... Hi Werner, Humm, this sounds like a question for a convergence specialist like Milton ! ;-) BTW, shouldn't it be 5/7, 31/37 and 47/53 instead of 7/5, 37/31...
Hi grostoon, my beginning of the product 2/3 * 7/5 * ... is quite correct. I thought I could avoid the ugly formula: product(p(n)/p(n+1)) * (p(n+3)/p(n+2)). ...
"Werner D. Sand" <Theo.3.1415@...> wrote: Hi grostoon, my beginning of the product 2/3 * 7/5 * ... is quite correct. I thought I could avoid the ugly...
... All factors 7/5, 23/17,...,p(n+3)/p(n+2),... are larger than 1 so how their products can converge to zero? 5/7*17/23* ... seems to converge to 0, so its...
... Hi, I've calculated very rough estimation of products p1=2/3*11/13*... and p2=7/5*19/17*... up to LIM primes (it is very rough since I used Nextprime from...
Hello Bob, you are not allowed to handle an infinite product like that. Did you already calculate step by step? Your argumentation is as if you would say: 1 -...
... I was just averaging some figures around the n = 40,000 area and it worked out to be around .9105. Looking a Jacque's findings the product seems to be ever...
could someone please tell me where can i find a list of the first 1 000 000 000 (1 billion) prime numbers. i need it for a program, but i cannot generate it...
Dear All, Please any one send me Farmet's Last Theorem (Proof) for n=2 and n=4 __________________________________ Start your day with Yahoo! - Make it your...
From: Burlacu Bogdan Date: 12/02/05 17:31:18 To: primenumbers@yahoogroups.com Subject: [PrimeNumbers] need help could someone please tell me where can i find a...
From: Idrees Muhammad Date: 12/02/05 23:34:46 To: primenumbers@yahoogroups.com Subject: [PrimeNumbers] HELP! About Farmet Last Theorem Dear All, Please any one...
... It would probably take you much longer to post a request and wait for a reply, or to download the list. I just used an intentionally-dumb method to list...
Hello Burlacu ! The 10^9th prime is 22,801,763,489. The best is, you generate yourself all primes with a program. I think it takes not more than any hours, but...
From: Werner D. Sand Date: 12/04/05 04:58:46 To: primenumbers@yahoogroups.com Subject: [PrimeNumbers] Re: product I suspect the product 2/3 * 7/5 * 11/13 *...
... From: "Kermit Rose" <kermit@...> Kermit says: With primes, anything might be possible. ... Then I'll wish for Xmas a prime divisible by 6, a pair...
... This product is not very difficult to compute if you know about the function gamma (the extension of factorials to the complex domain). You are trying to...
... I had a chat with Lee earlier and he said it was a case of "DNS poisoning" and that now the internet servers were propogating the correct information. I...
Hi all, after sieving through more than 10 trillion candidates to discover a new record Cunningham Chain of length 12, I surprisingly found a large Cunningham...
I have a quick question. How did Lucas determine s of 0 =4? The book I am reading says he uses U of n and V of n for (P,Q). IF (P,Q) determines that s of 0 =4,...
2^17 - 1 = 131071. Both 131 and 071 are prime, or 131~071, or 3~(2^17-1), since it splits at the third position. I tried to split other Mersenne primes up...
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