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Re: Primes/Benford   Message List  
Reply | Forward Message #4432 of 21093 |
Re: Primes/Benford

Phil Carmody wrote (at inordinate length):

> ln(1+1/d)/ln(b)

and I checked 25 thousand LucFib cofactor primes,
greater than a million, in base b=10:

d # fraction Benford=log(1+1/d)/log(10)

[1, 7869, 0.313] 0.301
[2, 4456, 0.177] 0.176
[3, 3107, 0.123] 0.125
[4, 2342, 0.093] 0.097
[5, 1977, 0.078] 0.079
[6, 1665, 0.066] 0.067
[7, 1360, 0.054] 0.058
[8, 1255, 0.049] 0.051
[9, 1107, 0.044] 0.046

Looks good to this heathen physicist!

David





Tue Dec 11, 2001 5:13 pm

djbroadhurst
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Message #4432 of 21093 |
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On Mon, 10 December 2001, Jack Brennen wrote: This is still _very much_ on topic for the list so I've brought it back on list, I hope you don't mind. ... And...
Phil Carmody
thefatphil
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Dec 10, 2001
8:33 pm

... No problem. You'll see as you read on that I have amended my view... ... Certainly no slight was intended, and I have the highest respect for you. ... ...
jbrennen
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Dec 10, 2001
10:32 pm

... I too have great respect for you, and for Jud too, which is why I said that I was prepared, even looking forward, to being educated by my elders, if the...
Phil Carmody
thefatphil
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Dec 11, 2001
12:45 am

... Or, to rephrase Emerson, in more gender-inclusive fashion: our reach should exceed our grasp. Andrey, Jack and Jud have grasped the obvious content of PNT;...
djbroadhurst
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Dec 11, 2001
1:05 am

Whoops! It was Browning; not Emerson: http://groups.yahoo.com/group/primeform/message/1142...
djbroadhurst
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Dec 11, 2001
1:15 am

... and I checked 25 thousand LucFib cofactor primes, greater than a million, in base b=10: d # fraction Benford=log(1+1/d)/log(10) [1, 7869, 0.313] 0.301 ...
djbroadhurst
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Dec 11, 2001
5:13 pm
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