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10^12000+3213 and P =/= NP   Message List  
Reply Message #694 of 24247 |
10^12000+3213 is a probable prime.

By the way these numbers prove that P =/ NP.

Primes are in NP (Pratt, 1975).

But, primes are not decidable in polynomial time,
example of this number and infinitely many others.
Therefore, primes are not in P.

Milton L. Brown




Thu Mar 29, 2001 9:36 pm

miltbrown@...
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Message #694 of 24247 |
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10^12000+3213 is a probable prime. By the way these numbers prove that P =/ NP. Primes are in NP (Pratt, 1975). But, primes are not decidable in polynomial...
Milton Brown
miltbrown@... Send Email
Mar 29, 2001
9:35 pm

... I have refrained from commenting on P versus NP, thus far. My understanding is restricted to some parts of Stephen Cook's precise formulation of the $1M ...
d.broadhurst@... Send Email Mar 29, 2001
10:58 pm

... Don't forget what your statement means. If primality proving cannot be in P, Riemann's Hypothesis is false. -- Barubary...
Barubary
barubary@... Send Email
Mar 29, 2001
11:04 pm

... Thanks for the reminder! I was talking to Alain Connes recently and told him: "If you manage to prove GRH, it will transform primality proving, in the...
d.broadhurst@... Send Email Mar 29, 2001
11:55 pm

I'm not a mathematician, nor do I know much about Riemann's Hypothesis (how Zeta() can have zeros at all is a mystery to me :) ). What I do know is that...
Barubary
barubary@... Send Email
Mar 30, 2001
2:03 am

... I meant a non-deterministic polynomial bound, almost always, as in ECPP. (And I should have said so, sorry, since being in NP is something different, as...
d.broadhurst@... Send Email Mar 30, 2001
3:24 am

Yes, I have read Cook's proof....
Milton Brown
miltbrown@... Send Email
Mar 30, 2001
2:36 am

... No you haven't, Milton, because there is no proof. Cook is justly famous for formulating a question that no-one has yet answered. That's why he was asked...
d.broadhurst@... Send Email Mar 30, 2001
2:58 am

What exactly is wrong? So, Riemann was wrong for once, it has happened to the best of us. Milton L. Brown...
Milton Brown
miltbrown@... Send Email
Mar 30, 2001
2:41 am

... Also, I don't think any knowledgeable person thinks that the ERH is false. If the ERH is true then primes are in P. ...
Jud McCranie
jud.mccranie@... Send Email
Mar 30, 2001
3:08 am

Sorry, I thought you meant the proof of the Cook-Levinson Theorem. Milton...
Milton Brown
miltbrown@... Send Email
Mar 30, 2001
4:06 am

... Sorry, I don't know that theorem. Norman Levinson did many fine things, such as his work on the zeros of the Riemann zeta function and his famous letter to...
d.broadhurst@... Send Email Mar 30, 2001
5:31 am

How specifically is it wrong? Could you define "knowledgeable person"? Or is that wrong, too?...
Milton Brown
miltbrown@... Send Email
Mar 30, 2001
4:09 am

... You're stating this without any proof or evidence: "But, primes are not decidable in polynomial time, example of this number and infinitely many others. ...
Jud McCranie
jud.mccranie@... Send Email
Mar 30, 2001
4:39 am

David, The reason I was confused seems to be your statemnt: "Anyone who thinks that is is easy to decide whether P is or is not the same as NP should read...
Milton Brown
miltbrown@... Send Email
Mar 30, 2001
5:30 am

... History is always moot. Jack Edmonds paper on matroids was clearly influential, as Cook says in the Clay 2000 PDF formulation to which I directed you. ... ...
d.broadhurst@... Send Email Mar 30, 2001
5:41 am

... Milton's right this time. Cook came up with NP-completeness. +--------------------------------------------------------+ ... ...
Jud McCranie
jud.mccranie@... Send Email
Mar 30, 2001
8:24 pm

... Thanks, Jud. I uncritically accepted the final sentence of http://www.claymath.org/prizeproblems/pvsnp.htm "Stephen Cook formulated the P versus NP problem...
d.broadhurst@... Send Email Mar 31, 2001
12:55 am
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