Dear All, This is my first communication with the primenumbers group, (or any group come to that) so I hope that I'm doing eveything right! My interest is with...
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Milton Brown
miltbrown@...
Jan 1, 2001 11:35 pm
Here is a complete program which I submitted last year, to do the multiplication as a convolution product. Just compile and run it. It does not require any...
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Andrey Kulsha
Andrey_601@...
Jan 1, 2001 11:41 pm
Hello Bill! Please mathematically define the rules of your symmetry, and I (and, probably, some other list members) will try to prove (or disprove) them. ...
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Milton Brown
miltbrown@...
Jan 1, 2001 11:49 pm
It is removing attachments? So here it is as text: Milton L. Brown miltbrown@... // // By Milton L. Brown 8-1-2000 (in file Mult.cpp) // It takes...
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Phil Carmody
fatphil@...
Jan 2, 2001 12:53 am
Here are some 'linting' problems with the code. - You don't use all of the variables you have declared. - If your char buffer is 100 bytes long, the largest...
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Milton Brown
miltbrown@...
Jan 2, 2001 2:06 am
Thanks for the hints. It was quick and dirty but it works, without optimizations. Some of thhe "h-files" that I have downloaded simply do not work. These are...
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Milton Brown
miltbrown@...
Jan 2, 2001 3:49 am
Thanks for letting me know. It seems that the new prime pages is some how, cutting off the attachments, which I still don't understand if this is correct, or...
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Dick Boland
richard042@...
Jan 2, 2001 8:36 am
Hello all,If you have trouble with the attachment, I will be posting a copy in Primeform's file areaIf you like the proof, please respond to the list with an...
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Dick Boland
richard042@...
Jan 2, 2001 10:18 am
Hello, Regarding my proof of Goldbach's Conjecture, I had some trouble with the pictures in HTML as an attachment. You may also view my proof at...
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Paul Leyland
pleyland@...
Jan 2, 2001 1:46 pm
I've not yet had chance to check your proof on your web page, but the following two sentences caught my eye. ... Too late. In virtually the entire world, you...
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Bill Krys
billkrys@...
Jan 2, 2001 3:01 pm
These 2 statements caught my eye too. you can't claim patent rights without registration and then they are granted to you. Also, Paul is right that most...
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Chris Caldwell
caldwell@...
Jan 3, 2001 12:00 am
... Yes, I set it up that way. I thought we might use the file area. But the attachments can be turned back on if folks prefer it. Attachments can carry...
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David Broadhurst
d.broadhurst@...
Jan 3, 2001 12:16 am
... Please leave them off, as at present. Non-ASCII stuff and/or long files belong in the files area, as successfully managed in PrimeForm and OpenPFGW...
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Conrad Eaton
ceaton@...
Jan 3, 2001 3:47 am
... OK, I agree - leave them off. However, let me display my ignorance here. How does one access the files area? Thanks, Connie...
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David Broadhurst
d.broadhurst@...
Jan 3, 2001 5:49 am
... Click on "Files" to left of message. There is the only file lodged there at present: http://www.egroups.com/files/primenumbers/Articles/antiorders.zip by...
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Rob Binnekamp
rob.binnekamp@...
Jan 3, 2001 1:59 pm
Let o be an odd number,e an even number and p a prime number with 2<p<o. Let o1=p1+e1 ( o1 arbitrary,p1 choosen<o1) Let o2=p2+e2 ( o2 arbitrary,p2...
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Paul Jobling
Paul.Jobling@...
Jan 3, 2001 2:11 pm
But can you guarantee that every even e is represented??? ... __________________________________________________ Virus checked by MessageLabs Virus Control...
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Dick Boland
richard042@...
Jan 3, 2001 6:34 pm
Gentlemen, I have rigidly proven Goldbach's Conjecture. It's amazing because the thing I found to finally prove it is "THE" prime number distribution...
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David Broadhurst
d.broadhurst@...
Jan 3, 2001 6:55 pm
... and others? ... I guess you need a referee of a reputable math journal to adjudicate as to rigidity. ... or, more rigidly: ...
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omega@...
Jan 3, 2001 7:30 pm
... Hello Dick, I really dont know what to think of this. My first thought is that its a rather early 1 April post after reading your claims in the...
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Dick Boland
richard042@...
Jan 3, 2001 8:59 pm
Hello, Yes I can. The distribution function is simply stated as follows, For any integer k>4, the first k^2 primes will be exactly distributed as follows: ...
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Hadley, Thomas H (Tom...
thadley@...
Jan 3, 2001 9:33 pm
Dick, I'm confused. I'm assuming that your notation p(n) means the nth prime, so for example p(25) = 97, the 25th prime. So if we let k=5, then does your...
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Phil Carmody
fatphil@...
Jan 3, 2001 10:08 pm
... k*(k+1) + k*(k-1) == 2k^2 So you seem to be out by a factor of 2 somewhere. Factoring in that factor of two... Table[{k, k^2, Prime[k^2], (Prime[k^2]+1)/2,...
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Milton Brown
miltbrown@...
Jan 3, 2001 10:17 pm
k^2 - k*(k+1) leaves k remaining not k*(k-1) or k*(k+1) + k*(k-1) = 2*k^2 Does this affect your proof? Could you send you mail with shorter lines, my...
40
Stphn828@...
Jan 3, 2001 10:17 pm
Has anyone noticed this? Finding primes, X to N when (3*X) > N, you do not need all of the primes up to the SQRT of N. Instead all you need is the primes up...
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Bill Krys
billkrys@...
Jan 3, 2001 11:03 pm
Dick, may I get a copy of your proof. I cannot acces your webpage after several attempts. Bill ... ===== Refining my sieve into a simple, non-stochastic...
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Dick Boland
richard042@...
Jan 3, 2001 11:11 pm
I am so sorry, Yes that is what I mean - k*(k+1)/2 in the first half and k*(k-1)/2 in the second half. It is correct in my proof. -Dick "Hadley, Thomas H...
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Dick Boland
richard042@...
Jan 3, 2001 11:15 pm
Sorry Phil, It was a typo. k*(k+1)/2 primes <= (p(k^2)+1)/2 and k*(k-1)/2 primes between ((p(k^2)+1)/2+1) and p(k^2). You won't find a counter example there....
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Dick Boland
richard042@...
Jan 3, 2001 11:22 pm
It does affect it, it was a typo.Should be k*(k+1)/2 and k*(k-1)/2.The best way to see it is at the website,It large and I couldn't get the pictures to go...
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Phil Carmody
fatphil@...
Jan 3, 2001 11:38 pm
... I know it was a typo, which is why in the data below I correct that typo. And with the typo corrected I do find counterexamples. Check again please. Phil ...
