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Messages 14626 - 14656 of 21093   Oldest  |  < Older  |  Newer >  |  Newest
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14626
Let's say you have an arbitrarily long list of primes (but it is bounded). Is it always possible to make a list of multipliers, with a one-to- one...
asposer
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Mar 3, 2004
12:41 am
14627
... This is always possible for any n and any order of the primes. The problem is just solving a set of modular equations. Your example, with x for the first...
Jens Kruse Andersen
jkand71
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Mar 3, 2004
4:37 am
14629
I wrote ... For some reason I had not seen Jens's post, which is (a) neater and (b) proves the general case. So I am erasing my post - sorry for wasting your...
mikeoakes2@...
mikeoakes2
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Mar 3, 2004
9:17 am
14630
Congratulations to Dave Linton! 659*2^800516-1 is prime. http://primes.utm.edu/primes/page.php?id=69058 It was more than 1 year which he had not submitted any...
Payam Samidoost
samidoost
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Mar 3, 2004
3:04 pm
14631
Congratulations indeed.Beyond the size of this prime,it is also a Riesel prime! one more down:) Pavlos ... __________________________________ Do you Yahoo!? ...
Pavlos S
pavlos199
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Mar 3, 2004
4:41 pm
14632
I've noticed, that there are sometimes troubles with GMP-ECM running a p-1 check with bounds that are bigger than 4e9. I ran a p-1 test with B1=1e10 on 2^933+1...
biwema
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Mar 3, 2004
11:18 pm
14633
While we're talking about GMP-ECM, was the trial factoring problem in version 5 ever fixed? Andrew...
andrew_j_walker
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Mar 4, 2004
1:37 am
14634
Thanks for your reply, I've read about the Chinese Remainder Theorem but I've struggled with understanding its implications. I'm also interested in functions...
asposer
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Mar 4, 2004
1:44 am
14635
Mike Oakes proved ... are ... Can we also prove the case for N=a^p+b^p? ... of m, ... Cino...
hillcino368
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Mar 5, 2004
9:25 am
14636
In a message dated 05/03/04 09:26:14 GMT Standard Time, ... Yes. Nowhere is the positivity of a or b used in the proof (so the Theorem should not have required...
mikeoakes2@...
mikeoakes2
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Mar 5, 2004
11:37 am
14637
... But of course! Thanks. I also noticed that if p is not prime then the prime factors of p divide q-1. This applies to even numbers also. Does the even case...
cino hilliard
hillcino368
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Mar 5, 2004
1:01 pm
14638
Is there a name for and/or have primes of the form (a-1)*(a^(p*q)-1)/(a^p-1)/(a^q-1) been studied? Here p and q are primes and a is any positive integer. Many...
Edwin Clark
eclark222001
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Mar 6, 2004
11:46 am
14639
Apparently many interesting prime forms have been overlooked, perhaps because there are infinitely many such forms. The past few days I've been looking at...
Fred Barnes
fredlb37
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Mar 6, 2004
8:45 pm
14640
Just to settle an argument that is developing in a newsgroup somewhere, could anyone tell me if there is possibly any difference between the terms "co-prime"...
Ben Newsam
primes@...
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Mar 7, 2004
1:00 am
14641
... I've never heard of a difference. There is also "a is prime to b" and "a and b are prime to each other", which mean the same thing....
Carl Devore
carldevore
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Mar 7, 2004
1:19 am
14642
... Same thing. http://mathworld.wolfram.com/RelativelyPrime.html...
Jud McCranie
judmccr
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Mar 7, 2004
3:09 am
14643
What do you think, does there exist a base b such that n*b^n-1 or n*b^n+1 never is prime? I have no answer to that question, but maybe it is easy for some of ...
yummie_55555
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Mar 7, 2004
12:16 pm
14644
Dear geeks , Are there any primes P of any form such that 2*K*P + 1 is never prime for any positive value of K. Or to be specific does there exist any single...
Shiv Nandan Singh
meet_crypto
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Mar 7, 2004
4:00 pm
14645
Dear geeks , Are there any primes P of any form such that 2*K*P + 1 is never prime for any positive value of K. Or to be specific does there exist any single...
Shiv Nandan Singh
meet_crypto
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Mar 7, 2004
4:00 pm
14646
... 2*P and 1 are relatively prime (whether P is prime or not). Then Dirichlet's theorem says there are always infinitely many primes. ...
Jens Kruse Andersen
jkand71
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Mar 7, 2004
6:04 pm
14647
... No base b has a finite covering set of factors. If M is a finite set then let A be the product of the members. If n=k*A for any k, then n*b^n+/-1 clearly...
Jens Kruse Andersen
jkand71
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Mar 7, 2004
6:04 pm
14648
Dear idiot, 2KP+1 is an arithmetic progression whose elements have no common factor, and so will always contain infinitely many primes, whatever P is. Andy PS...
Andy Swallow
umistphd2003
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Mar 7, 2004
7:22 pm
14649
Thomas, Large bases are less likely to produce primes, because of the rate the series grows by, but it is impossible to say there is no prime in the series or...
eharsh82
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Mar 8, 2004
4:37 am
14650
Indeed,the non-existence of a finite covering set does not prove infinite number of primes.Some time ago i had constructed a "possible"-infinite covering set...
Pavlos S
pavlos199
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Mar 8, 2004
9:41 am
14651
Hello, I have put a link to Dario Alpern's Factorisation applet and Xiao Gang's factorisation program Factoris on the F.I.D.N website at http://www.fidn.org/...
paulmillscv
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Mar 8, 2004
1:32 pm
14652
Hello, I post details of a new study on psychonumerics. This is recommended reading for persons who work daily with large numbers and will be of interest to a...
paulmillscv
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Mar 8, 2004
5:54 pm
14653
Paul, Thank you for the paper on "psychonumerics"! It's very funny, indeed! It's good to be able to laugh at ourselves sometimes. Tom ... From: paulmillscv...
Hadley, Thomas H (Tom...
kctom99
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Mar 8, 2004
6:12 pm
14654
I will take any patterns you guys have found in primes on the interent or one that you got yourself. I WILL find the ultimate pattern for primes....
Bigfoot
plano9
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Mar 9, 2004
12:11 am
14655
Dear Tom, Hello. I am glad you like it. Remember, do not venture into the unknown, unless you know. regards Paul Mills ... indeed! It's good to be able to...
paulmillscv
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Mar 9, 2004
2:24 pm
14656
Hi all i would like to ask if any body has a way to generate a sequence of numbers that containes all prime, faster than generating all odd number thank you in...
H.BARGHOUT
hamedbar
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Mar 10, 2004
2:06 pm
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