P4 formulae had a wrong term which summed the absolute...
This is partly on letting voters use a cluster of votes, all of which are negative whilst still complying with the [one man one vote] idea of keeping papers...
The equations of a new parametric preferential voting method that is truncation resistant and that complies with P2, are presented. Also the strengthening of...
I used the P4 definition that is at http://www.ijs.co.nz/ifpp.htm and got REDLOG to calculate the corruption of different methods. In 1 winner methods, the...
I tested the Alternative Vote to see if it was corrupt for 3 candidate elections. In the recent messages the Alternative Vote failed the P4 equal suffrage...
I coded up two 1 winner 3 candidate Borda methods and I tested them and the result that the REDLOG testing algorithms found was that Borda was corrupt. In the...
More on why candidates running to be a mayor should regard it as a fundamental rule of thumb that in an Alternative Vote election, more than extra 37.5% extra...
I must have lots of messages and keep them short, confesses the person I named Bathycles Zero. ... Mr Mike Ossipoff misspelt his name 79 times between 13...
Date: 19-Apr-2002 Solve the 1 winner 4 candidate preferential voting problem using IFPP axioms (and doing any fixing of the axioms them as needed). This was...
... Indeed there are 4 lobes. Also there are 2 types of lobes: * the 3 through the faces (A)-(B)-(C), (A)-(B)-(D), (A)-(C)-(D); * the lobe that is opposite to...
