Sorry,... the formula should have been posted as... (3^(2n-2))*(3^(2n-1)-1)/2. I thought about it while driving home last night. This idea follows from...
... implies CGD(A,B) = 1, so ... (B) = 2A ... Forget my attempt to formalize a formula for an odd-perfect number be- cause by your very sigma definitions......
... From: "leavemsg1" <leavemsg1@...> ... Why is that so? If you have a sound argument for that idea, i.e., that the first perfect number must occur at...
As part of a project to generate some computer art and to build a video game, it came to pass that I needed a way to convert whole numbers into graphic images....
... It's pretty cool. The idea of creating bijections between numbers and multi-dimensional images is one I've theorised about a lot (I was going to turn DeCSS...
... Very nice. I wrote a script to draw some of these and see why you chose to work with the largest factor first (though I used a green square instead of a...
I don't suppose anyone can sketch a proof of it, could they? A quick search on the interweb failed to yield anything, and I don't remember seeing it in any of...
Monday, September 04, 2006 6:21 PM [GMT+1=CET], ... I think there are two or more versions of the theorem, related I suppose. In "Introduction to Analytic...
For those who are interested, you can now experiment with the Whole Number Hash Applet at https://home.comcast.net/~rwynar/. You can input some pretty big...
... Many thanks Ignacio! The formulation of the theorem I have seen was different, but closely related (namely the C(2p-1,p-1) one), and hopefully not too much...
... Oh dear, you seem to have fallen for the "write once, run anywhere" bu^Wmarketting message that Sun was so proud of. Alas, it don't work here, and yes,...
... I'd wondered if you did that on purpose. Go to http://www.utm.edu/staff/caldwell/preprints/temp/ 1to30 is just that, 1, 2, 3, ... Then the flat primes p,...
* Regards Raman / Tuch ... Here's a new way to find what you're looking for - Yahoo! Answers Send FREE SMS to your friend's mobile from Yahoo! Messenger...
Do you know any factor of 2^65537-1? I know M8191 has factor 338193759479 M131071: 231733529 M524287: 62914441 M2147483647: 295257526626031 * * * * Regards ...
I wrote to Dr. Math on 9/6/06... today. He asked... What is your question? I wrote: I see the many definitions that math books are filled with and ponder- ed...
... ponder- ... the ... ...omit the restriction. The function should have been f(1/a + bi) = a * g(1+abi) ... it. ... de- ... real ... my ... made ... the ... ...
... If my grandmother were alive... she would say, "Pourquoi quelqu'un ne soigne pas?" ... roughly translated ... "Why doesn't anyone care?" Phil? Chris? ... ...
... When you start out with an assumption like this, the rest of your argument is suspect. You don't even have to look much further to find that the second...
[I tried to send this email several times these days. I hope this is the good one] ... First time I see it. Is it a result of yourself? Do you have a proof? If...
... 1) Obviously, if A is even perfect number, it must be of the form A = 2^(n-1)*M_n, where M_n = (2^n - 1) is a Mersenne prime. The proof is straightforward,...
... I was aware of that. I was just asking for a proof of the claim as it was first stated, involving all perfect numbers (even the theoretical odd ones!). I'm...
... You are right... I thought about the multiples of 945... and it's absurd... look at the connection between abundant and perfect numbers when I use the...
Sorry about the lame questions, but I am not clear on a point that should be obvious.... My implementation of the Pollard p-1 algorithm seems to work pretty...
... It searches for factors. For an arbitrary prime it will take an excessively long time, as the only factor is the entire number. It's just doing what it ...
Hi all: Recently, I attended the ICM celebrated in Madrid, and aside from meeting a lot of famous people (like Mandelbrot, Eric Weisstein, Frank Morgan,...
Hi Prof. Caldwell and members, after 2 mounths of working on a possibly Mersenneprimenumber PFGW unfortunately made an error report : Warning !! Did not valid...
This might surprise: Conjecture: The ratio k_b defined as "the sum of all base-b digits of all the primes between 1 and n" to "n", converges to the constant...
