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Messages 18176 - 18205 of 21093   Oldest  |  < Older  |  Newer >  |  Newest
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18176
Hello All: you can see this conjecture at Primepuzzles.net: Problems & Puzzles: Conjectures Conjecture 44. A property of prime twins, only? Sebastián Martín...
Sebastian Martin
sebi_sebi
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Jul 1, 2006
1:22 pm
18177
... Since p and q are twin primes q=p+2 So z becomes sqrt( (p^2 + (p+2)^2)/2 -1) = sqrt( (p^2 + p^2 + 4p +4)/2 -1) = sqrt( (2p^2+4p+4)/2 -1 ) = sqrt(p^2+2p+2 -...
Ronny Edler
ronny_edler
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Jul 1, 2006
2:36 pm
18178
... Let p = a and q = a+2. Let a = any integer. Then: (a^2 + (a+2)^2)/2 - 1 = (a^2 + a^2 + 4a + 4)/2 - 1 = (2a^2 + 4a + 4)/2 - 1 = (a^2 + 2a + 2) - 1 = a^2 +...
David Cleaver
wraythex
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Jul 1, 2006
3:21 pm
18179
Is that group dead?Group peoples simply discussed the every useless topics.Why don't any one respond to my mail.As i got the key, for what? u peoples...
kadhirvel
kadickv
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Jul 1, 2006
9:59 pm
18180
... From: "kadhirvel" <kadickv@...> ... * To God we thank* Jose PS Well, some of them have to drop by here every now and then......
Jose Ramón Brox
ambroxius
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Jul 2, 2006
2:30 pm
18181
Prime of Primes p(1)=2=x1 p(2)=3=x2 p(3)=5=x3 p(5)=11=x4 p(11)=31=x5 p(31)=127=x6 p(127)=709=x7 p(709)=5381=x8 p(5381)=??=x9 ... p(n)~n*ln(n) General Formula...
miltbrown@...
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Jul 2, 2006
9:10 pm
18182
... I liked 'primeth primes' better, a thread started by Werner D. Sand last November, starting with message 17225 ...
Dick
richard042
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Jul 2, 2006
10:13 pm
18183
Let p q consecutive prime numbers p<q. Let z=sqrt[(p^2+q^2)/2-1] Conjecture: p&q ares twin primes IF AND ONLY IF z is integer. This is not a trivial result. ...
Sebastian Martin
sebi_sebi
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Jul 4, 2006
3:05 pm
18184
I dont spoke about you. There are other e-mails in this list that said this result is trivial. You don't understand me correctly. Sorry my english is very...
Sebastian Martin
sebi_sebi
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Jul 4, 2006
5:23 pm
18185
Re: Discussion between Sebastian Martin Ruiz and Mike Oakes ... sqrt([ (23^2 + 25^2)/2 -1) = sqrt(529 + 625)/2 - 1) = sqrt(1154/2 -1) =sqrt(577 - 1) =...
Kermit Rose
kermit1941
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Jul 5, 2006
2:31 am
18186
... From: "Kermit Rose" <kermit@...> ... No, it's not! You are forgetting the first line of the conjecture. I will restate it: KNOWING that p and q are...
Jose Ramón Brox
ambroxius
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Jul 5, 2006
11:51 am
18187
RE twin primes conjecture: A property of twin primes, only? Posted by: "Jose Ramón Brox" ambroxius@... ambroxius Date: Wed Jul 5, 2006 4:51 am (PDT) ... ...
Kermit Rose
kermit1941
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Jul 5, 2006
9:22 pm
18188
... From: "Jose Ramón Brox" <ambroxius@...> ... Sorry, I should have tried to verify it before sending; I just saw that finding a counterexample is...
Jose Ramón Brox
ambroxius
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Jul 6, 2006
3:32 am
18189
... From: "Sebastian Martin" <sebi_sebi@...> Let p q consecutive prime numbers p<q. Let z=sqrt[(p^2+q^2)/2-1] Conjecture: p&q ares twin primes IF AND...
Jose Ramón Brox
ambroxius
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Jul 6, 2006
7:04 am
18190
Reflection on the conjecture that if q is the next prime after p, where p is a positive integer prime, and if q - p > 2, then sqrt( [ p^2 + q^2 ] /2 -1 ) is...
Kermit Rose
kermit1941
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Jul 6, 2006
1:42 pm
18191
Distribution of square free positive integers Let N be the generic positive integer. Number of positive primes < N = N/ln(N) Number of positive integers =...
Kermit Rose
kermit1941
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Jul 6, 2006
2:38 pm
18192
... I am not sure that the question, as written above, makes sense. k must be substantially smaller than N for this type of estimation to have any value, as N...
Chris Caldwell
primemogul
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Jul 6, 2006
4:08 pm
18193
Hello I have extended the conjecture: p, q consecutive primes p<q are equivalents: 1) p q are twin primes 2) z=sqrt[(p^2+q^2)/2-1] is integer 3)...
Sebastian Martin
sebi_sebi
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Jul 6, 2006
11:32 pm
18194
... From: "Sebastian Martin" <sebi_sebi@...> ... Counterexample [contraejemplo]: p = 3, q = 11 z = sqrt( (p^2+q^2)/2 -1 ) = = sqrt( (9+121)/2 -1 ) = =...
Jose Ramón Brox
ambroxius
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Jul 7, 2006
3:03 pm
18195
... From: "Jose Ramón Brox" <ambroxius@...> ... Ooops... as Paul Jobling noted to me, I missed the condition of p and q being _consecutive_. Sorry. Jose...
Jose Ramón Brox
ambroxius
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Jul 7, 2006
4:10 pm
18196
Sorry 'bout this but I just can't find some obvious things in the PARI manual, I hope I didn't miss it... Anyway: the easy instruction "factor(N)" yeilds a...
Roahn Wynar
hahahahastay...
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Jul 8, 2006
7:21 pm
18197
twin prim conjecture extended Posted by: "Sebastian Martin" sebi_sebi@... sebi_sebi Date: Thu Jul 6, 2006 4:32 pm (PDT) Hello I have extended the...
Kermit Rose
kermit1941
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Jul 8, 2006
7:32 pm
18198
Hello, Group. I'm optimistic that no one will find a counter-example. This method is similar to Euclid's proof for infinite-ly many primes. Let k = 2, 3, 4, 5,...
Bill Bouris
leavemsg1
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Jul 8, 2006
7:44 pm
18199
... The factor(N) function returns a matrix with W rows, where W is the number of distinct prime factors of N and each row consists of two elements -- the...
Peter Kosinar
pkosinar
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Jul 8, 2006
9:39 pm
18200
Hello Bill, ... Unfortunately, your conjecture seems to fail for k=29 prime(29) = 109 primorial(109)=279734996817854936178276161872067809674997230 ...
Peter Kosinar
pkosinar
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Jul 8, 2006
10:45 pm
18201
... No. PARI/GP says the first counter examples are for k = 29, 33, 38, 39. ... That's an awfully short check, especially for a form allowing so many twin...
Jens Kruse Andersen
jkand71
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Jul 8, 2006
11:46 pm
18202
Currently in the prime pages http://primes.utm.edu/curios/index.php?start=4&stop=4 <http://primes.utm.edu/curios/index.php?start=4&stop=4> we can read: quote...
Anton
al_at_i
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Jul 9, 2006
10:52 am
18203
... 390: (There is one curio for this number that has not yet been approved by an editor.) 391: No curios for the number "391" are currently in our database. ...
Peter Kosinar
pkosinar
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Jul 9, 2006
11:07 am
18204
... From: "Anton" <al_at_i@...> ... 391 is the first Smith number ( http://www.research.att.com/~njas/sequences/A006753 ) that is also of the form F(n)+n...
Jose Ramón Brox
ambroxius
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Jul 9, 2006
10:37 pm
18205
391*100*(3+9+1)+1 is prime Milton L. Brown miltbrown@......
miltbrown@...
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Jul 12, 2006
1:07 am
Messages 18176 - 18205 of 21093   Oldest  |  < Older  |  Newer >  |  Newest
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