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Messages 8726 - 8755 of 9803   Oldest  |  < Older  |  Newer >  |  Newest
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8726
... It will let through the sieve only those that are likely to be twin or SG. The AND operation is used. The reason being at the point of examination of the...
Paul Underwood
paulunderwooduk
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Aug 3, 2007
2:20 pm
8727
... s/b by-products. Let's hope TPS/PG can swallow their pride and think again about their n=500000 singly-sieved twin attempt! I suggest they switched to a...
Paul Underwood
paulunderwooduk
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Aug 3, 2007
2:32 pm
8728
Hi All, After 6 months of searching for a CPAP4 this morning I thought I had one. Note the below can be reproduced (by me at least) using the official release...
Ken Davis
kradenken
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Aug 5, 2007
7:36 am
8729
... I have no previous experience with the JF format and have not seen it documented. I don't know how to fix it but will just observe what goes wrong using...
Jens Kruse Andersen
jkand71
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Aug 5, 2007
1:04 pm
8730
I have started looking into the cpap format (the JF CPAP-?? format) file processing. What is happening, is that "internally", the program (once it finds a AP...
jim_fougeron
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Aug 6, 2007
6:00 pm
8731
... I guess there could also be AP's which were falsely found to not be CPAP, so Ken should test any reported AP by other means. -- Jens Kruse Andersen...
Jens Kruse Andersen
jkand71
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Aug 6, 2007
8:51 pm
8732
No, that situation could not happen. If a number was tested and found to be "not-cpap", then it means that one of the numbers in the middle was found to be...
jim_fougeron
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Aug 6, 2007
9:33 pm
8733
Hi Jim, Having thought about it over the lt couple of days I had come to the same conclusion. The prp testing is fine and the original sieving wasn't by pfgw. ...
Ken Davis
kradenken
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Aug 6, 2007
10:21 pm
8734
In 2002 Jack Brennen asked in ... This is now answered at the new record page "Largest Consecutive Factorizations" at ...
Jens Kruse Andersen
jkand71
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Aug 7, 2007
4:00 am
8735
... Call me impressed. :)...
Jack Brennen
jbrennen
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Aug 7, 2007
5:07 am
8736
... means n<=7. How about the largest 8 consecutive integers with known factorization? It is interesting to know the largest example for the least n which ...
jarek372000
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Aug 7, 2007
8:30 pm
8737
... Wow! Congrats to Jens for 5 years work :-) ... whereas sane people know that primes are completely factorized. Best regards from David...
David Broadhurst
djbroadhurst
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Aug 7, 2007
10:51 pm
8738
... That's neat! Given that we can factorize 111 digit numbers, without too much trouble, a 9th-order poly would be even neater. (8th order would do for Sean...
David Broadhurst
djbroadhurst
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Aug 7, 2007
11:01 pm
8739
... I am not aware of any published result for 8 numbers, but I might consider lowering the 500-digit limit if I heard a non-trivial result. Of course, there...
Jens Kruse Andersen
jkand71
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Aug 7, 2007
11:59 pm
8740
... 11 or 12 factorizatons at 125 digits may be reduced to 8, by setting x = -13860*y^2, since then the remainder are trivial, at only half that size: ...
David Broadhurst
djbroadhurst
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Aug 8, 2007
2:21 pm
8741
Congrats to Primegrid and, in particular, to Lasse Mejling Andersen for a 2 megabit Woodall prime: http://primes.utm.edu/top20/page.php?id=7 now being tested ...
David Broadhurst
djbroadhurst
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Aug 9, 2007
3:45 pm
8742
Let x=13860*(10^60+720251) N=x^2*(x^2-23)*(x^2-41)*(x^2-64)/55440 then N+k is factorized for k in [0,7]. Proof: ...
David Broadhurst
djbroadhurst
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Aug 9, 2007
5:06 pm
8743
... Congratulations! That was amazingly fast. I wondered whether anybody would even try 8 for years with the limit set at 500 digits. I guess you are also...
Jens Kruse Andersen
jkand71
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Aug 9, 2007
10:01 pm
8744
... Mainly thanks to Jarek, for his nice quartic Ansatz, which was easy to adapt, to give only 8 c125 factors, in 3 of the 8 targets, instead of the 11 that...
David Broadhurst
djbroadhurst
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Aug 9, 2007
10:54 pm
8745
... Now, at last, some recognition of that obvious fact seems to be dawning in TPS: http://www.mersenneforum.org/showpost.php?p=111996&postcount=180 ... I do...
David Broadhurst
djbroadhurst
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Aug 10, 2007
12:52 am
8746
Nice! That was a very quick response to the challenge. S....
Sean A. Irvine
archmageirvine
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Aug 10, 2007
3:46 am
8747
... Jarek's construction involves this Diophantine problem: Find a pair of positive coprime integers [a,b], with a<b, such that there exist two pairs of...
David Broadhurst
djbroadhurst
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Aug 10, 2007
4:31 pm
8748
That reminded me... http://tech.groups.yahoo.com/group/primenumbers/message/9901...
Andrey Kulsha
andrey_601
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Aug 11, 2007
7:28 am
8749
... Andrey's suggested method for 11 consecutive factorizations at 200 digits was to find factorizations of x^6-a, in the 5 hardest cases: a=2,3,5,6,7, and...
David Broadhurst
djbroadhurst
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Aug 11, 2007
9:16 am
8750
Let x=13860*(10^60+1898683) N=x^2*(x^2-23)*(x^2-41)*(x^2-64)/55440-4 then N+k is factorized for k in [0,9]. Proof: ...
David Broadhurst
djbroadhurst
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Aug 11, 2007
9:52 pm
8751
... Wow! Big congratulations on an astonishing record. ... After 5 days of the page, there are already more numbers above the 500-digit limit than I expected...
Jens Kruse Andersen
jkand71
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Aug 12, 2007
12:20 am
8752
... I was also astounded. I had been doing some p25 work on a sample of 1158 (potential) factorizations of 5 consecutive integers at 500 digits, based on PFGW...
David Broadhurst
djbroadhurst
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Aug 12, 2007
5:04 am
8753
... Sextic deconstruction: P(c,x) = prod(k=1,length(c),x - c[k]^2) Q(c,x) = P(c,x) - P(c,0) a = [22, 61, 86, 127, 140, 151]; b = [35, 47, 94, 121, 146, 148]; ...
David Broadhurst
djbroadhurst
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Aug 12, 2007
7:18 am
8754
... I know the feeling of finding more than was searched. It's nice! ... Well, I didn't say what it was relative to ;-) But I have changed "relatively easy" to...
Jens Kruse Andersen
jkand71
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Aug 12, 2007
1:33 pm
8755
Posted by: "Jens Kruse Andersen" jens.k.a@... jkand71 ... Wait a sec. You're constructing the composites. Why aren't you constructing them so that...
Phil Carmody
thefatphil
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Aug 13, 2007
9:24 am
Messages 8726 - 8755 of 9803   Oldest  |  < Older  |  Newer >  |  Newest
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