... Solved within a minute by searching the first term in OEIS: http://oeis.org/A214219 That may seem like cheating but this property looks difficult to guess....
24329
Mark
marku606
Jul 22, 2012 10:53 pm
Bingo! Yes with fresh eyes I see that the puzzle was rather obscure. Should have given a hint. But golly, is there anything that OEIS doesn't have? Good...
24330
Walter Nissen
nissen@...
Jul 23, 2012 12:59 am
Nice . Those interested in this puzzle , or even if not , may be interested in Doric Columns of Primes , http://upforthecount.com/math/pdor.html There are some...
24331
Jens Kruse Andersen
jkand71
Jul 23, 2012 9:27 am
... Your text was written in 1991. http://www.primepuzzles.net/puzzles/puzz_181.htm from 2003 has the same 11 terms up to 3163427380990800 and adds 3 more...
24332
Sebastian Martin Ruiz
s_m_ruiz
Jul 28, 2012 5:08 am
Hello all: If p and q are primes and p and q >3 we have: Floor[(p+q)/6]=Ceiling[(Floor[p/3]+Floor[q/3])/2] The reciprocal is not true. Sincerely Sebastian...
24333
Peter Kosinar
pkosinar
Jul 28, 2012 1:30 pm
... Now, replace "primes greater than 3" by "integers congruent to +1 or -1 modulo 6". Since any multiple of 6 behaves the same way on left-hand and right-hand...
24334
djbroadhurst
Jul 28, 2012 9:40 pm
... Here is one way to manufacture a titanic Fermat+Lucas PRP: {m=[142,144];z=[13,10];b=[1925,257];s= ...
24335
Bill Bouris
leavemsg1
Jul 28, 2012 9:46 pm
David, as the "Troll watcher", you should be looking at yourself in the mirror! Quit looking for primes, we know that they exist!! Prove a damn theory as...
24336
kevinacres
Aug 1, 2012 12:57 am
... [snip] ... [snip] Results from a neat little algorithm devised by David Broadhurst has allowed extension of the above puzzle. In particular the prime...
24337
paulunderwooduk
Aug 1, 2012 12:55 pm
Hi, I found this video of a lecture by Richard Taylor, which is pertinent to the group: http://www.youtube.com/watch?v=5pTaZu3C--s Paul...
24338
bobgillson@...
bobgillson
Aug 1, 2012 2:16 pm
Quite fascinating, but at the same time unintelligible on a deeper level, unless of course you possess the same pure Mathis insights that Richard Taylor has....
24339
Sebastian Martin Ruiz
s_m_ruiz
Aug 1, 2012 5:52 pm
Conjecture: This polynomial expression is always zero for all triplets of consecutive prime numbers greater than 23. Product[k...
24340
bobgillson@...
bobgillson
Aug 1, 2012 6:41 pm
I am pretty sure, but cannot be certain, that this was explained in Paul Underwood's recent reference to Richard's video, expounding and expanding Emil Artin's...
24341
Sebastian Martin Ruiz
s_m_ruiz
Aug 1, 2012 7:30 pm
I've been watching the video and are different things. ________________________________ De: "bobgillson@..." <bobgillson@...> Para: Sebastian...
24342
Aldrich
aldrich617
Aug 1, 2012 7:55 pm
{A,x,y : integers} 1) If A = 5x^2 + 5xy + y^2, then a subset of A is the complete set of all of the +/- 1 mod 10 primes and all of the composites that can be ...
24343
djbroadhurst
Aug 1, 2012 10:49 pm
... Let F(x,y) = 5*x^2 + 5*x*y + y^2 Then for any prime p = +/- 1 mod 10 it is straightforward to find integers [x,y] such that F(x,y) = p. In Pari-GP, simply...
24344
Peter Kosinar
pkosinar
Aug 2, 2012 12:55 am
... Rewriting the conjecture into a bit more readable form, we get the following claim (where p[n] denotes n-th prime number): For n >= 10, if we express...
24345
Aldrich
aldrich617
Aug 2, 2012 5:21 pm
... In this example, if p was not known already known to be prime or even if it was a possible value of F(x,y), would the qfbsolve procedure prove it to be so...
24346
Sebastian Martin Ruiz
s_m_ruiz
Aug 2, 2012 8:07 pm
Hello all: Conjecture: Let p(n) the nth prime number n>1 There is a twin prime pair between p(n) and p(n+1+Floor[log[n]^ (2-1/Pi^2)]) ...
24347
whygee@...
yasep16
Aug 2, 2012 8:11 pm
... Hello, ... I'm curious about your thought process. Can you please provide more background ? what makes you think this is true, how did you come to this...
24348
bobgillson@...
bobgillson
Aug 2, 2012 8:19 pm
Very good. But surely you must prove the Twin Prime Conjecture first. . . Sent from my iPad ... [Non-text portions of this message have been removed]...
24349
whygee@...
yasep16
Aug 2, 2012 8:22 pm
... Sure. but I don't think that the Twin Prime Conjecture will hold long :-)...
24350
bobgillson@...
bobgillson
Aug 2, 2012 8:26 pm
Opinions are far more numerous than proofs Sent from my iPad ... [Non-text portions of this message have been removed]...
24351
Sebastian Martin Ruiz
s_m_ruiz
Aug 2, 2012 8:29 pm
I tried experimentalemte many values. I work with MATHEMATICA and modifying the formulas many times I looking for symmetry, beauty and simplicity. Respect to...
24352
bobgillson@...
bobgillson
Aug 2, 2012 8:52 pm
Now I am totally lost. . . Symmetry, beauty and simplicity may well demonstrate that the Twin Prime Conjecture is false. Until someone, somewhere, is able to...
24353
whygee@...
yasep16
Aug 2, 2012 8:53 pm
... certainly. however, I have been working on-and-off on this and see that it is not impossible. It just requires a LOT of work, collaboration and more...
24354
bobgillson@...
bobgillson
Aug 2, 2012 9:17 pm
As I said the conversation is futile, but good luck! Sent from my iPad ... [Non-text portions of this message have been removed]...
24355
Mark
marku606
Aug 2, 2012 11:23 pm
Very neat conjecture Aldrich which I well remember you posted before. I bet it could be proven. Upon a flippant and cursory examination, perhaps your...
24356
djbroadhurst
Aug 2, 2012 11:55 pm
... No. ... No. ... It depends crucially on the sign of the discriminant. In the case of G(x,y) = 2*x^2 + 2*x*y + y^2 = (x + y)^2 + x^2 with negative...
24357
Mark
marku606
Aug 3, 2012 12:46 am
If x and y are relatively prime, the conjecture would be modified to this: If A is the set of all numbers of the form 5x^2 + 5xy + y^2, with x and y...
