Search the web
Sign In
New User? Sign Up
rtrfans · Fans of 'The Road to Reality'
? Already a member? Sign in to Yahoo!

Yahoo! Groups Tips

Did you know...
Real people. Real stories. See how Yahoo! Groups impacts members worldwide.

Best of Y! Groups

   Check them out and nominate your group.
Having problems with message search? Fill out this form to ensure your group is one of the first to be migrated to the new message search system.

Messages

  Messages Help
Advanced
Some thoughts on a question of Knarfian about spinorial tangent vec   Message List  
Reply | Forward Message #110 of 150 |
Hi! I noticed this question about exercise 15.5 seemed to be
outstanding for a while. Let me repost the post from sci.math here (by
Knarfian) and give some thoughts, and then mention some references:

--begin quote

Hello,

I have been working my way through Roger Penrose's fantastic book "The
Road to Reality", and I am nearing the end of the Math section. There
is a statement and a question in section 15.4 that has myself and
another friend stymied. (Unfortunately, the solutions are not
available yet.)

On page 336, he is describing the Clifford bundle / Hopf fibration:
"In fact, in turns out that each point of our sphere S^3 can be
interpreted as a unit-length 'spinorial' tangent vector to S^2 at one
of its points". Then, he goes on to propose a problem [15.5] in a
footnote:

[15.5] Show this. Hint: Take the tangent vector to be u(d/dv) -
v(d/du) + x(d/dy) - y(d/dx).

His definition of the the sphere in S^3: abs(w)^2+abs(z)^2=1, which is
u^2+v^2+x^2+y^2=1, where w=u+iv and z=x+iy. S^2 is defined as the
Riemann Sphere, where each point is associated with a Complex 1-D
subspace of the C^2, Aw+Bz=0, where the ratio of A/B is unique for
every point on S^2.

I understand the relation between unit quaternions, rotation, and S^3,
thanks to David Lyons' paper "An Elementary Introduction to the Hopf
Fibration". What I am missing is this notion of a spinorial tangent
vector to S^2.

After this point, Penrose also talks about 2 to 1 mappings between
antipodal points on S^3 and "ordinary tangent vectors" to S^2. I'd
really like to understand both of these concepts, and I feel I'm pretty
close - but not quite there.

Thanks in advance for any insight, or references to relevant background

--end quote



Here's my take. The Hopf bundle (or Clifford bundle, as Penrose calls
it here) is certainly a fascinating topic and I'm unlikely to do it
full justice in a short post.

Recall that the fibre bundle in question is the "Clifford bundle"
S^1->S^3->CP^1 (here we identify the complex projective line with the
Riemann 2-sphere). This is the sphere bundle for the "tautological
line bundle" C^1->C^2->CP^1, where it's "tautological" because CP^1
*is* the set of complex lines through the origin in C^2, and so if you
take C^2 as the total space, and you project each complex line to the
corresponding point in CP^1, then that projection map is a line bundle
(since the fibre over a point is that complex line that *is* the point).

So, the special unitary group SU(2) acts on the vector space C^2, and
preserves the unit sphere S^3. SU(2) is identified with the group of
unit quaternions (e.g., Pauli spin matrices) and is also Sp(1). Since
SU(2) acts on C^2 complex-linearly, it also takes complex lines to
complex lines. Thus it acts on CP^1. You can write the action out on
ratios A/B.

The tangent bundle of C^2 is of course a trivial bundle, and thus we
can talk about the basis vectors d/du, d/dv, d/dx, and d/dy in each
tangent space over each point. They are the differential operators
that "point in the directions of the coordinate axes", i.e., at a
given point, they take functions to numbers (the basis vector d/dx in
the tangent space at p is an operator taking f to the number "df/dx
evaluated at p").

So what is this beast: u(d/dv) - v(d/du) + x(d/dy) - y(d/dx)?

As a simpler example, take S^1 embedded in a R^2 with coordinates (u,
v). Then a point on the circle is (u, v) with u^2 + v^2 = 1. What is
an example of a tangent vector to S^1 at that point? Note that the
tangent bundle of S^1 sits as a subset of the tangent bundle to R^2
because of the embedding so we can talk meaningfully of which tangent
vectors over a point (u, v) are tangent to S^1. If you draw a picture,
you'll see that you want, for a point (u, v) on the circle, one
tangent vector points in the direction (v, -u). Since it is in the
tangent space, when you write it in terms of the basis of the tangent
space, you v d/du - u d/dv.

So, the same kind of computation serves to demonstrate that at a point
p = (u, v, x, y) = (u + vi, x + yi) in S^3 (inside C^2), we can find
that the vector u(d/dv) - v(d/du) + x(d/dy) - y(d/dx), which sits in
the tangent space T_p (C^2), is in fact a tangent vector for S^3, i.e.
it sits in the subspace T_p(S^3).

I had written up to this point, but I have been rather tied up with
other things and have not had the chance to finish constructing a
really clear explanation of what's going on. So I will refer to two
sources:

1. Penrose and Rindler's "Spinors and Space-Time" has a discussion of
spinorial tangent vectors in chapter 1 with more details.

2. Gilkey's Invariance Theory, the Heat Equation, and the
Atiyah-Singer Index Theorem has a very explicit construction of the
spin structure on the tangent bundle of CP^1 on pages 167-170. This
book is available free at http://www.emis.de/monographs/gilkey/ .
The basic idea is that if you can take the transition functions for
the tangent bundle of CP^1, which are in SO(2) (which is a circle S^1)
and replace them all with elements from the 2-fold cover (which I
think some people write as U(1) -> SO(2)) given by squaring, i.e.,
e^{it} -> e^{2it}, then that is a "spin structure" on the tangent
bundle. It's kind of like being able to take the "square root" of the
bundle.

Hope this helps!

Best wishes,
Francis Fung






Thu Sep 14, 2006 6:04 am

fycfung
Online Now Online Now
Send Email Send Email

Forward
Message #110 of 150 |
Expand Messages Author Sort by Date

Hi! I noticed this question about exercise 15.5 seemed to be outstanding for a while. Let me repost the post from sci.math here (by Knarfian) and give some...
fycfung
Online Now Send Email
Sep 14, 2006
6:07 am
Advanced

Copyright © 2009 Yahoo! Inc. All rights reserved.
Privacy Policy - Terms of Service - Guidelines - Help