The first 101 titanic primes are 10^999+n for the following n:
7, 663, 2121, 2593, 3561, 4717, 5863, 9459, 11239, 14397, 17289, 18919,
19411, 21667, 25561, 26739, 27759, 28047, 28437, 28989, 35031, 41037, 41409,
41451, 43047, 43269, 43383, 50407, 51043, 52507, 55587, 59877, 61971, 62919,
63177, 69229, 70777, 71893, 73203, 73209, 75301, 76447, 76969, 78463, 79923,
82243, 85837, 85971, 90079, 91737, 94281, 94699, 96081, 97807, 102133,
104461, 105219, 121503, 122163, 122833, 122901, 124381, 126691, 129303,
130513, 133767, 136803, 137821, 137997, 140769, 143751, 144771, 145689,
145879, 146293, 151303, 152781, 153943, 155887, 155911, 156589, 158199,
163959, 164719, 165783, 168333, 170889, 171741, 175203, 176311, 177019,
184069, 184623, 184993, 187021, 189829, 195333, 197629, 198379, 201009,
203959.

Prp'ed by PrimeForm/GW and proved by Marcel Martin's Primo.

The product (10^999+7)*...*(10^999+203959) has 1549 characters but can be
written on the short form (10^999+203959)#/(10^999)#. It has 100900 digits.

I invite primeform readers to perhaps mess with Chris' parser by finding a
prime on the form
p = k*420*(10^999+203959)#/(10^999)#-1, for k<10^9.
I recall reading about the Primeform e-group (before my time) but the
biography is currently specific for another 100k prime:
http://primes.utm.edu/bios/page.php?id=339

I have sieved to 10^12 such that p+2, 2p+1 and (p-1)/2 are also unfactored.
This gives a small bonus twin chance and two Sophie Germain chances,
all provable.
This is not the fastest method to search those records but it's a free chance.

Mail me for a PrimeForm ABC file (with the long product) if you want to
participate.
Around 4700 prp tests are expected to find a prime.

101 titanic helpers in pfgw -tc must be some sort of record.
Puzzle: How many titanic primality proofs are at least needed to prove
primality for a number on the form k*(10^999+203959)#/(10^999)#-1?

--
Jens Kruse Andersen