Hello friends, This is to inform u that a new group on number theory has been created. Any one interested in this field may please visit our site. It poses...
Is there a simple and easy explanation (proof) as to why Ln[p#(i)] nearly equal p(i) p#(i) being the primorial of the i-th prime p(i) Ln[] being the natural...
... From: "Anton" <al_at_i@...> Is there a simple and easy explanation (proof) as to why Ln[p#(i)] nearly equal p(i) p#(i) being the primorial of the...
Hello, I would like to propose two new conjectures about the quantity of primes in a given range. Date of discovery: 15 August 2005 (if I am the first ...). ...
I'm pausing the server for a few days (maybe a week or so) while I completely re-do the underlying database to permit it to manage multiple independent ...
hi, I am looking for a pre-computed table of the prime factorization of 2^n -1,400<n<500 and n is even. I am only able to find the prime factorization for all...
You can work out the factorisations of the even values from the tables of factorisations of 2^n+1 and 2^n-1 given in that document - all of the required...
... Sarad There is an algebraic factorisation for even exponents: 2^(2n)-1 = (2^n-1)(2^n+1) So there's no point in recording them separately. (Read the...
According to Prime Number Theorom a) pi_a(n) ~ Li(n) above is the improvement over b) pi_b(n) ~ n/(ln(n)+B) with B = -1.08336 For those who cannot compute the...
Hello I unfortunately have no good books on the prime number theorem and my studies in prime numbers have led me to this conjecture: The difference between the...
Hi, a special congratulations to the Hungarian collaborators Zoltán Járai, Gabor Farkas, Timea Csajbok, Janos Kasza and Antal Járai for the record 51779...
Consider the product (2*A*B). If A and B represent two CONSECUTIVE ODD integers, or two CONSECUTIVE EVEN integers, or two CONSECUTIVE PRIME integers, then one...
w_sindelar@...
Sep 8, 2005 11:31 am
17010
This exercise stems from my previous post "A Remarkable Property of Consecutive Integer Pairs; Odd, Even and Prime." Anyone care to carry it further? There...
w_sindelar@...
Sep 8, 2005 12:01 pm
17011
Ladies and Gentlemen, I have an important announce to make. Remember back in 2001 or so, I made this preposterous statement that I'll crack the RSA code....
The following number is PRP with 10000 digits 2^33216-10^9997-9^10476-8^11069-7^11829-6^12846-5^14302-4^16603-3^20950-77985 It coverts th 10000 digit number...
Milton Brown
miltbrown@...
Sep 8, 2005 1:34 pm
17013
Can someone tell me if Paul Leyland of Microsoft is still around? Thanks!...
... A humble apology to Daniel Papp for mispelling his name. The new record also doubles as the largest Chen prime todate. We are still searching primes from...
... In other words: There are cases of consecutive primes P, Q, R such that Q*R +/- P*(Q+R)/2 are both prime. If P, Q, R is a prime AP3 with P>3 then P, Q, R...
Yes. I fail completely: a) to see what it has to do with me in particular and b) to understand your reasoning with respect to the difficulty of the "RSA...
Basically no new big features since the last chart, 7 months ago. http://primes.utm.edu/~fatphil/20050909_5y_all.png The horizontal scale is in days since...
They are presented at the same time because they have formal similarities. Conjecture A : Pi((m+1)^n) - Pi(m^n) >= m^(n-2) for n >= 2, m >= 1. Conjecture B : ...
On Thu, 8 Sep 2005 23:28:10 +0200 "Jens Kruse Andersen" ... Jens thank you for your quick response. But you have me stumped. Can I interpret your response as...
w_sindelar@...
Sep 10, 2005 2:05 pm
17022
... Yes, that is correctly interpreted. My formulation: "There are cases of consecutive primes P, Q, R such that Q*R +/- P*(Q+R)/2 are both prime" is simply a...
Dear People, David Broadhurst and I have recently proven a new Non-trivial Gigantic primerecord with 31034 digits. It's the Generalized Lucas primitive part...
Mark, I think what Jean meant was that multiple people could work on different factor values for the same range of numbers. For example how PSP does...
... My point is that you won't be able to sieve much deeper by taking a larger range and distributing it. Maybe you can sieve 1% or 2% deeper, but that...
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