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Messages 19018 - 19048 of 21093   Oldest  |  < Older  |  Newer >  |  Newest
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19018
[Sorry for the repeat message folks.] RMA.NET is now available for beta testing on Windows Vista. The source files are located here: ...
Shane
divineprime
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Jul 2, 2007
11:27 pm
19019
Who can help me calculating up to 10 exact decimal places sum (1/n^(1-1/n) - 1/n) sum (1/p^(1-1/p) - 1/p) sum (ln(n) / n^2) sum (ln(p) / p^2) n=positive...
Werner D. Sand
theo2357
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Jul 5, 2007
2:25 pm
19020
An interesting extension of Patrick De Geest's Table is where 10^n+p and p are both prime (the first instance) The table begins: n---------p ============= ...
miltbrown@...
Send Email
Jul 5, 2007
2:26 pm
19021
... Patrick already has a list where 10^n-p1, 10^n+p2, n, p1 and p2 are all prime on his page http://www.worldofnumbers.com/index.html . Just search for...
Dirk Augustin
trex400
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Jul 5, 2007
8:23 pm
19022
maybe... let Z = 2^(2^(p+1))+1 ; p is prime Z is prime iff [Z (mod (2^p+1))] == 2^q ; for some q for p = 2, 3,..., next??? eg. p=2, 2^8+1 mod 5 == 2^1 and... ...
leavemsg1
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Jul 7, 2007
5:09 pm
19023
... maybe if q can only be odd???, then a statement that all Fermat primes greater than F4 are composite may arise??? just tinkering with the idea!...
Bill Bouris
leavemsg1
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Jul 8, 2007
11:02 pm
19024
Thanks for evaluations received. What I mean is: Can sum(ln(n)/n^2 ~ 0.93 reach 1? Can sum(ln(p)/p^2 ~ 0.49 reach 0.5? WDS ... [Non-text portions of this...
Werner D. Sand
theo2357
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Jul 9, 2007
11:29 am
19025
Hello members ! Is it possible that exist a new prime-k-tuplet page ? Since some days, I can't reach http://www.ltkz.demon.co.uk/ktuplets.htm best -- Norman ...
N.L.
nluhn
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Jul 9, 2007
5:15 pm
19026
Hello, ... Consider the inequality sum(ln(k)/k^2, k=A+1..infinity) < integral(ln(k)/k^2, k=A..infinity) The right-hand side can be evaluated as (ln(A)+1)/A....
Peter Kosinar
pkosinar
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Jul 9, 2007
9:49 pm
19027
What is the probability of a number being square free... it seems that the more square free numbers than the non-square free numbers for big numbers. Would be...
Sudarshan Iyengar
sudarshansr
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Jul 10, 2007
9:29 am
19028
... The density of numbers being nth-powerfree is 1/zeta(n), where zeta is the Riemann Zeta Function. So, for squarefree numbers, we have your probability is...
Jose Ramón Brox
ambroxius
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Jul 10, 2007
10:48 am
19029
I´d like to share a little concept for ACCOUSTICAL FACTORIZATION by using the relation between tones and overtones on strings, many guitarplayers might be...
Johannes Z.
joz1977
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Jul 11, 2007
5:50 pm
19030
Using a similar trick, one can verify the sum over the primes is strictly less than 0.5. One overestimates the tail end of the sum: sum(log(t)/t^2,t=p to 00,...
Adam
a_math_guy
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Jul 12, 2007
3:28 pm
19031
Is there a list of the known of Ramanujan prime? What is the largest value?...
John W. Nicholson
reddwarf2956
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Jul 12, 2007
3:37 pm
19032
PHYSICS: Factoring Numbers with Waves Zubairy Science 27 April 2007: 554-555 DOI: 10.1126/science.1140915 Hugo Scolnik A wise man hears one word and...
scolnik
scolnik2003
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Jul 12, 2007
5:45 pm
19033
Hugo Thank You for the hint, I´ll have a look at it soon as I get free access somewhere......
Johannes Z.
joz1977
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Jul 12, 2007
6:40 pm
19035
I was searching for an interesting note I've read years ago. Here it is: http://www.mathpages.com/home/kmath222.htm Hugo Scolnik [Non-text portions of this...
scolnik
scolnik2003
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Jul 13, 2007
11:56 am
19036
Whoops! Of course those inequalities are the other way around!! One overestimates the tail end of the sum: sum(log(t)/t^2,t=p to 00, t prime) <...
Adam
a_math_guy
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Jul 13, 2007
6:17 pm
19037
Fine trick, but what makes you sure the integral is not e.g. = 0.008? Didn't you only shift the problem upon the integral? Werner ... [Non-text portions of...
Werner D. Sand
theo2357
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Jul 14, 2007
11:53 am
19038
... The integral can be evaluated explicitly, exactly as I did in my original post. I just didn't find this method "nice trick"-y enugh, as it required adding...
Peter Kosinar
pkosinar
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Jul 14, 2007
2:25 pm
19039
... 0.008? ... original ... required ... sum). ... is ... 1000, ... terms ... 0.5. ... You are quite right. I integrated only numerically. Everything clear. ...
Werner D. Sand
theo2357
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Jul 16, 2007
7:36 am
19040
Let p be a large prime, and g a generator of Z/pZ. Let u<p be non-zero modulo small prime q. From g^u (mod p), is it ever possible to tell anything more about...
Phil Carmody
thefatphil
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Jul 18, 2007
1:58 pm
19041
Hello All, I generated the following fractal plot: http://www.isenbek.com based on the first 10,000 primes. I was wondering if anyone has seen this before, and...
snudco
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Jul 18, 2007
2:43 pm
19042
The new version of RMA.NET, has been extensively tested, and is now ready for release. This windows program is by far the fastest prime number software ...
Shane
divineprime
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Jul 18, 2007
5:23 pm
19043
The divergence of sum(1/2^ln n) and sum(1/2^ln p) can easily be proven. How can be proven that sum(1/3^ln n) and sum(1/3^ln p) converge? (IF they do. What are...
Werner D. Sand
theo2357
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Jul 21, 2007
1:17 pm
19044
... 3^ln(n) = 3^(log_3(n)*ln(3)) = n^ln(3) sum(1/n^ln(3)) converges as n^ln(3) dominates n*ln(n)^2 whose sum of reciprocals converges. => sum(1/p^ln(3)) also...
Phil Carmody
thefatphil
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Jul 21, 2007
2:16 pm
19045
... proven. ... the tail ... Thank you. Remains adding that the convergence radius r of sum(1/a^ln n) and sum(1/a^ln p) is r=a>e corresponding to the unity in...
Werner D. Sand
theo2357
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Jul 22, 2007
9:44 am
19046
We fill the array with it's index up to the length of the table. For example if we wish to use the Fermat prime number sieve to find the primes < 250, we set...
Kermit Rose
kermit1941
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Jul 24, 2007
4:34 am
19047
Hi, I'm not sure if my email got through to you so I'll post here. I put a message on usenet a few years back ...
andrew_j_walker
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Jul 29, 2007
1:00 am
19048
2^(2^m) + 1 mod prime 3 cannot divide any number in this series because (2 -1)^2 + 1 = 2 5 cannot divide any number in this series except 5 because (2 -...
Kermit Rose
kermit1941
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Jul 29, 2007
12:17 pm
Messages 19018 - 19048 of 21093   Oldest  |  < Older  |  Newer >  |  Newest
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