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primenumbers · Prime numbers and primality testing

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  • Members: 1090
  • Category: Number Theory
  • Founded: Dec 27, 2000
  • Language: English
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These being, given s=1/2 + it 1) s is always irrational 2) s1-s2 != s3-s4 3) product(si) != product(sj) 4) sum(si) != sum(sj) Jon Perry perry@... ...
3 May 8, 2002
6:07 pm

Andrey Kulsha
andrey_601
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Hello Marcel! I see no reason why not to add this 9658-digit prime to your Top-20 page: http://www.znz.freesurf.fr/pages/primotop20.html Certificate is...
8 May 8, 2002
6:07 pm

Andrey Kulsha
andrey_601
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I have worked on Riemann's Hypothesis on and off for years. My interest lies in its application to encryption. Of course, monetary rewards await the...
1 May 8, 2002
2:22 pm

lonestarqueen2000
lonestarquee...
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(I forgot an important fact) ... and s = 1/2 + it is a zero of the zeta function as extended by Riemann or anyone else for that matter into the complex plane,...
1 May 8, 2002
6:02 am

Jon Perry
jon_perryuk
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According to Dickson, HotToN, Euler proved Fermat divisors are k.2^(n+1)+1, and it was only Lucas that pushed the exponent up to n+2. Other sources state that...
3 May 7, 2002
3:29 pm

Phil Carmody
thefatphil
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Hello to all ! After 180 days i found this nice prime 8-tuplet. 15234072433401*375#+43813839521 (+0,+2,+6,+8,+12,+18,+20,+26) best wishes Norman ...
1 May 7, 2002
3:14 pm

Norman Luhn
nluhn
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Dear members, I am sending an attachment with this mail, which contains a beautiful article (A research paper) written by my Professor, Dr. E. Sampath Kumar. ...
1 May 7, 2002
1:59 am

S.R.Sudarshan Iyengar
sudarshansr
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I was researching the Riemann Hypothesis, and I developed this theory. ... zeta(2)=pi^2/6 And zeta(2) is can also be written as the prime-based product: ...
6 May 6, 2002
10:57 am

Jon Perry
jon_perryuk
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Hi all ! 233 is the only prime p of form 60k-7 (up to 100000) where 2^p-3 is prime. Norman __________________________________________________________________ ...
5 May 5, 2002
1:43 am

Richard Traynham
therichardt
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While the page in question is still offline (perhaps a world record for the longest time offline by a Computer Society originated web page - I have this page...
2 May 4, 2002
7:52 am

Jon Perry
jon_perryuk
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Let p=k.2^n+1 Do you sieve p and (S)PRP/prove what remains, and then test to see if 2^(2^m)==-1 (mod p) for some m? If so, exactly what (S)PRP/proof is used...
4 May 3, 2002
9:07 pm

Phil Carmody
thefatphil
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Hello, If a prime q divides N=2^p+3 then : 2^p = -3 (mod q) so (2^p/q) = (-3/q) where (a/b) is the Legendre symbol it implies that (2/q) = (3/q).(-1/q) because...
1 May 3, 2002
8:27 pm

Renaud LIFCHITZ
nono2357
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Does anyone in the group know if any series of the form k.2^n+/-1 has 100+ known primes? Regards Robert Smith...
12 May 3, 2002
4:11 pm

Barbara and Joe
eulerprime
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I have 'issues&#39; with something in Crandall & Pomerance, their algorithm and their claimed big-Oh don't match (they are 'optimistic&#39;, heheh). However, they...
22 May 3, 2002
3:53 pm

djbroadhurst
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We hear a lot about n^2+1 containing a infinite number of primes. A similar function may well be: floor(n^(3/2))+/-k (and obviously 3/2 is a variable too) Does...
6 May 3, 2002
9:23 am

Jon Perry
jon_perryuk
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...what/which primes we find/prove, since there are so many of them. The only thing that matters is WHY and HOW the primes came upon us. Contemplate. So I'll...
1 May 3, 2002
1:53 am

Hans.Rosenthal@...
prime13117532
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Of course, when it rains, it pours: 10^75+5473 = P38 * P38 P38 = 11171602016259629892335959089815716691 P38 = 89512676744531089226201976823759569403 10^75+5659...
1 May 2, 2002
11:45 pm

Jim Fougeron
jim_fougeron
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I meant sum over the primes. The page in question uses a double-sided implies symbol, i.e. implies and is implied by. Going from left to right is no problem...
3 May 2, 2002
6:31 pm

Jon Perry
jon_perryuk
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Dear Phil, Mr. Martin has given an excellent proof for it. it is simply excellent. Sudarshan Iyengar *************************************************** ...
2 May 2, 2002
5:02 pm

Phil Carmody
thefatphil
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Hello all, I have a question on an equation. Given the equation: x^2 + k - y^2 = n where we know all of x, y, k, and n. Is there a way to factor n from all...
7 May 2, 2002
5:01 pm

Nuutti Kuosa
nkuosa
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Hello folks, my name is Andrew. I'm writing to introduce myself to the list and to get some feedback on an idea I have about prime number distribution. First...
2 May 2, 2002
4:27 pm

David Underbakke
dlunderbakke
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Excellent Martin, That was simply fantastic. Excellent proof, did you build the proof all on your own, or did you refer to some literature. Whatever it is, the...
1 May 2, 2002
3:56 pm

S.R.Sudarshan Iyengar
sudarshansr
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Hello! I I have a candidate p. Can everyone find a small factor of 2^7911907+3 or make PRP test ? Norman ...
6 May 2, 2002
2:45 pm

wfgarnett3
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Hello there, We all are familiar with the wilson's theorem which states that (1)(2)(3)...(p-1) = -1 (modp), where p is a prime number. But what can you say...
1 May 2, 2002
1:22 pm

S.R.Sudarshan Iyengar
sudarshansr
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... Consider a primitive root, all of its powers, and the product of all of its powers. This would prove the hypothesis for 2, 4, p^n and 2.p^n. I'd hope...
1 May 2, 2002
11:40 am

Phil Carmody
thefatphil
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Dear my groupmates I found my answer after that I requist you ,there for I thank you all .I found this in Euler law: fi(m) ... N for my case I let m=10 Omid...
1 May 2, 2002
9:32 am

omidmazaheri
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i am wondering if there's a formula for generating the nth prime however ineffecient it might be.i strongly doubt its existence but can anyone throw some light...
12 May 2, 2002
3:42 am

asen@...
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I am quite a few time zones west of you, yet you seem to be posting when I am posting. ... Robert...
1 May 2, 2002
12:42 am

rlberry2002
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I'm in a silly mood tonight - must be something to do with the quality of posts these last few days. So I will add to the hogwash. Excuse if you all know this...
2 May 2, 2002
12:35 am

rlberry2002
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Note, the result must be 14 or 194 ! In few seconds i found primes of form 2^n+3 with n=7,12,15,16,18,28,30,55,67,84,228,390,784,1110, 1704 best wishes Norman ...
2 May 1, 2002
10:27 pm

mikeoakes2@...
mikeoakes2
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