BTW, you will find a Excel sample in the file section of this group.
It has digital I/O control

--- In ultimaserial_group@yahoogroups.com, xchen992000 <no_reply@...>
wrote:
>
> See http://www.ultimaserial.com/standard.html#SetDIODir:
>
> It is plain binary format, bit 0 for DIO0, bit 1 for DIO1....
>
> In case you are not familiar with binary, here is the equation:
>
> diodir = 0
> If DIO7isInput Then diodir = diodir + 128
> If DIO6isInput Then diodir = diodir + 64
> If DIO5isInput Then diodir = diodir + 32
> If DIO4isInput Then diodir = diodir + 16
> If DIO3isInput Then diodir = diodir + 8
> If DIO2isInput Then diodir = diodir + 4
> If DIO1isInput Then diodir = diodir + 2
> If DIO0isInput Then diodir = diodir + 1
>
> UltimaSerial.SetDIODir diodir
>
> --- In ultimaserial_group@yahoogroups.com, "throrope" <throrope@>
> wrote:
> >
> > I see posts for setting the direction of all digital IO to in or
> > out, but I can't find a post that explains how to set one to out and
> > one to in. Also, can that digital output be individually set to
> > high?
> >
> > My application runs within Excel's visual basic editor.
> >
> > I have the following instructions:
> >
> > UltimaSerial.SetDIODir 0 turns all DIO to outputs
> > UltimaSerial.SetDIODir &HFF turns all DIO to inputs
> >
> > UltimaSerial.DigitalOutput &HFF turns all available outputs to high
> > UltimaSerial.DigitalOutput 0 turns all available outputs to low
> >
> > For DIO 2, would the &HFF be &H2F for each of the above? Do we set
> > all to outputs then set the inputs individually?
> >
> > ie:
> >
> > UltimaSerial.SetDIODir 0
> > UltimaSerial.SetDIODir &H0F
> > UltimaSerial.SetDIODir &H1F
> > UltimaSerial.SetDIODir &H3F
> > UltimaSerial.DigitalOutput &HFF
> >
> > I'm thinking the above sets all to out; then 0,1,3 to in; then since
> > only 2 is left as out, setting all to high indexes only 2 to high.
> > Will UltimaSerial.DigitalOutput &H2F set only 2 to high? Any
> > thoughts?
> >
> > Paul
> >
>