Hi Mark, I certainly hope to find a 100,000+ digit mf some time this year. If I do it will be of the form n!2-1. (but I've got to find it and they are few and...
11601
Harvey, Steven
harvey563
Feb 26, 2003 10:28 pm
I hope to find either a Generalized Woodall or Multifactorial prime with 100000+ digits by the end of the year. Probaby a n!2+1 if a multifactorial. Ken Davis...
11602
Jane Jones
jane91108
Feb 27, 2003 6:57 am
From: Milton Brown [mailto:miltbrown@...] Sent: Tuesday, February 25, 2003 11:30 AM To: d.broadhurst@...; primenumbers@yahoogroups.com Cc:...
11603
David Broadhurst <...
djbroadhurst
Feb 27, 2003 8:34 am
Yes Jane, I replied at 25-FEB-2003 21:07:39.71 GMT to that message, off-list, since that is how Milton sent it. It seems that you and he are closely ...
11604
Gary Chaffey
garychaffey
Feb 27, 2003 7:30 pm
Is there a list of Twin primes with non trivial proofs?!? __________________________________________________ Do You Yahoo!? Everything you'll ever need on one...
11605
David Broadhurst <...
djbroadhurst
Feb 27, 2003 10:15 pm
I don't know of any larger than 4915416*10^1999+19 2006 p40 01 Twin (p+2), ECPP 4915416*10^1999+17 2006 p40 01 Twin (p), ECPP...
If p is a prime, what is the probability of p+/-2 being prime? Jon Perry perry@... http://www.users.globalnet.co.uk/~perry/maths/ ...
11608
David Broadhurst <...
djbroadhurst
Feb 27, 2003 10:33 pm
Gary: I assume that you account these triplet twins as trivial: (482408919814344*3251#*(4436*3251#+1)+210)*(4436*3251#-1)/35+13 4135 p44 2002 Triplet (3) ...
11609
broke_as_ajoke <lu...
broke_as_ajoke
Feb 28, 2003 12:14 am
Hi everyone i'm new to the group and i want t start out by saying hello... but i hate to break the bad news i have a question as well. i hope someone can help....
11610
Dick <richard042@....
richard042
Feb 28, 2003 1:52 am
Hello, Thanks for the kind words Phil. I'm gearing up to produce some new stuff which will be clearer, more rigorous, of stronger theoretical valuable and...
11611
Carl Devore
carldevore
Feb 28, 2003 7:15 am
... We can choose any contiguous block from the M and any contiguous block from the N. This can be done M*(M+1)*N*(N+1)/4 ways. Prove by induction that the...
11612
Jud McCranie
judmccr
Feb 28, 2003 8:05 am
... for NxN, this is Sloane's sequence A537....
11613
Ignacio Larrosa Ca...
ilarrosa
Feb 28, 2003 8:19 am
... From: <luken2u@...> To: <primenumbers@yahoogroups.com> Sent: Friday, February 28, 2003 1:14 AM Subject: [PrimeNumbers] need a lil help with a...
11614
Phil Carmody
thefatphil
Feb 28, 2003 8:39 am
... Less than 2/ln(p). The fact that you've excluded p=3 from the possible factors means that the usual probability is doubled. (And notice you have 2...
11615
mikeoakes2@...
mikeoakes2
Feb 28, 2003 9:18 am
In a message dated 28/02/03 08:40:10 GMT Standard Time, ... This is standard stuff - see for example ...
11616
Gary Chaffey
garychaffey
Feb 28, 2003 9:18 am
The reason I ask is that I almost accidently stumbled across 2^3500+1935001 2^3500+1935003 But these are smaller than the other ones mentioned by David and Co....
11617
Phil Carmody
thefatphil
Feb 28, 2003 10:30 am
... I realised that as soon as I'd posted, but I knew that others would pipe up soon enough anyway. The thing that threw me briefly was that it's _not_ the...
11618
Jon Perry
jon_perryuk
Feb 28, 2003 12:44 pm
Thanks. I think I'll take Phil's <2/ln(p) answer as definitive. A point in passing, what are the respective limits when p and p' are summed, where p is the...
11619
Adam <a_math_guy@....
a_math_guy
Feb 28, 2003 3:08 pm
I was wondering about a topic related to "twin primes are rarer than the product of two independent probabilities would suggest." Specifically, Dirichlet's...
11620
David Broadhurst <...
djbroadhurst
Feb 28, 2003 3:22 pm
Adam: I think you can forget about pseudoprimes, provided you are not using big powers of 2 in your Ansatz. More likely, the probabilites are not independent...
11621
David Broadhurst <...
djbroadhurst
Feb 28, 2003 3:28 pm
PS: An obvious factor of 2 might come from the fact that the first prime is odd?...
11622
Jon Perry
jon_perryuk
Feb 28, 2003 4:32 pm
Anybody seen this before? http://www.geocities.com/rze17/zeros.pdf (home page http://www.geocities.com/rze17/math.html) Jon Perry perry@... ...
11623
Jose Ramón Brox
ambroxius
Feb 28, 2003 5:30 pm
I'm looking at the proof for if I could find a flaw. The only thing I have observed is that he took off the null roots of the polynomial, and I was wondering...
11624
Jose Ramón Brox
ambroxius
Feb 28, 2003 6:06 pm
Well, in the same page of Mathworld (http://mathworld.wolfram.com/RiemannZetaFunction.html) we can see the graphic of zeta(x) and it isn't zero in x=0, so...
11625
David Broadhurst <...
djbroadhurst
Feb 28, 2003 7:25 pm
I knew of the use of Euler-Maclaurin in Sondow, Jonathan The Riemann hypothesis, simple zeros and the asymptotic convergence degree of improper Riemann sums. ...
I want to say thank u to all that helped me.. my teacher gave the answer... C(n+1,2)* C(m+1,2).. now i have to come up with the best way to explain it.. and i...
11628
velozant <velozant...
velozant
Feb 28, 2003 10:14 pm
I was looking at http://www.primepuzzles.net/problems/prob_037.htm and in the proof of the formula mr Fengsui claims that "...the class of residues Tn mod mn...
11629
Jon Perry
jon_perryuk
Mar 1, 2003 12:01 am
'Suppose that: the Tn is a complete set of residues prime to mn, the least number more than 1 in this set U(Tn) is the n-th prime pn. The number of elements of...
